relative-path

问题 I am trying to display a website to a user, having downloaded it using php. This is the script I am using: <?php $url = 'http://stackoverflow.com/pagecalledjohn.php'; //Download page $site = file_get_contents($url); //Fix relative URLs $site = str_replace('src="','src="' . $url,$site); $site = str_replace('url(','url(' . $url,$site); //Display to user echo $site; ?> So far this script works a treat except for a few major problems with the str_replace function. The problem comes with relative

问题 I'm having trouble with paths in a ASP.NET MVC application that's running behind a proxy. Our IIS Application root path is for example http://server/MyApp/ meaning that all urls using the application root ("~/",Url.Action("MyAction","MyController")) are resolved to "/MyApp" Now we're running behind a proxy server that forwards all requests, but requires you to access the application through a URL like this: "/Secury/Proxy/RubbishUrl/MyApp" Because the proxy url is only available on the client

问题 Well, i can launch slimerjs by specifying the path of the slimer.bat file : C:\bin\slimerjs\slimerjs.bat and then execute my file. But if i modify casperjs file (in bin\ ) and modify the default exec for slimer : 'env_varname': 'SLIMERJS_EXECUTABLE', 'default_exec' : 'C:\bin\slimerjs\slimerjs.bat' when i execute the casper command : casperjs --engine=slimerjs test.js It doesn't work, the path to slimerjs.bat seems to be ignored. I tried this too : https://github.com/laurentj/slimerjs/blob

问题 I have 2 projects Project A , Project B , project A has a reference to project B , project A is an executable. Project A --> Project B inside project B there is a directory called "MyFolder" so the soulotion hierarchy is as follows : MySolution - A - B - MyFolder how do i get a Relative Path to MyFolder from with in project A(Executable). I found allot of answer which state the following : sring path = Assembly.GetAssembly(typeof(SomeClassInBProject)).Location; The path i got back from this

问题 How do i obtain the relative path from an absolute path, e.g. convert 'C:\absolute\path\file.ext' to 'path'? Thanks for your consideration edit: i'd like to recursivly scan a directory for a certain filetype and then create symlinks for these folders containing this filetype. the symlinks should be named like the directory containing the filetype. 回答1: This function works DosTips.com :MakeRelative It compares both pathes and removes the identical front. Then it adds "..\" for each non

问题 I tried to link with the html file name, but it works because they are on the same folder. [Title](./this-is-the-file.html) But it is possible that another article would appear on another folder because of the ARTICLE_URL pattern. Examples: [Title 1](/2014/02/article1.html) [Title 2](/2014/01/25/article2.html) Is it possible to link your own articles with a reference to the slug ? Any other better solution than the generated HTML file name ? 回答1: As noted in the documentation, you can link to

问题 I want to convert this physical path "C:\bla\bla\Content\Upload\image.jpg" to server path like "/Content/Upload/image.jpg" . How can i do that ? 回答1: you can use something like that : public static class Extensions { public static string RelativePath(this HttpServerUtility utility, string path, HttpRequest context) { return path.Replace(context.ServerVariables["APPL_PHYSICAL_PATH"], "/").Replace(@"\", "/"); } } and you call Server.RelativePath(path, Request); 回答2: You can do the following to

问题 I have a relative file path (for example "/res/example.xls") and I would like to get an InputStream Object of that file from that path. I checked the JavaDoc and did not find a constructor or method to get such an InputStream from a path/ Anyone has any idea? Please let me know! Thank you 回答1: Use FileInputStream: InputStream is = new FileInputStream("/res/example.xls"); But never read from raw file input stream as this is terribly slow. Wrap it with buffering decorator first: new

问题 How can I make my static-file root directories relative to my application root folder (instead of a hard-coded path)? In accordance with CP instructions (http://www.cherrypy.org/wiki/StaticContent) I have tried the following in my configuration file: tree.cpapp = cherrypy.Application(cpapp.Root()) tools.staticdir.root = cpapp.current_dir but when I run cherrpy.quickstart(rootclass, script_name='/', config=config_file) I get the following error builtins.ValueError: ("Config error in section:

问题 I'm wondering something, but I can't seem to be finding a good, clear answer, or even a solution to this problem: My PHP website has the following structure: root functions generators helpers scripts style index.php These are all folders and one php file. Functions contains a bunch op php files related to database connection and various other database operations such as inserting, deleting, updating,... Generators contains classes to automatically generate web pages to make them look all the