regex

VBA Excel Replace last 2 digits of number if occurs at beginning of string

好久不见. 提交于 2021-02-10 05:14:25
问题 I'm trying to replace the last two digits of number with " XX BLOCK " if it occurs at the start of the string and has more than 2 digits. I'm using the Microsoft VBScript Regular Expressions 5.5 reference. Dim regEx As New RegExp With regEx .Global = True 'Matches whole string, not just first occurrence .IgnoreCase = True 'Matches upper or lowercase .MultiLine = True 'Checks each line in case cell has multiple lines .pattern = "^(\d{2,})" 'Checks beginning of string for at least 2 digits End

VBA Excel Replace last 2 digits of number if occurs at beginning of string

守給你的承諾、 提交于 2021-02-10 05:14:13
问题 I'm trying to replace the last two digits of number with " XX BLOCK " if it occurs at the start of the string and has more than 2 digits. I'm using the Microsoft VBScript Regular Expressions 5.5 reference. Dim regEx As New RegExp With regEx .Global = True 'Matches whole string, not just first occurrence .IgnoreCase = True 'Matches upper or lowercase .MultiLine = True 'Checks each line in case cell has multiple lines .pattern = "^(\d{2,})" 'Checks beginning of string for at least 2 digits End

MySQL substring match using regular expression; substring contain 'man' not 'woman'

北慕城南 提交于 2021-02-10 04:19:05
问题 I have an issue while I fetch data from database using regular expression. While I search for 'man' in tags it returns tags contains 'woman' too; because its substring. SELECT '#hellowomanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 0 correct, it contains 'woman' SELECT '#helloowmanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 0 incorrect, it can contain anything other than 'woman' SELECT '#stylemanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 1 correct How can I update the regular

MySQL substring match using regular expression; substring contain 'man' not 'woman'

|▌冷眼眸甩不掉的悲伤 提交于 2021-02-10 04:14:21
问题 I have an issue while I fetch data from database using regular expression. While I search for 'man' in tags it returns tags contains 'woman' too; because its substring. SELECT '#hellowomanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 0 correct, it contains 'woman' SELECT '#helloowmanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 0 incorrect, it can contain anything other than 'woman' SELECT '#stylemanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 1 correct How can I update the regular

MySQL substring match using regular expression; substring contain 'man' not 'woman'

萝らか妹 提交于 2021-02-10 04:14:17
问题 I have an issue while I fetch data from database using regular expression. While I search for 'man' in tags it returns tags contains 'woman' too; because its substring. SELECT '#hellowomanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 0 correct, it contains 'woman' SELECT '#helloowmanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 0 incorrect, it can contain anything other than 'woman' SELECT '#stylemanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 1 correct How can I update the regular

MySQL substring match using regular expression; substring contain 'man' not 'woman'

会有一股神秘感。 提交于 2021-02-10 04:14:12
问题 I have an issue while I fetch data from database using regular expression. While I search for 'man' in tags it returns tags contains 'woman' too; because its substring. SELECT '#hellowomanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 0 correct, it contains 'woman' SELECT '#helloowmanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 0 incorrect, it can contain anything other than 'woman' SELECT '#stylemanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 1 correct How can I update the regular

split string by top-most level parentheses

依然范特西╮ 提交于 2021-02-10 03:42:00
问题 I have a string like the following: '(1) (2 (3))' I want to regex it to get the following array: ['1', '2 (3)'] another example: '(asd (dfg))(asd (bdfg asdf))(asd)' -> ['asd (dfg)', 'asd (bdfg asdf)', ('asd')] I've tried to search how to do such a regex, but I've only found ones that split by all the () , couldn't find anything to only filter the highest level of them. 回答1: I don't see a way to resolve it with regex, here's a programmatic approach (although there are probably a lot more

Python: split string by a multi-character delimiter unless inside quotes

梦想的初衷 提交于 2021-02-10 03:26:10
问题 In my case the delimiter string is ' ' (3 consecutive spaces, but the answer should work for any multi-character delimiter), and an edge case text to search in could be this: 'Coord="GLOB"AL Axis=X Type="Y ZR" Color="Gray Dark" Alt="Q Z"qz Loc=End' The solution should return the following strings: Coord="GLOB"AL Axis=X Type="Y ZR" Color="Gray Dark" Alt="Q Z"qz Loc=End I've looked for regex solutions, evaluating also the inverse problem ( match multi-character delimiter unless inside quotes ),

Python: split string by a multi-character delimiter unless inside quotes

喜欢而已 提交于 2021-02-10 03:25:43
问题 In my case the delimiter string is ' ' (3 consecutive spaces, but the answer should work for any multi-character delimiter), and an edge case text to search in could be this: 'Coord="GLOB"AL Axis=X Type="Y ZR" Color="Gray Dark" Alt="Q Z"qz Loc=End' The solution should return the following strings: Coord="GLOB"AL Axis=X Type="Y ZR" Color="Gray Dark" Alt="Q Z"qz Loc=End I've looked for regex solutions, evaluating also the inverse problem ( match multi-character delimiter unless inside quotes ),

Python: split string by a multi-character delimiter unless inside quotes

二次信任 提交于 2021-02-10 03:24:51
问题 In my case the delimiter string is ' ' (3 consecutive spaces, but the answer should work for any multi-character delimiter), and an edge case text to search in could be this: 'Coord="GLOB"AL Axis=X Type="Y ZR" Color="Gray Dark" Alt="Q Z"qz Loc=End' The solution should return the following strings: Coord="GLOB"AL Axis=X Type="Y ZR" Color="Gray Dark" Alt="Q Z"qz Loc=End I've looked for regex solutions, evaluating also the inverse problem ( match multi-character delimiter unless inside quotes ),