regex

How to get parentheses inside parentheses

廉价感情. 提交于 2021-02-10 06:36:38
问题 I'm trying to keep a parenthese within a string that's surrounded by a parenthese. The string in question is: test (blue,(hmmm) derp) The desired output into an array is: test and (blue,(hmmm) derp) . The current output is: (blue, , (hmm) and derp) . My current code is thatof this: var input = Regex .Split(line, @"(\([^()]*\))") .Where(s => !string.IsNullOrEmpty(s)) .ToList(); How can i extract the text inside the outside parentheses (keeping them) and keep the inside parenthese as one string

How do I create a new column in pandas from the difference of two string columns?

被刻印的时光 ゝ 提交于 2021-02-10 06:32:09
问题 How can I create a new column in pandas that is the result of the difference of two other columns consisting of strings? I have one column titled "Good_Address" which has entries like "123 Fake Street Apt 101" and another column titled "Bad_Address" which has entries like "123 Fake Street". I want the output in column "Address_Difference" to be " Apt101". I've tried doing: import pandas as pd data = pd.read_csv("AddressFile.csv") data['Address Difference'] = data['GOOD_ADR1'].replace(data[

How do I create a new column in pandas from the difference of two string columns?

一曲冷凌霜 提交于 2021-02-10 06:31:23
问题 How can I create a new column in pandas that is the result of the difference of two other columns consisting of strings? I have one column titled "Good_Address" which has entries like "123 Fake Street Apt 101" and another column titled "Bad_Address" which has entries like "123 Fake Street". I want the output in column "Address_Difference" to be " Apt101". I've tried doing: import pandas as pd data = pd.read_csv("AddressFile.csv") data['Address Difference'] = data['GOOD_ADR1'].replace(data[

Remove period[.] and comma[,] from string if these does not occur between numbers

↘锁芯ラ 提交于 2021-02-10 06:16:06
问题 I want to remove comma and period from a text only when these does not occur between numbers. So, following text should return "This shirt, is very nice. It costs DKK ,.1.500,00,." "This shirt is very nice It costs DKK 1.500,00" I tried with text = re.sub("(?<=[a-z])([[$],.]+)", " ", text) but it does not substitute anything in the text. 回答1: You could try this: >>> s = "This shirt, is very nice. It costs DKK ,.1.500,00,." >>> re.sub('(?<=\D)[.,]|[.,](?=\D)', '', s) 'This shirt is very nice

Elasticsearch Query on indexes whose name is matching a certain pattern

雨燕双飞 提交于 2021-02-10 06:14:14
问题 I have a couple of indexes in my Elasticsearch DB as follows Index_2019_01 Index_2019_02 Index_2019_03 Index_2019_04 . . Index_2019_12 Suppose I want to search only on the first 3 Indexes. I mean a regular expression like this: select count(*) from Index_2019_0[1-3] where LanguageId="English" What is the correct way to do that in Elasticsearch? 回答1: How can I query several indexes with certain names? This can be achieved via multi-index search, which is a built-in capability of Elasticsearch.

Elasticsearch Query on indexes whose name is matching a certain pattern

社会主义新天地 提交于 2021-02-10 06:14:08
问题 I have a couple of indexes in my Elasticsearch DB as follows Index_2019_01 Index_2019_02 Index_2019_03 Index_2019_04 . . Index_2019_12 Suppose I want to search only on the first 3 Indexes. I mean a regular expression like this: select count(*) from Index_2019_0[1-3] where LanguageId="English" What is the correct way to do that in Elasticsearch? 回答1: How can I query several indexes with certain names? This can be achieved via multi-index search, which is a built-in capability of Elasticsearch.

Java's Scanner. How to match whitespace?

人走茶凉 提交于 2021-02-10 05:54:04
问题 Suppose, I need to match parentheses containing whitespace. Here is a snippet: String input = "( ) ( ) ( )"; Pattern pattern = Pattern.compile("\\(\\s\\)"); Scanner scanner = new Scanner(input); scanner.useDelimiter("\\n"); Matcher matcher = pattern.matcher(input); System.out.println(scanner.hasNext(pattern)); // false System.out.println(matcher.find()); // true System.out.println(matcher.start(0) + " " + matcher.end(0)); // 0 3 Matcher does exactly what I need, but Scanner doesn't. The

How to search a string with parentheses using regular expression? [duplicate]

こ雲淡風輕ζ 提交于 2021-02-10 05:44:06
问题 This question already has answers here : matching parentheses in python regular expression (3 answers) Closed 1 year ago . I have a txt file containing strings as: A 123 B 456 Ab(123) ...... I wish to search Ab(123) in txt file. What I have tried : re.search(r'Ab(123)',string) 回答1: There are 12 characters with special meanings, you escape to its literal meaning with \ in front of it. re.search(r'Ab\(123\)',string) # or re.findall(r'Ab\(123\)',string) Look up https://regex101.com/r/1bb8oz/1

Replace CSS “#” (ID) with .(Class)

天涯浪子 提交于 2021-02-10 05:36:06
问题 I've a CSS string like #xyz{ color:#ee2ee2; } .abc{ background-color:#FFFFFF; border-color:1px solid #eee; } .def #xyz{ border-color:1px solid #ddd; } I need to replace the #xyz (or any other ID selector) with .xyz without changing the color: #ee2ee2 (or any other color selector). Basic java-script code would do I've tried some regex but it fails a few cases cssText.replace(/#([a-zA-Z])/gm, '.$1'); 回答1: This will replace # with . only when there is a { somewhere after in the same line.

Regex to match only numbers in currency

自作多情 提交于 2021-02-10 05:15:08
问题 I'm trying to get a VB regex to match only the numbers in a currency sequence without additional substitution lines if possible. It needs to look for a number with + on end $ at the start and return what's in the middle, minus any commas. Accordingly $10,000+ match returns 10000 $20,000+ match returns 20000 $30,000+ match returns 30000 $1,000,000+ match returns 1000000 $10,000 (anything without the trailing +) should *not* match I can easily get the match to the value but I can't figure out