regex

get string between two strings with javascript [duplicate]

由 六眼飞鱼酱① 提交于 2021-02-15 10:41:44
问题 This question already has answers here : Javascript Regex: How to put a variable inside a regular expression? [duplicate] (9 answers) Closed 6 years ago . How do I get a string between two strings using match with variables? The following code works well if I use match with strings Regular Expression to get a string between two strings in Javascript I also tried to apply the info at JavaScript - Use variable in string match : var test = "My cow always gives milk"; var testRE = test.match("cow

Javascript string replace method. Using matches in replacement string

由 六眼飞鱼酱① 提交于 2021-02-15 07:52:26
问题 I have the following javascript string /Library/Application%20Support/Adobe/Fireworks%20CS6/Commands The numeral in the "CS#" section may change, but I would like to convert the string to the following format keeping in mind that the numeral may change. /Library/Caches/Adobe/TypeSupport/CS6 I know I can do this in several ways, but for the purpose of education I am looking for the best method. I can search with a regular expression using the replace method, but is it possible to use matches

Email validation Javascript+RegEx, but to exclude certain domains

由 梦想的初衷 提交于 2021-02-15 07:52:21
问题 I have client side email validation script Javascript+RegEx, it works fine, but I want to exclude certain domains while validating, namely all Apple domains since they do not work (emails sent to these addresses are deleted without any notice): @apple.com, @me.com, @icloud.com, @mac.com. I found appropriate questions here, but still they are not the same I am asking for help. Please, help to implement this Can it be done via RegEx modification, or I have to use loop and search substrings (

Javascript string replace method. Using matches in replacement string

由 浪尽此生 提交于 2021-02-15 07:52:06
问题 I have the following javascript string /Library/Application%20Support/Adobe/Fireworks%20CS6/Commands The numeral in the "CS#" section may change, but I would like to convert the string to the following format keeping in mind that the numeral may change. /Library/Caches/Adobe/TypeSupport/CS6 I know I can do this in several ways, but for the purpose of education I am looking for the best method. I can search with a regular expression using the replace method, but is it possible to use matches

Linux实战教学笔记27：Nginx详细讲解

由 有些话、适合烂在心里 提交于 2021-02-15 07:34:28
前言：nginx的特点 本节主要对Nginx Web服务软件进行介绍，涉及Nginx的基础，特性，配置部署，优化，以及企业中的日常运维管理和应用。作为HTTP服务软件的后起之秀，Nginx与它的老大哥Apache相比有很多改进之处，比如，在性能上，Nginx占用的系统资源更少，能支持更多的并发连接（特别是静态小文件场景下），达到更高的访问效率；在功能上，Nginx不但是一个优秀的Web服务软件，还可以作为反向代理负载均衡及缓存服务使用；在安装配置上，Nginx更为方便，简单，灵活，可以说，Nginx是一个极具发展潜力的Web服务软件。 Nginx是什么？ nginx是一个开源的，支持高性能，高并发的www服务和代理服务软件。 nginx因具有高并发（特别是静态资源），占用系统资源少等特性，且功能丰富而逐渐流行起来。 nginx不但是一个优秀Web服务软件，还具有反向代理负载均衡功能和缓存服务功能，与lvs负载均衡及Haproxy等专业代理软件相比，Nginx部署起来更为简单，方便；在缓存功能方面，它又类似于Squid等专业的缓存服务软件。 Nginx的重要面试知识 Nginx的重要特性 支持高并发：能支持几万并发连接（特别是静态小文件业务环境） 资源消耗少：在3万并发连接下，开启10哥Nginx线程消耗的内存不到200MB 可以做HTTP反向代理及加速缓存，即负载均衡功能

Multiple Conditions in Validation Regex

由 感情迁移 提交于 2021-02-15 06:54:45
问题 I am more or less a regex novice. I tried to get the following conditions into a regex: No White Space at the beginning and at the end of a string Allow all digits Allow spaces, points, brackets, plus and minus Resulted in the following regex: ^\S[\d\/. ()\-+]*\S$ But now i try to apply two more conditions: Allow only one or two + Allow only one ( and one ) My problem is how to merge those two conditions into the existing regex string above cuz excluding + [+]{1,2} and () [(]{1} [)]{1} doesn

Multiple Conditions in Validation Regex

由 蓝咒 提交于 2021-02-15 06:54:12
问题 I am more or less a regex novice. I tried to get the following conditions into a regex: No White Space at the beginning and at the end of a string Allow all digits Allow spaces, points, brackets, plus and minus Resulted in the following regex: ^\S[\d\/. ()\-+]*\S$ But now i try to apply two more conditions: Allow only one or two + Allow only one ( and one ) My problem is how to merge those two conditions into the existing regex string above cuz excluding + [+]{1,2} and () [(]{1} [)]{1} doesn

Regular expression doesn't work in Go

由 徘徊边缘 提交于 2021-02-15 06:43:25
问题 forgive me for being a regex amateur but I'm really confused as to why this doesn't piece of code doesn't work in Go package main import ( "fmt" "regexp" ) func main() { var a string = "parameter=0xFF" var regex string = "^.+=\b0x[A-F][A-F]\b$" result,err := regexp.MatchString(regex, a) fmt.Println(result, err) } // output: false <nil> This seems to work OK in python import re p = re.compile(r"^.+=\b0x[A-F][A-F]\b$") m = p.match("parameter=0xFF") if m is not None: print m.group() // output:

Escape regex literal in Google Apps Script

由 ≡放荡痞女 提交于 2021-02-15 05:09:30
问题 I have no idea why this isn't working - I've put it through one of the better regex tools I've found on the web to verify it, and I'm using what seems to be the escape character '\' before the + sign to make it a literal '+', but Google Scripts keeps complaining saying "Invalid Quantifier '+'" (Line 2) Here's my script, with certain personal details (it's to clean out email as I use this account as a hard spam filter) omitted: function getEmailData() { var find_email_regex = new RegExp(

Maven-插件build-helper-maven-plugin

由 流过昼夜 提交于 2021-02-14 23:14:06
　　把原有项目添加到Maven管理时，总会出现很多莫名奇妙的问题，其中之一便是Maven默认的项目结构和自己的项目结构不一致，导致无法编译源代码，更不用说部署、运行项目了。 　　Java程序开发，一般使用Eclipse、MyEclipse等工具，其源码目录为src，这与Maven默认的src/main/java不同。因此，在没有额外配置的情况下，使用Maven命令无法完成代码的编译。 　　针对这种情况，codehaus提供了build-helper-maven-plugin插件来支持自定义的项目目录结构(相对于Maven默认目录结构来说)。 官网： http://www.mojohaus.org/build-helper-maven-plugin/ <!-- https://mvnrepository.com/artifact/org.codehaus.mojo/build-helper-maven-plugin --> <dependency> <groupId>org.codehaus.mojo</groupId> <artifactId>build-helper-maven-plugin</artifactId> <version>3.0.0</version> </dependency> Goals 概览 build-helper:add-source Add more
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