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Unbalanced parenthesis error with Regex

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问题 I am using the following regex to obtain all data from a website Javascript data source that is contained within the following character pattern [[]]); The code I am using is this: regex = r'\[\[.*?\]]);' match2 = re.findall(regex, response.body, re.S) print match2 This is throwing up an error message of: raise error, v # invalid expression sre_constants.error: unbalanced parenthesis I think I am fairly safe in assuming that this is being caused by the closing bracket within my regex. How can

How to remove tabs and newlines with a regex

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问题 In Python 3.x, the special re sequence '\s' matches Unicode whitespace characters including [ \t\n\r\f\v]. The following piece of code is intended to replace tabs and newlines with a space. import re text = """Hello my friends. How are you doing? I'm fine.""" output = re.sub('\s', ' ', text) print(output) However, the tab is still present in output. Why? 回答1: The problem is(likely) that your tab character is just a bunch of spaces. >>> re.sub(r"\s+", " ", text) "Hello my friends. How are you

How to remove tabs and newlines with a regex

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How to remove tabs and newlines with a regex

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Python regex match literal asterisk

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问题 Given the following string: s = 'abcdefg*' How can I match it or any other string only made of lowercase letters and optionally ending with an asterisk? I thought the following would work, but it does not: re.match(r"^[a-z]\*+$", s) It gives None and not a match object. 回答1: How can I match it or any other string only made of lowercase letters and optionally ending with an asterisk? The following will do it: re.match(r"^[a-z]+[*]?$", s) The ^ matches the start of the string. The [a-z]+

Python regex match literal asterisk

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Django入门到进阶-适合Python小白的系统课程

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download： Django入门到进阶-适合Python小白的系统课程掌握Django的基础知识，学习Web的相关扩展知识，学会开发c/s服务与apiserver服务；学习多方面非Django内置模块的配置开发方法；学习真正生产环境的服务器最终部署方案；全面阐述Web开发的各个环节的知识点，让你在使用或不使用Django进行开发的情况下都可以顺利上手基于Python的Web服务，尽量涉及绝大部分Python Web开发的生态，并且做讲解知识浅中带细，易于理解，对初学者友好适合人群入门Python刚刚接触Web开发的同学做Python运维的同学（基于Django开发相关Web业务）做Python测试的同学技术储备要求掌握Python基础了解前端基础 import random 2 if __name__ == " __main__ " : # 四位數字字母考證码的生成 3 checkcode= "" # 保管考證码的變量 4 for i in range(4 ): 5 index=random.randrange(0,4) # 生成一個0~3中的數 6 if index!=i and index +1 != i: 7 checkcode +=chr(random.randint(97,122)) # 生成a~z中的一個小寫字母 8 elif index +1==

why regexec() in posix c always return the first match,how can it return all match positions only run once?

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问题 Now when I want to return all match positions in str, such as: abcd123abcd123abcd Suppose I want to get all "abcd", I must use regexec(),get the first position:0, 3, then I will use: 123abcd123abcd as the new string to use regexec() again, and so on. I read the manual about regexec(), it says: int regexec(const regex_t *preg, const char *string, size_t nmatch, regmatch_t pmatch[], int eflags); nmatch and pmatch are used to provide information regarding the location of any matches. but why

why regexec() in posix c always return the first match,how can it return all match positions only run once?

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get string between two strings with javascript [duplicate]

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问题 This question already has answers here : Javascript Regex: How to put a variable inside a regular expression? [duplicate] (9 answers) Closed 6 years ago . How do I get a string between two strings using match with variables? The following code works well if I use match with strings Regular Expression to get a string between two strings in Javascript I also tried to apply the info at JavaScript - Use variable in string match : var test = "My cow always gives milk"; var testRE = test.match("cow