regex

Swift 5: How to calculate correct Date from provided string?

南笙酒味 提交于 2021-01-07 02:50:50
问题 I am not good at Swift so I would like to know how to calculate the current time is between two times. I got the following response from the backend. {"workHours":"M-F 9:00 - 18:00"} How to get start (9:00) time, end (18:00) time from "M-F 11:00 - 20:00" response using regular expression and DateFormatter?(I am not sure it is the correct way to get Date object from this kind of string, if not please recommend the best way and experience) 回答1: You can use the following regex: "^\\w-\\w\\s{1}(\

Split string in 3 blocks (Text - Number - Other characters) if possible

旧巷老猫 提交于 2021-01-07 02:43:10
问题 I need to divide a string into 3 blocks at most The first block is only for letters The second only numbers The third the remainder Examples : Karbwqeaf 11D Jablunkovska 21/2 Tastoor Nstraat 43 Schzelkjedow Heajsd 3/5/7 m 344 Lasdasdt seavees 3., 729. tasdasd F 2. ul. Pasydufasdfa 73k/120 I need to split like this: Block1: Karbwqeaf Block2: 11 Block3: D Block1: Jablunkovska Block2: 21 Block3: /2 Block1: Tastoor Nstraat Block2: 43 Block3: Block1: Schzelkjedow Block2: Block3: Block1: Heajsd

Windows batch/powershell file to regex find and replace only in files having specific text [closed]

那年仲夏 提交于 2021-01-07 02:31:45
问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed yesterday . Improve this question How could I make a Windows batch file to find and rename with regex in files, that have specific text in them? This is the needed scenario: If file path is C:\Folder\ and file name is something_*.xml (wildcards allowed) and the file has specific text

Replace with multi line regex [duplicate]

£可爱£侵袭症+ 提交于 2021-01-07 01:59:09
问题 This question already has answers here : Replace multiple lines with regex (2 answers) Closed 7 days ago . Given the following text, I want to remove everything in data_augmentation_options{random_horizontal_flip {..}} ( ... means other text in the following) i.e., input is : ... batch_size: 4 num_steps: 30 data_augmentation_options { random_horizontal_flip { keypoint_flip_permutation: 0 keypoint_flip_permutation: 2 keypoint_flip_permutation: 1 keypoint_flip_permutation: 4 keypoint_flip

How to capture the field values in the csv file using bufferedreader

对着背影说爱祢 提交于 2021-01-07 01:25:34
问题 The csv file looks like this I'm trying to get the field values like name, it is the value after $$NAME$$ (there is a space after the identifier). How do I store the value for each field by using BufferedReader in Java? The fields could be in any line number and not in a fixed place or format, and also throw out an error if there is any special characters or null value is encountered. int n = 100; // Max lines String line; try (BufferedReader br = new BufferedReader(new FileReader(str))) {

regular expression put space between number and character

走远了吗. 提交于 2021-01-06 04:24:54
问题 I wonder how can I write regular expression to put a space between number and character only if this character not % and not space. var str = "... 15a...".replace(/(\d+)(\D+)/g,'$1 $2') The above doesn't work as I expect, for example I need the following constraints "... 15a ..." => "... 15 a ..." "... 15 a ..." => "... 15 a ..." "... 15% ..." => "... 15% ..." I would appreciate any help. 回答1: var str = "... 15a...".replace(/(\d+)([a-z]+)/g,'$1 $2') 回答2: "... 15a...".replace(/(\d+)([^%\d\s]+?

Groovy regex/pattern matching

别来无恙 提交于 2021-01-05 09:26:13
问题 How do we do regex matching in groovy, what will be the regex in groovy for below example? Example : f2376 Regex: (anyLetter)(followed by 4 digits) 回答1: Pretty simple with groovy "f1234" ==~ /[a-z]\d{4}/ Note that the regex [a-z]\d{4} means any of the characters a-z once, followed by exactly 4 digits, and can be probably be used with any language that handles regex, not just groovy. In my console I tested for just lower case letters, but to handle upper case too just do "f1234" ==~ /[a-zA-Z]

Groovy regex/pattern matching

感情迁移 提交于 2021-01-05 09:24:05
问题 How do we do regex matching in groovy, what will be the regex in groovy for below example? Example : f2376 Regex: (anyLetter)(followed by 4 digits) 回答1: Pretty simple with groovy "f1234" ==~ /[a-z]\d{4}/ Note that the regex [a-z]\d{4} means any of the characters a-z once, followed by exactly 4 digits, and can be probably be used with any language that handles regex, not just groovy. In my console I tested for just lower case letters, but to handle upper case too just do "f1234" ==~ /[a-zA-Z]

Get Full Range Text to String

丶灬走出姿态 提交于 2021-01-05 09:13:16
问题 I'm writing a script that looks through my outgoing emails and searches for frequent stylistic errors I make. It locates them using regex and then highlights them yellow. Code: Public Sub highlightBadForm() Dim oWordDoc As Object Dim oMatches As Object Dim oRange As Range Dim strText As String Dim lngFindFrom As Long Dim varMtch As Variant Set oWordDoc = Application.ActiveInspector.WordEditor strText = LCase(oWordDoc.Range.Text) lngFindFrom = InStr(strText, "from: ") If lngFindFrom > 0 Then

Regex to remove the whole outer parent pattern but still preserving the data inside child pattern. Nested Patterns

核能气质少年 提交于 2021-01-05 09:12:38
问题 I want to remove a specific pattern which starts with either \( or with \\( and ends with /) or //) . There may or may not be a space before and after the pattern i.e the pattern can be in the starting or on the end too. But the real problem is that There is very useful data inside a child pattern which starts with \text { preserve this data } too and I want to preserve that thing. For example: this is my text \( delete it x+y I do not care \text { Preserve this } whatever is here I do not