regular expression put space between number and character

问题

I wonder how can I write regular expression to put a space between number and character only if this character not % and not space.

var str = "... 15a...".replace(/(\d+)(\D+)/g,'$1 $2')

The above doesn't work as I expect, for example I need the following constraints

"... 15a ..." => "... 15 a ..."
"... 15 a ..." => "... 15 a ..."
"... 15% ..." => "... 15% ..."

I would appreciate any help.

回答1:

var str = "... 15a...".replace(/(\d+)([a-z]+)/g,'$1 $2')

回答2:

"... 15a...".replace(/(\d+)([^%\d\s]+?)/g,'$1 $2')   

"... 15 a..."

"... 15 a...".replace(/(\d+)([^%\d\s]+?)/g,'$1 $2')

"... 15 a..."

"... 15%...".replace(/(\d+)([^%\d\s]+?)/g,'$1 $2')

"... 15%..."

回答3:

Well, you are trying to find a digit followed by a nondigit, non-percent character. So this:

replace(/(\d)([^\d\s%])/g,'$1 $2')

Should do the trick.

来源：https://stackoverflow.com/questions/23752362/regular-expression-put-space-between-number-and-character