regex

问题 I want to find all patterns in a string that match the regex: no="(\d+)" then replace the digits in the group with something else. In the method below I can find and replace the entire match, but that is not what I want. Is there a way to replace just a portion in that match? private String replaceStringFromPatternSearch(String stringToSearch, String patternString, String replacementString) { String replacedString = null; Pattern stringPattern = Pattern.compile(patternString); Matcher

问题 I set up a complex regex to extract data from a page of text. For some reason the order of the alternation is not what I expect. A simple example would be: ((13th|(Executive |Residential)|((\w+) ){1,3})Floor) Put simply I am trying to either get a floor number, a known named floor and, as a back-up, I capture 1-3 unknown words followed by floor just in case to review later (I in fact use a groupname to identify this but didn't want to confuse the issue) The issue is if the string is on the

问题 I set up a complex regex to extract data from a page of text. For some reason the order of the alternation is not what I expect. A simple example would be: ((13th|(Executive |Residential)|((\w+) ){1,3})Floor) Put simply I am trying to either get a floor number, a known named floor and, as a back-up, I capture 1-3 unknown words followed by floor just in case to review later (I in fact use a groupname to identify this but didn't want to confuse the issue) The issue is if the string is on the

问题 I set up a complex regex to extract data from a page of text. For some reason the order of the alternation is not what I expect. A simple example would be: ((13th|(Executive |Residential)|((\w+) ){1,3})Floor) Put simply I am trying to either get a floor number, a known named floor and, as a back-up, I capture 1-3 unknown words followed by floor just in case to review later (I in fact use a groupname to identify this but didn't want to confuse the issue) The issue is if the string is on the

问题 I'm trying to return only those rows which colA and colB do not contain a number or a whitespace Here is my code so far. SELECT * FROM table_name WHERE colA REGEXP '[^0-9^\W]' AND colB REGEXP '[^0-9^\W]' given the dataset colA colB ---------- ---------- test | testB 33 | text <- this is not returned blah | 0123A <- this is returned I am assuming my issue is with my regexp... any help please? 回答1: Well your expression does not work because: 33 is both numbers and you're looking for any non

问题 I've been trying to convert the following from Python to node.js. It's a simply program that uses regex to check if an IP address is Public or Private: import re def is_private_ip(ip): """ Returns `True` if the `ip` parameter is a private network address. """ c = re.compile('(^127\.0\.0\.1)|(^10\.)|(^172\.1[6-9]\.)|(^172\.2[0-9]\.)|(^172\.3[0-1]\.)|(^192\.168\.)') if c.match(ip): return True return False print is_private_ip('192.168.0.1') # True print is_private_ip('8.8.8.8') # False print is

问题 I've been trying to convert the following from Python to node.js. It's a simply program that uses regex to check if an IP address is Public or Private: import re def is_private_ip(ip): """ Returns `True` if the `ip` parameter is a private network address. """ c = re.compile('(^127\.0\.0\.1)|(^10\.)|(^172\.1[6-9]\.)|(^172\.2[0-9]\.)|(^172\.3[0-1]\.)|(^192\.168\.)') if c.match(ip): return True return False print is_private_ip('192.168.0.1') # True print is_private_ip('8.8.8.8') # False print is

问题 I have a text that i need to parse in python. It is a string where i would like to split it to a list of lines, however, if the newlines (\n) is inside quotes then we should ignore it. for example: abcd efgh ijk\n1234 567"qqqq\n---" 890\n should be parsed into a list of the following lines: abcd efgh ijk 1234 567"qqqq\n---" 890 I've tried to it with split('\n') , but i don't know how to ignore the quotes. Any idea? Thanks! 回答1: Here's a much easier solution. Match groups of (?:"[^"]*"|.)+ .

问题 I have a text that i need to parse in python. It is a string where i would like to split it to a list of lines, however, if the newlines (\n) is inside quotes then we should ignore it. for example: abcd efgh ijk\n1234 567"qqqq\n---" 890\n should be parsed into a list of the following lines: abcd efgh ijk 1234 567"qqqq\n---" 890 I've tried to it with split('\n') , but i don't know how to ignore the quotes. Any idea? Thanks! 回答1: Here's a much easier solution. Match groups of (?:"[^"]*"|.)+ .

问题 Using GNU sed (with the -r flag for clarity), the following two substitutions on the input string ab give the same result: s/(.)(.)|(.)(.)$/\2\1\3\4/ and s/(.)(.)$|(.)(.)/\1\2\4\3/ both give ba . It would appear that the alternative (.)(.) (the one without $ ) succeeds in both substitutions, regardless of whether its position as the first or second alternative. Why is this the case? What is the tie-breaker for such alternatives? The POSIX specification of regular expressions specifies 1 the