regex-lookarounds

I have the below patterns to be excluded. make it cheaper make it cheapere makeitcheaper.com.au makeitcheaper making it cheaper www.make it cheaper ww.make it cheaper.com I've created a regex to match any of these. However, I want to get everything else other than these. I am not sure how to inverse this regex I've created. mak(e|ing) ?it ?cheaper Above pattern matches all the strings listed. Now I want it to match everything else. How do I do it? From the search, it seems I need something like negative lookahead / look back. But, I don't really get it. Can some one point me in the right

replace characters in notepad++ BUT exclude characters inside single quotation marks Sorry to all users (especially to Avinash Raj) who answered already 1st similiar question - I did simply forget the 2nd kind of string. (And (that is the sad thing) - I'm not able to adjust the solution from 1st similiar question to the 2nd kind of string...) I have TWO different strings in this kind: SELECT column_name FROM table_name WHERE column_name IN ('A' , 'st9u' ,'Meyer', ....); WHERE a.object_type IN (' 'TABLE'', ''MATEerialIZED VIE3W' ') I want replace all characters in notepad++ from upper to lower,

In the following let's say zip codes I am trying to exclude the 33333- from the result. I do: String zip = "11111 22222 33333- 44444-4444"; String regex = "\\d{5}(?(?=-)-\\d{4})"; Pattern pattern = Pattern.compile(regex); Matcher matcher = pattern.matcher(zip); while (matcher.find()) { System.out.println(" Found: " + matcher.group()); } Expect to get: Found: 11111 Found: 22222 Found: 44444-4444 I am trying to enforce format of: 5 digits optionally followed by a - and 4 digits. 5 digits with just a - (hyphen) is not wanted I get exception: Exception in thread "main" java.util.regex

I need to find all \r\n that do not precede the letter M; Seems I can't do this: \r\n[^M] I can only do \r\n with extended search selected or [^M] with regular expressions selected; but not together. You should instead use this regex: \R(?!M) Explanation: \R Any Unicode newline sequence. (?!M) Negative Lookahead : Assert "M" cannot be matched. \r\n is valid with Regular expression checked in the Find tab too - i.e. not just with Extended checked: why not just use \r\n[^M] with Regular expression checked? Given the following test text... whatever M whatever G foo ..., \r\n[^M] yields the

I'm trying to craft two regular expressions that will match URIs. These URIs are of the format: /foo/someVariableData and /foo/someVariableData/bar/someOtherVariableData I need two regexes. Each needs to match one but not the other. The regexes I originally came up with are: /foo/.+ and /foo/.+/bar/.+ respectively. I think the second regex is fine. It will only match the second string. The first regex, however, matches both. So, I started playing around (for the first time) with negative lookahead. I designed the regex /foo/.+(?!bar) and set up the following code to test it public static void

Matching a repeated character in regex is simple with a backreference: (.)\1 Test it here. However, I would like to match the character after the pair of characters, so I thought I could simply put this in a lookbehind: (?<=(.)\1). Unfortunately, this doesn't match anything. Why is that? In other flavours I wouldn't be surprised because there are strong restrictions on lookbehinds, but .NET usually supports arbitrarily complicated patterns inside lookbehinds. Martin Ender The short version: Lookbehinds are matched from right to left. That means when the regex engine encounters the \1 it hasn't