reference

问题 I have this interesting situation. I have a bunch of structs that hold a string. struct foo { string mStringName; } vector<foo> mFoos; I also have a queue of string references queue<string&> mStringQueue; And finally, I have a function that accepts a const string& void Bar(const string&); Heres the situation. //...in some loop currentFoo = mFoos[index]; // Queue up the string name. mStringQueue.push(currentFoo.mStringName); //...Later on, go through our queue and pass each one to the function

问题 I'm trying to start a C++ game engine project. I don't have much knowledge of dll's and lib's but figured the engine itself would be a dll and I would have separate dll projects such as renderer, input, etc that would be used by the engine and the engine dll would be used by the game. I seem to have the engine project referenced fine in the demo.exe project(by adding a reference and adding the path to additional include directories) but when trying to add a reference to a renderer dll project

问题 I have the following sample code template<class T1, class T2> class Operation { public: constexpr Operation(const T1& lhs, const T2& rhs) noexcept : m_lhs(lhs), m_rhs(rhs) { } private: const T1& m_lhs; const T2& m_rhs; }; int main() { constexpr int a = 3; constexpr int b = 4; constexpr Operation op(a, b); return 0; } Compiling this with cygwin (gcc 8.2) I get error: 'Operation<int, int>{a, b}' is not a constant expression: constexpr Operation op(a, b); With MSVC 2019 it compiles fine, but

问题 It's pretty common knowledge that the semantically accurate way to declare pointers is int *x; instead of int* x; This is because C sees *x as an int, not x as an int pointer. This can be easily demonstrated by int* a, b; where a is an int pointer, while b is an int. There are at least 5 duplicate questions on stackoverflow.com that discuss this issue for pointers. But what about references? 回答1: Bjarne Stroustrup says: A typical C programmer writes int *p ; and explains it *p is what is the

问题 It's pretty common knowledge that the semantically accurate way to declare pointers is int *x; instead of int* x; This is because C sees *x as an int, not x as an int pointer. This can be easily demonstrated by int* a, b; where a is an int pointer, while b is an int. There are at least 5 duplicate questions on stackoverflow.com that discuss this issue for pointers. But what about references? 回答1: Bjarne Stroustrup says: A typical C programmer writes int *p ; and explains it *p is what is the

问题 Is there some kind of subtle difference between those: void a1(float &b) { b=1; }; a1(b); and void a1(float *b) { (*b)=1; }; a1(&b); ? They both do the same (or so it seems from main() ), but the first one is obviously shorter, however most of the code I see uses second notation. Is there a difference? Maybe in case it's some object instead of float? 回答1: Both do the same, but one uses references and one uses pointers. See my answer here for a comprehensive list of all the differences. 回答2:

问题 Situation : Our company has an Open Issues list we use for individual parts during trialing/launching a program. The program has its own Excel document, and each part has its own tab in that document for a running list of that specific part. It has recently been proposed that we track how long issues are open using MS Project. I can take the information from our Excel tab and manually copy it into Project to show what we want, and I can have Project automatically update linked sources if it

问题 Situation : Our company has an Open Issues list we use for individual parts during trialing/launching a program. The program has its own Excel document, and each part has its own tab in that document for a running list of that specific part. It has recently been proposed that we track how long issues are open using MS Project. I can take the information from our Excel tab and manually copy it into Project to show what we want, and I can have Project automatically update linked sources if it

问题 I read different things on the Internet and got confused, because every website says different things. I read about * referencing operator and & dereferencing operator; or that referencing means making a pointer point to a variable and dereferencing is accessing the value of the variable that the pointer points to. So I got confused. Can I get a simple but thorough explanation about "referencing and dereferencing"? 回答1: Referencing means taking the address of an existing variable (using &) to

问题 I just want to pass device function as argument of a host function, of cause, the host function then can launch some kernels with this device side function. I tried the usual C++ way (pass by pointer/reference) and the CUDA debugger told me the kernel cannot launch. Update: What I want to do is: __host__ void hostfunction(int a, int (*DeviceFunction)(int)) { /...do something.../ somekernel<<<blocks, threads>>>(int * in, DeviceFunction); } And launch the host with: hostfunction(x,