readfile

PHP Readfile() not working for me and I don't know why

只谈情不闲聊 提交于 2019-11-28 12:08:15
问题 I am trying to get this code to work but for some reason, all the echo's are able to output correct content, but the headers don't seem to want to force the download of my document. What follows is the file I am trying to build for file downloads. It is set to input code like this: downloader.php?f=13&t=doc to download a file that is named 201-xxx.doc or 201-xxx.pdf from one of two folders depending on the users privileges. All the logic works up to the header info at the bottom. If I comment

How to get file read line by line

徘徊边缘 提交于 2019-11-28 09:04:10
I have a file containing text in separate line. I want to display line first, and then if I press a button, the second line should be displayed in the TextView and the first line should disappear. Then, if I press it again, the third line should be displayed and so on. Should I have to use TextSwitcher or anything else? How can I do that? You tagged it as "android-assets" so I'm going to assume your file is in the assets folder. Here: InputStream in; BufferedReader reader; String line; TextView text; public void onCreate(Bundle savedInstanceState){ super.onCreate(savedInstanceState);

string replace in a large file with php

帅比萌擦擦* 提交于 2019-11-28 08:42:19
I am trying to do a string replace for entire file in PHP. My file is over 100MB so I have to go line by line and can not use file_get_contents() . Is there a good solution to this? Dominic Barnes If you aren't required to use PHP, I would highly recommend performing stuff like this from the command line. It's byfar the best tool for the job, and much easier to use. In any case, the sed (Stream Editor) command is what you are looking for: sed s/search/replace oldfilename > newfilename If you need case-insensitivity: sed -i s/search/replace oldfilename > newfilename If you need this to perform

Why does readfile() exhaust PHP memory?

纵饮孤独 提交于 2019-11-28 07:26:17
I've seen many questions about how to efficiently use PHP to download files rather than allowing direct HTTP requests (to keep files secure, to track downloads, etc.). The answer is almost always PHP readfile() . Downloading large files reliably in PHP How to force download of big files without using too much memory? Best way to transparently log downloads? BUT, although it works great during testing with huge files, when it's on a live site with hundreds of users, downloads start to hang and PHP memory limits are exhausted. So what is it about how readfile() works that causes memory to blow

动态代理

ぐ巨炮叔叔 提交于 2019-11-28 06:41:48
1 分为jdk自带代理 2 实现接口 InvocationHandler ,用反射调用方法 3 获取代理类:Proxy.newProxyInstance(cls.getClassLoader(),cls.getInterfaces(), new TestProxy(obj)); 4 5 实例: 6 public interface ReadFile { 7 public void read(); 8 } 9 10 public class Boss implements ReadFile { 11 @Override 12 public void read() { 13 System.out.println("I'm reading files."); 14 } 15 } 16 17 public class Secretary implements InvocationHandler { 18 private Object object; 19 public Secretary(Object object) { 20 this.object = object; 21 } 22 @Override 23 public Object invoke(Object proxy, Method method, Object[] args) throws Throwable { 24

前端随心记---------nodejs基础学习-Express 框架

。_饼干妹妹 提交于 2019-11-28 04:19:26
Express 框架简介 express 框架是什么? 为什么要使用 express 框架呢? 如何使用 express 框架呢? express 框架是什么?   Express基于nodejs开发的一个框架(基于http模块封装,功能更强)。   Express 是一个保持最小规模的灵活的 Node.js Web 应用程序开发框架,为 Web 和移动应用程序提供一组强大的功能。 为什么要使用 express 框架呢? 加快项目开发,便于团队协作。 Express 提供精简的基本 Web 应用程序功能,而不会隐藏您了解和青睐的 Node.js 功能。 如何使用 express 框架呢? Express 入门使用 express 入门使用 express 路由 什么是路由? 为什么要使用路由呢? 如何使用路由呢? 什么是路由参数呢? Express之路由   路由就是当浏览器输入一个 URL 地址后,将该请求交给后台的哪一个应用程序进行处理的过程称为路由。而这样的操作需要事先在后台定义好规则,定义出来的规则我们叫做 路由规则。   如何使用路由呢?  路由基本语法 1. 普通语法 app.HTTP请求类型(请求路径,回调函数) 发送 GET请求:app.get(请求路径,回调函数) 发送 POST请求:app.post(请求路径,回调函数) 发送 任意请求:app.all(请求路径

PHP readfile() of external URL

给你一囗甜甜゛ 提交于 2019-11-28 03:15:05
问题 Can I use external URLs in readfile()? header('Content-type: application/pdf'); header('Content-Transfer-Encoding: binary'); header('Content-Disposition: inline; filename="'.$file.'" '); //header('Content-Length: ' . filesize("http:...z/pub/".$file.'.pdf')); @readfile("http://...z/pub/".$file.'.pdf'); 回答1: The PHP manual on readfile states: A URL can be used as a filename with this function if the fopen wrappers have been enabled. See fopen() for more details on how to specify the filename.

read file from external storage

限于喜欢 提交于 2019-11-27 21:49:01
问题 I simply cannot find how to get one specified file from the external storage. I know that with getExternalStoragePublicDirectory(), you get the external storage directory but I can't get further. I need some kind of method where you have to give the name of the file and it returns the file. Thanx 回答1: Better than using File.separator is this, which is standard Java: final File file = new File(Environment.getExternalStorageDirectory() .getAbsolutePath(), filename); 回答2: You can just do this:

Using Promises with fs.readFile in a loop

不问归期 提交于 2019-11-27 19:03:45
I'm trying to understand why the below promise setups don't work. (Note: I already solved this issue with async.map. But I would like to learn why my attempts below didn't work.) The correct behavior should be: bFunc should run as many time as necessary to fs read all the image files (bFunc below runs twice) and then cFunc console prints "End". Thanks! Attempt 1: It runs and stops at cFunc(). var fs = require('fs'); bFunc(0) .then(function(){ cFunc() }) //cFunc() doesn't run function bFunc(i){ return new Promise(function(resolve,reject){ var imgPath = __dirname + "/image1" + i + ".png"; fs

Problem when loading php file into variable (Load result of php code instead of the code as a string)

半城伤御伤魂 提交于 2019-11-27 16:26:39
I have a site architechure where I assign content to variables and then print them in a master page. My problem is that php code in the sub pages is imported into the variables as strings. Is there anyway to make sure that the code is actually executed and the results is imported in the variables instead? In the example below the php code in signup_header.php is imorted as a string to $page_header. The result is that "getVerifiedEmail(); ?>" is displayed in the form element instead of the e-mail address. master.php <!DOCTYPE HTML> <html> <head> <?php echo $page_header; ?> </head> <body id=