readfile

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I'm trying to load a UTF8 json file from disk using node.js (0.10.29) on Windows 8.1. The following is the code that runs: var http = require ( 'http' ); var utils = require ( 'util' ); var path = require ( 'path' ); var fs = require ( 'fs' ); var myconfig ; fs . readFile ( './myconfig.json' , 'utf8' , function ( err , data ) { if ( err ) { console . log ( "ERROR: Configuration load - " + err ); throw err ; } else { try { myconfig = JSON . parse ( data ); console . log ( "Configuration loaded successfully" ); } catch ( ex ) {

fstream提供了三个类，用来实现c++对文件的操作。（文件的创建、读、写）。 fstream - 打开文件供读写 文件打开模式： ios::in 读 ios::out д ios::app 从文件末尾开始写 ios::binary 二进制模式 ios::nocreate 打开一个文件时，如果文件不存在，不创建文件。 ios::noreplace 打开一个文件时，如果文件不存在，创建该文件 ios::trunc 打开一个文件，然后清空内容 ios::ate 打开一个文件时，将位置移动到文件尾 文件指针位置在c++中的用法： ios::beg 文件头 ios::end 文件尾 ios::cur 当前位置 例子： file.seekg(0,ios::beg); //让文件指针定位到文件开头 file.seekg(0,ios::end); //让文件指针定位到文件末尾 file.seekg(10,ios::cur); //让文件指针从当前位置向文件末方向移动10个字节 file.seekg(-10,ios::cur); //让文件指针从当前位置向文件开始方向移动10个字节 file.seekg(10,ios::beg); //让文件指针定位到离文件开头10个字节的位置 常用的错误判断方法: good() 如果文件打开成功 bad() 打开文件时发生错误 eof() 到达文件尾

异步函数是异步编程语法的终极解决方案，它可以让我们将异步代码写成同步形式，让代码不再有回调函数嵌套，使代码变得清晰明了。 基础语法： const fn = async () => {} async function fn () {} // async // 1.在普通函数定义的前面加上asynv 关键字，普通函数就变成了异步函数 // 2.异步函数默认的返回值是promise 对象 // 3.在异步函数内部使用throw关键字进行错误的抛出 // 4.在异步函数内部使用 return 关键词 进行结果的返回，结果会被包裹在promise 对象中， return 关键词 代替了 promise 方法中的 resolve 。 // await 关键字 // 1. 它只能出现在异步函数中 // 2. promise await 后面只能写promise 对象，写其他类型的API是不行的。 // 3. await 关键字是暂停异步函数向下执行，直到promise 返回结果。 示例： 1 async function f1 () { 2 return 'f1' 3 } 4 5 async function f2 () { 6 return 'f2' 7 } 8 9 async function f3 () { 10 return 'f3' 11 } 12 13 async function

定义头部，将输出方式改为文件流； 使用readfile读取文件。 <a href="download.php?filename=test.png">下载图片</a> // 1.获取文件名 $filename = $_GET['filename']; // 2.文件存放路径名 $filepath = './file/'.$filename; // 3.判断是否存在 if(!file_exists($filepath)){ exit('文件不存在'); }else{ // 4.设置头部(以文件流的方式输出) header("Content-type: applicaton/octet-stream"); header("Content-Disposition: attachment; filename=".basename($filepath)); // 5.读取文件 readfile($filepath); } 文章来源: php进阶—— 04 文件下载

I need to load a file from an umounted TrueCrypt disk into memory. Is there any way to do this programatically? Does TrueCrypt offer an API? The way I believe is best for attempting this would be to mount the volume (prompting the user for a password, of course), open the file, and then unmount the volume. Is there a way to do this all automatically? I am on Windows Vista. I have C#, Python, and Perl readily available. Preet Sangha Can you not use the true crypt command line from say System.Diagnostics.Process? using System; using System.Diagnostics; namespace Test { class TrueCrypeStart {

On a previous project I was required to read file contents into an array. Now I have to do the same thing only I have to read the contents into an ArrayList. A few problems I am encountering is How do I step through the ArrayList adding each item separately? If the file contains more than 10 inputs, it has to exit. I have tried the following, which does not work properly. Code: public static String readFile(String fileName) throws IOException { String result = ""; String line = ""; FileInputStream inputStream = new FileInputStream(fileName); Scanner scanner = new Scanner(inputStream);

I'm really problems when open files stored in my project. I need open some files (pdf, html,...) and ever has the same problem: Value does not fall within the expected range . I have tried several ways: a) private async Task<string> ReadFileContentsAsync(string fileName) { StorageFolder foldera = ApplicationData.Current.LocalFolder; try { Stream filea = await foldera.OpenStreamForReadAsync("/Assets/Data/htm/" + fileName + ".htm"); ... } catch (Exception e) { Debug.WriteLine("ERROR ReadFileContentsAsync " + e.Message); return null; } } b) private async Task<string> ReadFileContentsAsync(string

I have a huge data file with a specific string being repeated after a defined number of lines. counting jump between first two 'Rank' occurrences. For example the file looks like this: 1 5 6 8 Rank line-start 2 4 8 5 7 5 8 6 5 4 6 4 1 5 7 4 Rank line-end 4 8 6 4 2 4 8 5 3 6 8 9 5 4 6 4 Rank You can notice that the string Rank is repeated every 3rd line. So the number of lines in a block is 4 for the above example. My Question is how do i get the number of lines using python readline(). I currently follow this: data = open(filename).readlines() count = 0 for j in range(len(data)): if(data[j]