readfile

How is the logic behind storing program setting in text file like 'config.cfg'?

懵懂的女人 提交于 2019-12-06 04:08:24
Often I see some software and specially games that store setting in a text file. I want to have same thing in my C# WinForms application too (I know it is possible to do with application settings for both user and software side) Since I think it is easier for end user to deal with it. So what I need to know is how these settings files are being read and for example set the fields of a class. Imagine I have a class that has the following fields: private double vOffset = 0; private bool Refresh = false; And here will be my text file (lets say file is named "config.cfg"): ;This is a comment

NodeJS readFile() retrieve filename

跟風遠走 提交于 2019-12-06 01:07:47
问题 I am iterating over an array which contains filenames. For each of them, I invoke readFile() . When the corresponding callback is invoked, I wish to retrieve the filename passed to readFile() as a parameter. Can it be done? Enclosed a snipped code to better explain my intention. var fs = require("fs"); var files = ["first.txt", "second.txt"]; for (var index in files) { fs.readFile(files[index], function(err, data) { //var filename = files[index]; // If I am not mistaken, readFile() is

How to read docx file content in java api using poi jar

前提是你 提交于 2019-12-05 21:30:46
I have done reading doc file now i'm trying to read docx file content. when i searched for sample code i found many, nothing worked. check the code for reference... import java.io.*; import org.apache.poi.xwpf.usermodel.XWPFDocument; import org.apache.poi.xwpf.extractor.XWPFWordExtractor; import com.itextpdf.text.pdf.PdfWriter; import com.itextpdf.text.Document; import com.itextpdf.text.Paragraph; public class createPdfForDocx { public static void main(String[] args) { InputStream fs = null; Document document = new Document(); XWPFWordExtractor extractor = null ; try { fs = new FileInputStream

Skipping Blank lines in read file python

天涯浪子 提交于 2019-12-05 16:56:53
Im working on a very long project, i have everything done with it, but in the file he wants us to read at the bottom there are empty spaces, legit just blank spaces that we aren't allowed to delete, to work on the project i deleted them because i have no idea how to get around it, so my current open/read looks like this file = open("C:\\Users\\bh1337\\Documents\\2015HomicideLog_FINAL.txt" , "r") lines=file.readlines()[1:] file.close() What do i need to add to this to ignore blank lines? or to stop when it gets to a blank line? for line in file: if not line.strip(): ... do something Follwoing

nodejs异步编程

∥☆過路亽.° 提交于 2019-12-05 15:37:52
nodejs异步编程,老生常谈。今天总结一下,算是巩固学习吧。 以读文件为例,同步编程这么写: var fs = require ( "fs" ); var fileContent = fs.readFileSync( 'sync.js' , 'utf8' ); console.log(fileContent); console.log( "something else" ); 异步编程咋整?回调函数伺候之: var fs = require ( "fs" ); fs.readFile( 'async.js' , 'utf8' , function (err,data) { if (!err) { console.log(data); } }); console.log( "something else" ); 回调函数太棒了,程序可以异步了。不过回调这东西有点好过头了,当回掉函数嵌套太多时候,程序写起来相当烦人。我想每个人都知道回调地狱(callback hell)。 javascript这个又爱又恨的东西这几年发展很快,投入的很大精力去改进的东西很多东西都是为了避免回调地狱。到现在(2016-5-17),es7草案已经提出,下面我们就以es7的视野来总结一下如何避免callback hell来异步编程。 模块化代码 使用生成器 使用promise 使用时间驱动编程

Java reading txt.file - access denied?

别来无恙 提交于 2019-12-05 13:55:54
I have created a txt file which I have saved in My Documents on my computer. I am trying to read the txt file through FileReader and BufferedReader . However, when I try to run the program I get the error message: java.io.FileNotFoundException: <filelocation> (Access is denied) Does anyone know what causes this, and how I might fix the problem? I have tried saving the document other places too, but I always get this message. I am sure the file path is correclty entered. One random guess is that you may be having multiple instance of your test program running so the file is locked by earlier

ReadFile function returns ERROR_INVALID_PARAMETER

三世轮回 提交于 2019-12-05 05:01:50
问题 I'm trying to get to work ReadFile function. Here's my code: #define BUFFERSIZE 5 int main(int argc, char* argv[]) { OVERLAPPED overlapIn = {}; HANDLE tHandle; char buf[BUFFERSIZE] = {}; DWORD lpNumberOfBytesRead; tHandle = CreateFile( L"\\\\.\\D:", GENERIC_READ, FILE_SHARE_READ, NULL, OPEN_EXISTING, FILE_ATTRIBUTE_NORMAL, NULL); if (tHandle == INVALID_HANDLE_VALUE) { DWORD error = GetLastError(); assert(0); } if (ReadFile(tHandle, &buf, BUFFERSIZE - 1, &lpNumberOfBytesRead, NULL) == 0) { int

Read two textfile line by line simultaneously -java

╄→гoц情女王★ 提交于 2019-12-05 04:19:04
I have 2 textfiles in two different languages and they are aligned line by line. I.e. the first line in the textfile1 should be equals to the first line in textfile2, and so on and so forth. Is there a way to read both file line-by-line simultaneously? Below is a sample of how the files should look like, imagine the number of lines per file is around 1,000,000. textfile1: This is a the first line in English This is a the 2nd line in English This is a the third line in English textfile2: C'est la première ligne en Français C'est la deuxième ligne en Français C'est la troisième ligne en Français

Open local file in electron and render in wavesurfer.js

白昼怎懂夜的黑 提交于 2019-12-05 03:03:10
I'm working on an app built with electron, it should work with wavesurfer.js to display a waveform representing the audio file. However, I'm having trouble opening the file using the fs module and pushing the file content to wavesurfer via a Blob. The file loads and everything seems to work but when decoding wavesurfer says Error decoding audiobuffer . Two things I thought maybe could influence this: The fs.readFile function takes an encoding as second parameter The Blob constructor takes an options object as second parameter, whithin this you can define the mimetype via the type property

Read maven.properties file inside jar/war file

不打扰是莪最后的温柔 提交于 2019-12-04 19:34:55
Is there a way to read the content of a file ( maven.properties ) inside a jar/war file with Java? I need to read the file from disk, when it's not used (in memory). Any advise on how to do this? Regards, Johan-Kees One thing first: technically, it's not a file. The JAR / WAR is a file, what you are looking for is an entry within an archive (AKA a resource). And because it's not a file, you will need to get it as an InputStream If the JAR / WAR is on the classpath, you can do SomeClass.class.getResourceAsStream("/path/from/the/jar/to/maven.properties") , where SomeClass is any class inside