rank

I have a dataset with 142 data entries: 121 individuals measured on two occasions (two years, before and after treatment, Year = 0 or 1), in the second year 46 individuals were in treated plots and the rest were in control plots (treatment = 0 or 1). Here's some example data: ID <- c("480", "480", "620", "620","712","712") Year <- c("0", "1", "0", "1","0", "1") Plot <- c("14", "14", "13", "13","20","20") Treat <- c("0", "0", "0", "1", "0", "1") Exp <- c("31", "43", "44", "36", "29", "71") ExpSqrt <- c("5.567764", "6.557439", "6.633250", "6.000000", "5.385165", "8.426150") Winter <- data.frame

I am looking to get the top 3 distinct salaries of each department. I was able to do it either using RANK() or DENSE_RANK() or ROW_NUMBER() but my table is having some records with same salaries. Mentioned below is my query and its result. The top 3 salaries of Dept 20 should be 6000, 3000, 2975. But there are 2 employees with salary 3000 and both of them have rank 2. So it is giving me 4 records for this department (1 for rank 1, 2 records for rank2 and 1 record for rank3). Please suggest/advise about how can get the distinct top 3 salaries for each department. Query: SELECT * FROM ( SELECT

I've got my mysql table posts , where all posts of my forum are stored. It's like this: id uid thread post title text time (int) (int) (varchar) (int) (varchar) (text) (int) Now I want to show the rank (ranking of number of posts) on the user profiles. I've tried something like this: set @rownum := 0; SELECT @rownum := @rownum + 1 AS rank, uid, count(id) FROM `posts` GROUP BY uid ORDER BY count(id) But it returns not the right data. The uid and count(id) match, but the rank is wrong. My entry is like: rank uid count(id) 1 1 214 I'm user 1, and I've got 214 posts, but that's not rank 1. There

I am trying to figure our a way to calculate rank. Right now it simply takes ratio of wins / losses of each individual entry, so e.g. one won 99 times out of a 100, it has 99% winning rank. BUT if an entry won 1 out of total 1 votes, it will have a 100% winning rank, but definitely it can't be higher that of the one that won 99 times. What would be a better way to do this? Depending on how complicated you want to make it, the Elo system chess uses (or something similar) may be what you want: http://en.wikipedia.org/wiki/Elo_rating_system Even if a person has won 1/1 matches, his rating would

这里使用的Intellij IDEA的版本是14.1.1，使用maven构建的项目是 Rank ， rank是一个seo工具，用于分析网站的搜索引擎收录排名。 1、将项目FORK到自己的GITHUB主页，如何FORK参考这里的 入门指南 链接，然后从自己的GITHUB账户下检出代码，要将下面的ysc换成你的GITHUB账户名称： 2、从现存源码新建一个项目： 3、找到项目保存的位置： 4、选择Maven： 5、选中“Import Maven projects automatically"： 6、选择项目： 7、JDK必须是1.8： 8、项目名称： 9、选择第一个New Window： 10、从左面项目导航区找到相应的类， 在右面代码区单击右键，运行main方法 ： 11、在下面的控制台输出窗口就会有日志，如果想控制日志的详细程度，则修改左面的项目导航区中的日志配置文件src/main/resources/logback.xml： 来源： oschina 链接： https://my.oschina.net/u/121944/blog/402634

I have code to display two subgraphs: graph { rankdir=LR; subgraph cluster01 { label="t=0" a0 [label="A"]; a1 [label="B"]; a2 [label="C"]; a5 [label="E"]; a0 -- a1; a1 -- a2 ; a2 -- a0; }; subgraph cluster02 { label="t=10" b0 [label="A"]; b5 [label="E"]; b1 [label="B"]; b2 [label="C"]; b0 -- b1; b2 -- b5; }; a0--b0 [style=dotted]; a1--b1 [style=dotted]; a2--b2 [style=dotted]; a5--b5 [style=dotted]; } This code displays two subgraphs like this: But I want to have it like this: I hope someone will help me fix the "rankdir" to get it done. The following was achieved by using invisible edges and

df <- data.frame (Categories=c("Alpha Category", "Alpha Category", "Alpha Category", "Bravo Category", "Bravo Category", "Bravo Category", "Charlie Category", "Charlie Category", "Charlie Category"), choices=c("alpha1", "alpha2", "alpha3", "bravo1", "bravo2", "bravo3", "charlie1", "charlie2", "charlie3") , ratings=c(20,60,40, 55,75,25,65,35,45)) df.plot <- ggplot(df, aes(Categories, ratings, fill = choices)) + geom_bar(position="dodge", stat="identity") + coord_flip() df.plot <- df.plot + theme_classic(base_size = 16, base_family = "") + scale_fill_brewer(palette="Paired") df.plot <- df.plot +

I've made an SQL query which rank pages by how many times they have been viewed. For instance, ╔══════╦═══════╗ ║ PAGE ║ VIEWS ║ ╠══════╬═══════╣ ║ J ║ 100 ║ ║ Q ║ 77 ║ ║ 3 ║ 55 ║ ║ A ║ 23 ║ ║ 2 ║ 6 ║ ╚══════╩═══════╝ Now what I would like to do is find the percentile rank of each page using an SQL query. The math I would like to use for this is simple enough, I just want to take the row number of the already generated table divided by the total number of rows. Or 1 minus this value, depending on my interests. Can I do a COUNT(pages) on an already generated table like this? I realize that's