quartz-scheduler

问题 I am experiencing a situation where one of the jobs in my Grails app stops running without any explicit reason. There is no exception thrown. We are using Grails 2.2.3 and Quartz2 plugin. Interesting thing is that all the other jobs which keep running; only one particular job keeps freezing time and again. This job makes a call to the 3rd party REST API calls which sometimes give a very delayed responses and also no responses at all in few instances. All the jobs are concurrent = false . Can

问题 I have my own ITrigger . Basically, it looks like the below: public interface ITrigger : IDisposable { /// <summary> /// Occurs when an input has been trigger. /// </summary> event InputTriggedEventHandler InputTrigged; /// <summary> /// Starts the trigger. /// </summary> /// <param name="trigger">The data about the trigger to start.</param> void Init(Trigger trigger); } One implementation of this interface is a FileCreatedTrigger which fires the event when a file is created. I want another

问题 We're using Quartz 1.8.6 in our app. We are using CronTriggers for hourly and nightly jobs. We would like to set things up such that if there is a misfire, we want to skip the job until the next cron time rolls around. For simple jobs, it appears you can do a nightlyTrigger.setMisfireInstruction(SimpleTrigger.MISFIRE_INSTRUCTION_RESCHEDULE_NEXT_WITH_REMAINING_COUNT); However, it appears that this does not work with CronTrigger. What is the Misfire instruction to use in this case? 回答1: You

问题 I have created my own job class by extending the default class added couple of member variables and member methods. I saw the job gets triggered and is running for a very long time. I just wanted to get the Job Instance not the JobDetail and wanted to invoke any member methods which has been defined by me or wanted to access the member variables. Could you please let me know how we can achieve this? Thanks, Kathir 回答1: There is not such way, probably because quartz is meant to be compatible

问题 I'm using spring mvc 4.2.5.RELEASE and quartz 2.2.1 quartz-jobs 2.2.1 I have a user interface when the user inputs the name and the cron expression of a quartz job, and then I create the job like this SchedulerFactory schedFact = new org.quartz.impl.StdSchedulerFactory(); schedFact.getScheduler().getContext().put("externalInstanceEstatus", myObject); Scheduler sched = schedFact.getScheduler(); sched.start(); JobDetail job = null; job = newJob(MyTask.class) .withIdentity((String) String

问题 Trying to get quartz to log in ms sql server but getting error in web config file. </configSections> <quartz> <add key="quartz.scheduler.instanceName" value="SchedulingPOC"/> <add key="quartz.scheduler.instanceId" value="SchedulingPOC"/> <!-- Configure Thread Pool --> <add key="quartz.threadPool.type" value="Quartz.Simpl.SimpleThreadPool, Quartz" /> <add key="quartz.threadPool.threadCount" value="10" /> <add key="quartz.threadPool.threadPriority" value="Normal" /> <!-- Configure Job Store -->

问题 For the first time i stored the jobs and scheduled them using crontrigger with the below code. package com.generalsentiment.test.quartz; import static org.quartz.CronScheduleBuilder.cronSchedule; import static org.quartz.JobBuilder.newJob; import static org.quartz.TriggerBuilder.newTrigger; import java.util.Date; import java.util.Properties; import org.quartz.CronTrigger; import org.quartz.JobDetail; import org.quartz.Scheduler; import org.quartz.SchedulerFactory; import org.quartz

问题 Using Spring's integration api with Quartz , what will the effects be on cron jobs that have uncaught exceptions? Since the cronbean/worker thread did not catch the exception, will that mean the thread is dead and will not be able to go back to the SimpleThreadPool? If its dead and does not get back to the pool will that mean the SimpleThreadPool will need to create new threads, if say this happens multiple times thus emptying out the pool? This is a sample the stack trace: org

问题 I want to run a job at every 14 minutes form now. For example if I schedule a job at 11:04 am, using 0 0/14 * * * ? cron expression. then expected fire time suppose to be 11:18,11:32,11:46 and so on . but it will fire at 11:00,11:14:11,28:11:42,11:56,12:00 which is not expected. and why it fired at 12:00 o'clock after 11:56, there is diff of only 4 min. How can I achieve what I want using cron expression? Can any one explain me this behaviour of quartz cron? Thanks in advance. 回答1: Well, 0/14

问题 I have installed Quartz plugin in my Grails 2.1 application. Every 5 minutes one job is triggered that will calculate some numbers. The numbers are being shown on the side bar of every page. The calculated results will change frequently and my goal is when users refresh their screen they can see the new result on their sidebar. Right now my approach is to send ajax call to a controller and grab the result from the database and render it on the screen. Is there any way to store (cache) the