pycurl

版权声明：本文为博主原创文章，遵循 CC 4.0 BY-SA 版权协议，转载请附上原文出处链接和本声明。 本文链接：https://blog.csdn.net/yexiaohhjk/article/details/73117032 今天在win10下python3.6.0下 利用pip 安装pyspider时出现以下错误: Command "python setup.py egg_info" failed with error code 10 in C:\Users\Auser\AppData\Local\Temp\pip-build-57obphna\pycurl\ 解决办法: 利用wheel安装对应的pycurl 1 安装wheel pip install wheel 1 .2 下载pycurl编译安装包 访问:http://www.lfd.uci.edu/~gohlke/pythonlibs/下载对应Python版本的编译包 我的电脑py版本是py3.6 64位 于是选择下载最后一个到本地 然后在该目录下 pip install xxxx.whl文件 返回successfully就安装好了。 注意：在windows上面安装各种python包行不通的,都可以尝试通过以上方法安装. ———————————————— 版权声明：本文为CSDN博主「So_weak_yx」的原创文章

I'm trying to install pycurl via: sudo pip install pycurl It downloaded fine, but when when it runs setup.py I get the following traceback: Downloading/unpacking pycurl Running setup.py egg_info for package pycurl Traceback (most recent call last): File "<string>", line 16, in <module> File "/tmp/pip-build-root/pycurl/setup.py", line 563, in <module> ext = get_extension() File "/tmp/pip-build-root/pycurl/setup.py", line 368, in get_extension ext_config = ExtensionConfiguration() File "/tmp/pip-build-root/pycurl/setup.py", line 65, in __init__ self.configure() File "/tmp/pip-build-root/pycurl

I am making HTTP requests using the requests library in python, but I need the ip address from the server that responded the http request and I'm trying to avoid to make two calls (and possibly having a different ip address from the one that responded the request. Is that possible? Does any python http library allows me to do that? ps: I also need to make HTTPS requests and to use an authenticated proxy. Update 1: Example: import requests proxies = { "http": "http://user:password@10.10.1.10:3128", "https": "http://user:password@10.10.1.10:1080", } response = requests.get("http://example.org",

I was trying to install pycurl in a virtualenv using pip and I got this error ImportError: pycurl: libcurl link-time ssl backend (openssl) is different from compile-time ssl backend (none/other) I read some documentation saying that "To fix this, you need to tell setup.py what SSL backend is used" (source) although I am not sure how to do this since I installed pycurl using pip. How can I specify the SSL backend when installing pycurl with pip? Thanks helloworld2013 After reading their INSTALLATION file, I was able to solve my problem by setting an environment variable and did a reinstall

- Mac 不知道怎么操作的 rm 了 usr/local/ 里面的某些文件, 导致一直出现 pycurl: libcurl link-time ssl backend (openssl) is different from compile-time ssl backend (none/other), 卸载从新安装, 重新配环境变量, 重新编译 都无法解决 甚是心累; - 解决方法: 　　- 0. pip uninstall pycurl 　　- 1. brew install openssl 　　- 2. echo 'export PATH="/usr/local/opt/openssl/bin:$PATH"' >> ~/.bash_profile 　　　　ps: 这步出现了 Permission denied 你敢信 我可是 sudo 啊, 如果出现了这种情况, 直接用 vim 将 export PATH="/usr/local/opt/openssl/bin:$PATH" 写到 ~/.bash_profile 文件里; 　　- 3. export LDFLAGS="-L/usr/local/opt/openssl/lib" 　　- 4. export CPPFLAGS="-I/usr/local/opt/openssl/include" 　　- 5. export

How does the Requests library compare with the PyCurl performance wise? My understanding is that Requests is a python wrapper for urllib whereas PyCurl is a python wrapper for libcurl which is native, so PyCurl should get better performance, but not sure by how much. I can't find any comparing benchmarks. I wrote you a full benchmark , using a trivial Flask application backed by gUnicorn/meinheld + nginx (for performance and HTTPS), and seeing how long it takes to complete 10,000 requests. Tests are run in AWS on a pair of unloaded c4.large instances, and the server instance was not CPU