protected

Java Protected Access Not Working

由 ╄→尐↘猪︶ㄣ 提交于 2019-12-05 02:50:34
问题 In java, there's three levels of access: Public - Open to the world Private - Open only to the class Protected - Open only to the class and its subclasses (inheritance). So why does the java compiler allow this to happen? TestBlah.java: public class TestBlah { public static void main(String[] args) { Blah a = new Blah("Blah"); Bloo b = new Bloo("Bloo"); System.out.println(a.getMessage()); System.out.println(b.getMessage()); //Works System.out.println(a.testing); System.out.println(b.testing);

Why does the Object class in Java contain protected methods?

由 ╄→尐↘猪︶ㄣ 提交于 2019-12-05 02:08:42
问题 Why does the Object class in Java contain protected methods, such as clone() and finalize(), if all classes you use or write inherit the instance methods of Object? 回答1: If class C2 extends C1 , and C1 contains a public method, then the method in C2 (if overridden) must also be public ; Java makes it illegal to put additional restrictions on a method's access when overriding. If C1 contains a protected method, then an overriding method in C2 may be protected or public . These rules apply even

Using wget to download a file from a password protected link

由 限于喜欢 提交于 2019-12-05 01:53:08
问题 I am trying to use wget to download a file from a http link that is password protected. I am using the following syntax: wget --http-user=user --http-password=xxxxxx http://...... Am I using the right syntax? Should user and password be surrounded by quotes or double quotes? 回答1: I did this a few years ago and luckily found the script in a backup I still have. I remember it was a two-stage process. The first step is to get and store the cookie(s): wget --keep-session-cookies --save-cookies

Accessing a protected member variable outside a class

由 Deadly 提交于 2019-12-04 23:41:47
I'm querying for the ID of a field by accessing a class function which someone has already put in place. The result is a object returned with protected member variables. I'm struggling to see how I can access the member variable values outside the class. Just add a "get" method to the class. class Foo { protected $bar = 'Hello World!'; public function getBar() { return $this->bar; } } $baz = new Foo(); echo $baz->getBar(); Pawka Accessing protected or private variables from public is incorrect (thats why they are protected or private). So better is to extend class and access required property

@protected in Objective-C

由 ￡可爱￡侵袭症＋ 提交于 2019-12-04 23:40:55
问题 I have a simple class: #import <UIKit/UIKit.h> #import <CoreData/CoreData.h> @interface MyTableViewController : UITableViewController { @protected NSFetchedResultsController *_fetchedResultsController; } And one more: #import <UIKit/UIKit.h> @interface MyChildTableViewController : MyTableViewController { } - (void)someMethod; The problem is that I can't use _fetchedResultsController in MyChildTableViewController class. I get compile-time error: '_fetchedResultsController' undeclared (first

How to set base class members before derived class constructor is called?

由 安稳与你 提交于 2019-12-04 22:00:19
There is a base class for components of my application which provides some members and the functions Init() and Update() which must be overwritten. class Component { public: void Set(type* Member1, type* Member2, type* Member3) { this->Member1 = Member1; this->Member2 = Member2; this->Member3 = Member3; } virtual void Init() = 0; virtual void Update() = 0; virtual ~Component() {} protected: type* Member1; type* Member2; type* Member3; }; For handeling the components, there is a manager. It first sets the members of a component and then calls Init() on it. Later on it can be used to update all

Why can't you have a protected abstract class in Java?

由 时光毁灭记忆、已成空白 提交于 2019-12-04 18:50:39
问题 I have an abstract class which looks like: abstract class AbstractFoo implements Bar { //Code goes here } However when I try to make AbstractFoo protected I get an error compile time error complaining that it is an illegal modifier. protected abstract class AbstractFoo implements Bar { //Code goes here } Why can't you have a protected abstract class within Java? EDIT: I should probably mention that this is not vanilla Java and is actually Blackberry / J2ME. 回答1: As many others have noted, the

Google spreadsheet - Error when Remove range protection

由 |▌冷眼眸甩不掉的悲伤 提交于 2019-12-04 15:33:08
Here's my script, but I can't get it to work for some weird reason??!!! Driving me nuts. function removeThenSetProtection() { // Remove all range protections in the spreadsheet that the user has //permission to edit. var ss = SpreadsheetApp.getActive(); var protections = ss.getProtections(SpreadsheetApp.ProtectionType.SHEET); for (var i = 0; i < protections.length; i++) { var protection = protections[i]; if (protection.canEdit()) { protection.remove(); } } } Change: var protections = ss.getProtections(SpreadsheetApp.ProtectionType.RANGE); To: var protections = ss.getProtections(SpreadsheetApp

protected internal class working within class but not working outside

由 拟墨画扇 提交于 2019-12-04 15:24:43
I was trying few things and would like to know why this is happening so. Say, I have a class called A in namespace n and I was trying to create protected internal class B. namespace n { public class A { public A() { } } protected internal class B //throwing error { } } But when i try like this (B as a sub class of A), its not throwing error and its built success. Could you explain me why it is so? namespace n { public class A { public A() { } protected internal class B // its not throwing error { } } } Am i missing anything theoretically? Its quite a bit confusing. Look at the error. Elements

Ok, we can have private identifiers in javascript, but what about protected ones?

由 梦想的初衷 提交于 2019-12-04 13:41:38
Simple as that, can we emulate the "protected" visibility in Javascript somehow? Do this: /* Note: Do not break/touch this object */ ...code... Or a bit of google found this on the first page: http://blog.blanquera.com/2009/03/javascript-protected-methods-and.html Sure you can. Here's another example . What could that possibly mean? You don't have classes . I suppose you could analyze caller to determine whether it meets some set of criteria for being permitted to call a method. This will be hideously inefficient and your criteria will always be spoofable. There's an interesting pattern worth
订阅 protected