projection

3d to 2d Projection Matrix

五迷三道 提交于 2020-01-09 13:58:44
问题 I have 3 points in a 3D space of which I know the exact locations. Suppose they are: (x0,y0,z0) , (x1,y1,z1) and (x2,y2,z2) . Also I have a camera that is looking at these 3 points and I know the 2D locations of those three points on camera view plane. So for example (x0,y0,z0) will be (x0',y0') , and (x1,y1,z1) will be (x1',y1') and (x2,y2,z2) will be (x2',y2') from the camera's point of view. What is the easiest way to find the projection matrix that will project those 3D points into 2D

3d to 2d Projection Matrix

二次信任 提交于 2020-01-09 13:58:32
问题 I have 3 points in a 3D space of which I know the exact locations. Suppose they are: (x0,y0,z0) , (x1,y1,z1) and (x2,y2,z2) . Also I have a camera that is looking at these 3 points and I know the 2D locations of those three points on camera view plane. So for example (x0,y0,z0) will be (x0',y0') , and (x1,y1,z1) will be (x1',y1') and (x2,y2,z2) will be (x2',y2') from the camera's point of view. What is the easiest way to find the projection matrix that will project those 3D points into 2D

Convert lat/lon to pixel coordinate?

好久不见. 提交于 2020-01-08 13:23:29
问题 I'm trying to convert a lat/lon pair to a pixel coordinate. I have found this mercator projection but I don't understand the code. What is the factor,x_adj, y_adj variable? When I run the code without those constants my lat/lon pair is not on my map and the x and y pixel coordinate is not what I want. function get_xy(lat, lng) { var mapWidth=2058; var mapHeight=1746; var factor=.404; var x_adj=-391; var y_adj=37; var x = (mapWidth*(180+lng)/360)%mapWidth+(mapWidth/2); var latRad = lat*Math.PI

Projections' Angle of Line in Space

柔情痞子 提交于 2020-01-06 23:52:11
问题 Start of line (yellow) and axes are at [xc,yc,zc] End of line is at [xp,yp,zc] . a , b , c are the angles which line makes in space. What I need are the angles which line's projections (black line) create on xy,yz and xz planes. A_y_to_z : Projected line's angle from y axis to z axis on xz plane. A_z_to_x : Angle from z to x axis on zx plane. A_x_to_y : Angle from x to y axis on xy plane. Writing code on Matlab 回答1: You can calculate the projection angle to any plane by: Obtaining the

Java Spring projection inside projection

梦想与她 提交于 2020-01-06 06:36:32
问题 Is it possible to use a projection and in some related object use it's own projection? For example, a have Exam , that has List<Question> . I'd like to request a list of exams (wich I have a @projection ), but I'd like to define the attributes to be retreived for each related Question 回答1: If I understand correctly you want to use Projection as children of Projection. If it is the case, yes, you can. You can create a QuestionProjection and use inside the ExamProjection. Example: @Projection

R: plotting sky map in Mollweide projection in galactic coordinate system

女生的网名这么多〃 提交于 2020-01-06 05:30:14
问题 I need to produce the star map with constellations etc in the Mollweide projection (elliptical projection giving 360 view angle, used in plotting night sky). I found a recipe at https://kimnewzealand.github.io/2019/02/21/celestial-maps/ with the use of sf package and converting the default EPSG:4326 data of the sky objects into Mollweide projection. At some stage the data is converted to the Mollweide projection using the command: constellation_lines_sf_trans<- st_transform(constellation

What is the best way to achieve a diagonal text animation using storyboards in a Windows Phone Application?

醉酒当歌 提交于 2020-01-05 09:36:09
问题 I would like to create a storyboard that animates two TextBlocks by sliding them from right and left in the center of the Screen. I have tried rotating the TextBlocks and using Global Offset and Local Offset properties of Projection in Blend for Visual Studio and also manually using Translate X and Translate Y properties of the RenderTransform at specific Keyrames . The storyboard does kick off and appears perfect in Blend but when running on the actual device, the TextBlocks don't appear in

Minimize Euclidean distance from sets of points in 3-d

喜你入骨 提交于 2020-01-03 06:41:08
问题 Let's look at four (m) points in 3-d space- I want to generalize to n-d, but 3 should suffice for a solution ( Part 1). a= (x1, y1, z1) b= (x2, y2, z2) c= (x3, y3, z3) . . p= (x , y , z) Find point q = c1* a + c2* b + c3* c + .. where c1 + c2 + c3 +.. = 1 and c1, c2, c3, .. >= 0 s.t. euclidean distance pq is minimized. What algorithms can be used ? Idea or pseudocode is enough. Part 2: solve for m points in n-dimensions : I thought it would be trivial to generalize to m points in n dimensions

How to get visible size of DisplayObject with perspective projection

自闭症网瘾萝莉.ら 提交于 2020-01-03 04:47:08
问题 The following is entirely a math question. As we know, PerspectiveProjection delivers perspective transformations in 3D represented by the interdependent values of fieldOfView and focalLength according to the following formula: focalLength = stageWidth/2 * (cos(fieldOfView/2) / sin(fieldOfView/2) (source: bgstaal.net) Q: How to get the visible on-screen size of the DisplayObject (Cube on the above-linked image) to which PerspectiveProjection has been applied? A more thorough description and

Time Series Projection in Google BigQuery

﹥>﹥吖頭↗ 提交于 2020-01-03 04:32:06
问题 I was looking for a good way to do time series projection in BigQuery, and found this one, which nicely works to calculate correlations and slope: View Post. But it doesn't help to extend the timeline to your choice. But can anyone please suggest a complete solution, where I can extend the timeline (x) according to my need and get projections of (Y) using a single query? Any help will be highly appreciated. 回答1: The basic idea is to left join the model specs to a generated dates table and use