projection

I've been wondering which kind of projections should I use, so I did a little test, which covered 5 types of projections (based on docs: https://docs.spring.io/spring-data/jpa/docs/current/reference/html/#projections ): 1. Entity projection This is just a standard findAll() provided by Spring Data repository. Nothing fancy here. Service: List<SampleEntity> projections = sampleRepository.findAll(); Entity: @Entity @Table(name = "SAMPLE_ENTITIES") public class SampleEntity { @Id private Long id; private String name; private String city; private Integer age; } 2. Constructor projection Service:

I've been looking around a bit and can't seem to find just what I"m looking for. I've found "canonical formulas," but what's the best way to use these? Do I have to scale every single vertex down? Or is there a better way? A formula would really help me out, but I'm also looking for an explanation about the near and far z planes relative the viewer's position Bob Cross Here is a reasonable source that derives an orthogonal project matrix : Consider a few points: First, in eye space, your camera is positioned at the origin and looking directly down the z-axis. And second, you usually want your

I have a 3D scene and a camera defined using gluPerspective . I have a fixed FOV, and I know the minimum distance of any geometry to the camera (it is a first-person view, so that is the minimum distance from the viewpoint to the character's collision volume). How can I choose the farthest near clip plane (for the best depth buffer resolution) which will will not cause any clipping , no matter how the player moves and looks? These distances are not simply equal because the corners of the near plane are farther from the origin than the center. Formula: nearPlane = nearestApproachToPlayer / sqrt

In an attempt to convert screen space coordinates into world space coordinates, I've been doing the following calculation: WorldSpace Vector = inverse(Projection Matrix) * inverse(View Matrix) * ScreenSpace vector Up to this point, I believe I have most of my calculations right, however I'm unsure of how to perform the last step needed in order to have my vector transformed to world coordinates. Problem: I've been told that the last step of this process is to divide my results by the variable "w" because we are using homogeneous coordinates. However I have no idea what "w" represents. I've

I have a set of points which comprise a (in theory) co-planar curve. My problem is that the plane is arbitrary and can move between each time I collect the data (these points are being collected from a camera). I was wondering if you guys could help me figure out how to: find the plane which is closest to the one which these points are co-planar on project the points on this plane in such a way that gives me a 2-d curve I believe that I know how to do point 2, it is really mainly point 1 that i'm struggling with, but I wouldn't mind help on the second point as well. Thanks a ton! find 3 points