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问题 World.cpp: World::World() { //something } World::~World() { //something } void World::doSomething(Organism *organisms[20][20]) { cout << organisms[1][1]->Key(); // example of what I need to do here } int main() { World *world = new World(); World::doSomething(world->organisms); return 0; } world.h class World { public: static void doSomething(Organism *organisms[20][20]); World(); ~World(); Organism *organisms[20][20]; }; Organism.cpp Organism::Organism(){ } Organism::~Organism(){ } char

问题 This is my code package alpha ; class A1 { static class A11 { private final // WHAT IS THE EFFECT OF THIS MODIFIER? void fun ( String caller ) { System . out . println ( "A11:\t" + caller ) ; } } static class A12 extends A11 { private void fun ( String caller ) { super . fun ( caller + caller ) ; } } public static void main ( String [ ] args ) { A12 a12 = new A12 ( ) ; a12 . fun ( "Hello" ) ; } } I have found that with or without the final mdifer in A1.A11 the program compiles and runs. I can

问题 Consider the following code in my library: pub struct Foo; impl Foo { fn helper(&self) { /* .. */ } } pub fn do_something(foo: &Foo) { foo.helper(); } The users of my library should be able to use Foo and do_something() , but shall never call helper() . Everything works fine with the code above. But now imagine the code gets huge and I want to separate those definitions into their own files/modules -- they are then pulled back into the root-namespace with pub use . See here: mod foo { //

问题 This snippet used to work properly with Groovy 2.1.0: class User { private String sayHello() { return "hello" } } assert new User().sayHello() == "hello" User.metaClass.sayHello = { return "goodbye" } assert new User().sayHello() == "goodbye" but it does not work anymore in Groovy 2.4.3. Does anybody know how to override the behaviour of a private method with Groovy (if possible)? 来源： https://stackoverflow.com/questions/31938551/overriding-private-method-with-metaclass-in-groovy

问题 I trying to write some files on the internal storage. I saw the FileOutputStream fos = openFileOutput(FILENAME, Context.MODE_PRIVATE); on Data Storage and I understood that the file will be private to my application. but the problem is it can only open a file without a path, so first I opened a new directory file with file.mkdir(), but now, how do I write the file as private ? 回答1: I saw theFileOutputStream fos = openFileOutput(FILENAME, Context.MODE_PRIVATE); on Data Storage and I understood

问题 A collegue of mine has written the following code in a multithreaded c# app... public class1 { private static partialClass var1 = new partialNonStaticClass(); public static method1() { //do something with var1 } } Although var1 is private and set to a nonstatic partial class, the fact that it is static means it could be shared by all threads. Also, no locking is performed on var1. Therefore, var1 is not threadsafe. Just wanted someone to verify that I am correct. 回答1: , the fact that it is

问题 The Principle Engineer at my last company had a rule that private static methods should be implemented as functions in the implementation file, not as class methods. I don't remember if there were any exceptions to his rule. I have stumbled into the motivation for it at my current job: If the arguments or return type of the function in question are objects that would require the inclusion of a definition file in the header, this can cause unnecessary difficulties. That's enough to steer me

问题 Is it possible to make a C# base class accessible only within the library assembly it's compiled into, while making other subclasses that inherit from it public? For example: using System.IO; class BaseOutput: Stream // Hidden base class { protected BaseOutput(Stream o) { ... } ...lots of common methods... } public class MyOutput: BaseOutput // Public subclass { public BaseOutput(Stream o): base(o) { ... } public override int Write(int b) { ... } } Here I'd like the BaseOutput class to be

问题 Suppose I have a private[stuff] method Stuff.something in org.my.stuff . Is there something that I can do in the Scala REPL so that I can call Stuff.something without getting the error error: value something is not a member of org.my.stuff.Stuff ? In particular, can I get the REPL to be "inside" a given package (here org.my.stuff ), giving access to its private members? 回答1: Using "packages" in the REPL You cannot get a REPL prompt "inside" a given package, see https://stackoverflow.com/a

问题 I've been spending quite some time trying to figure out how exactly to retrieve the raw private key data from openssl_pkey_get_private() using a passphrase. I feel like there's a simple thing I am missing. Here's my code: $config = array( "private_key_bits" => 2048, //size of private key ) $privKey = openssl_pkey_new($config); //creating a private key resource openssl_pkey_export($privKey, $pkeyout,"test123",$config); //obtaining an encrypted private key $result = openssl_pkey_get_private(