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问题 Is it possible to assign properties with private setters using AutoMapper? 回答1: If you set the value for this properties in the constructor like this public class RestrictedName { public RestrictedName(string name) { Name = name; } public string Name { get; private set; } } public class OpenName { public string Name { get; set; } } then you can use ConstructUsing like this Mapper.CreateMap<OpenName, RestrictedName>() .ConstructUsing(s => new RestrictedName(s.Name)); which works with this code

问题 I don't know how to make a struct or object as threadprivate, what I'm doing generates a error: struct point2d{ int x; int y; point2d(){ x = 0; y = 0; } //copy constructor point2d(point2d& p){ x = p.x; y = p.y; } }; I declare a static structure and try to make them threadprivate static point2d myPoint; #pragma omp threadprivate(myPoint) It generates an error: error C3057: 'myPoint' : dynamic initialization of 'threadprivate' symbols is not currently supported Does it means that current openmp

问题 package com.valami; public class Ferrari { private int v = 0; private void alam() { System.out.println("alam"); } public Ferrari() { System.out.println(v); } public static void main(String[] args) { Ferrari f = new Ferrari(); f.v = 5; System.out.println(f.v); } } Hi all! I have one simple question.... WHY can I reach a private variable from the main method ? I know, I'm in the containing class, but it is main. I believed the main is NOT part of the class which is containing it... Then I would

问题 I have a class that benefits from the use of constants in its internal implementation, but I would like to limit visibility of these constants. Why doesn't PHP permit private constants? Is there another way to achieve this or is PHP trying to discourage some type of design misstep I am ignorant of? 回答1: Use private static properties. In that case you will have the same variable throughout all objects and if you want to extend its scope to nested, you can expose a getter method to get its

问题 Consider the following piece of code: class foo { private function m() { echo 'foo->m() '; } public function call() { $this->m(); } } class bar extends foo { private function m() { echo 'bar->m() '; } public function callbar() { $this->m(); } } $bar = new bar; $bar->call(); $bar->callbar(); Now, changing the visibility of the m() method, I get: ( + for public , - for private ) Visibility bar->call() bar->callbar() ====================================================== -foo->m(), -bar->m() foo

问题 class Employee{ // salary variable is a private static variable private static double salary; // DEPARTMENT is a constant public static final String DEPARTMENT = "Development"; public static void main(String args[]){ salary = 1000; System.out.println(DEPARTMENT+ " average salary:"+salary); } } This java program contains a static variable. But I cannot understand the difference between public and private static variables. 回答1: A public variable is accessible everywhere in the code - a private

问题 I have a private repository on Github for a project I'm working on. Until now I had only worked on my home desktop, but I just bought a laptop, and am trying to set it up so that I can work on the project from either computer, and push / pull changes. I added a new SSH key to my Github account for the laptop, and was successful in cloning and making changes to a public test repo that I set up. However, I couldn't clone the private repo. Is there anything special I need to do in the command

问题 This is a followup to this question about java private constructors. Suppose I have the following class: class Foo<T> { private T arg; private Foo(T t) { // private! this.arg = t; } @Override public String toString() { return "My argument is: " + arg; } } How would I construct a new Foo("hello") using reflection? ANSWER Based on jtahlborn's answer, the following works: public class Example { public static void main(final String[] args) throws Exception { Constructor<Foo> constructor;

问题 Just seen one tutorial saying that: Class Dog { private string Name; } Class SuperDog:Dog { private string Mood; } Then there was an UML displaying that SuperDog will inherit Name as well. I have tried but to me it seems that only public members are inherited. At least I could not access Name unless it was declared as public. 回答1: A derived class has access to the public, protected, internal, and protected internal members of a base class. Even though a derived class inherits the private

问题 This article has been helpful in understanding the new access specifiers in Swift 3 . It also gives some examples of different usages of fileprivate and private . My question is - isn't using fileprivate on a function that is going to be used only in this file the same as using private ? 回答1: fileprivate is now what private used to be in earlier Swift releases: accessible from the same source file. A declaration marked as private can now only be accessed within the lexical scope it is