prepared-statement

insert null for DATETIME Field through PrepareStatement using jdbc

扶醉桌前 提交于 2019-12-08 03:59:33
问题 i want to insert null value into an DATETIME Field through PrepareStatement using JDBC (using Mysql Database) i have tried following ways but nothing is worked. i have a method " Util.dateconvertdate " it use to convert input date into a formatted string type public static String dateconvertdate(Timestamp timestamp) { Date date=null; String formattedDate=""; if(timestamp != null){ SimpleDateFormat sdf = new SimpleDateFormat("dd-MMM-yyyy hh:mm:ss"); SimpleDateFormat formatter = new

JAVA + Mysql PreparedStatement.setString() ArrayStoreException

北慕城南 提交于 2019-12-08 03:20:51
问题 I've been getting this ArrayStoreException in my code for loading records from one mysql table to another. I tried truncating the destination table and running my code again and it seems that it encounters the said exception randomly. I was going to implement a (Spring) JdbcTemplate based DAO when i've encountered an ArrayStoreException during unit testing. I tried to recreate it with ordinary JDBC code and still encounter the error. For my DDL: All the columns are of type varchar, except for

mysql - Select all from one table and one column form another where $var is found

老子叫甜甜 提交于 2019-12-08 02:11:48
问题 Ooooookay. I have two tables client and users. Both have AUTO_INCREMENT id but client table has credid-column whis is foreign key and references to users table's id. I want to prepare a PHP PDO statement that fetches all columns from client-table and only username-column from users-table where client table's column credid = :var and user table's column id = :var So far I have something like this and it is not working $userid = $_SESSION['id']; //echoes a number $STH = $DBH->prepare("SELECT *

PHP SQLSRV Sorting with Parameter of Prepared Statement

放肆的年华 提交于 2019-12-08 01:59:25
问题 I can't figure out why sorting will work as long as I'm not using $sort as a passed in parameter. Example below will work for sorting: $sort = "quantity desc"; $sql = " with items as ( SELECT i.[item_id] ,i.[name] ,i.[value] ,i.[quantity] ,i.[available] ,isnull(r.awarded, 0) as awarded , ROW_NUMBER() OVER( ORDER BY $sort ) rowNumber FROM [Intranet].[dbo].[Goodwell_Item] i LEFT JOIN ( SELECT r.item_id , COUNT(1) awarded from [Intranet].[dbo].[Goodwell_Reward] r group by r.item_id ) as r ON i

JDBC - prepareStatement - How should I use it?

烈酒焚心 提交于 2019-12-07 20:12:47
问题 I saw this example somewhere: rs = connection.prepareStatement("select * from table").executeQuery(); Could I use this format, if I want to execute a query like this " Select * from table where column = "hello" "? The way in which I usual I use prepareStatement object is something like this: String sql = "select * from adresa where column = ?"; PreparedStatement pre = con.prepareStatement(sql); pre.setString(1, i); rs = pre.executeQuery(); Later Edit: I don't understand. Pascal Thivent wrote

PHP MySQL - How to insert default value in a prepared statement

a 夏天 提交于 2019-12-07 18:08:29
问题 Let's say I have a prepared statement that looks like this: $insertSql = ""; $insertSql .= "INSERT INTO table"; $insertSql .= "(tag,month_interval,month_interval_lastupdated,date_due,date_due_lastupdated,date_completion,date_completion_lastupdated,"; $insertSql .= "activeNotification,date_lastmodified) "; $insertSql .= "VALUES (?,?,NOW(),?,NOW(),?,NOW(),?,NOW())"; But sometimes some of those question marks would not be set. Is there a keyword I can substitute in the prepared statement that

Java does not run prepare statements with parameter

元气小坏坏 提交于 2019-12-07 17:00:58
问题 I am using PreparedStatement to query my table. Unfortunately, I have not been able to do so. My code is as simple as this: PreparedStatement preparedStatement = connection.prepareStatement( "Select favoritefood from favoritefoods where catname = ?"); preparedStatement.setString(1, "Cappuccino"); ResultSet resultSet = preparedStatement.executeQuery(); The error thrown is java.sql.SQLException: ORA-00911: invalid character . As if it never run through the parameter given. Thanks for your time.

mysql_query to PDO and prepared statements

拥有回忆 提交于 2019-12-07 14:56:22
问题 I have this function in my CMS, which inserts a variable list of fields and values into two different tables; one is a static index table and one is dynamic. This is the function: function insertFields($fields) { $stdfields = array(); $extfields = array(); /* Separate the fields based on if the fields is standard or extra. $this->fields is a csv list of the defined extra fields */ foreach($fields as $field => $value) { $fields[mysql_real_escape_string($field)] = mysql_real_escape_string(

Strange issue with mysqli_stmt_bind_result

会有一股神秘感。 提交于 2019-12-07 11:36:25
问题 Alright so this bugs the crap out of me, and I can't seem to find anything in the PHP documentation, nor anywhere in the Google resultosphere, so maybe someone can help here. I am using prepared statements, binding the results, and then using those bound results to populate dropdown. Example: <option value="">Select artist</option> <?php $artistQuery = "SELECT ArtistID,ArtistName FROM Artist_v"; if($artist = mysqli_prepare($link,$artistQuery)){ mysqli_stmt_execute($artist); $artistResult =

Is it better to use a prepared Select statement when you are only doing one select?

给你一囗甜甜゛ 提交于 2019-12-07 09:47:41
问题 I am currently writing a CRUD class in PHP using PDO. I like the security that prepared statements provide, but I have heard that they also prevent databases like mysql from using the queryCache. Is it better to use a prepared Select statement when you are only doing one select at a time? or would just $pdo->quote() suffice the security standpoint (or have any other advantages like caching?). All my update, delete and inserts are done using prepared statements already. I am just curious about