prepared-statement

Prepared Statement not returning anything

☆樱花仙子☆ 提交于 2019-12-13 14:02:03
问题 Please forgive me for the possibility of the stupidity of this question, but I've just started using prepared statements. I know this particular query works, as I tested it with unprepared, procedural methods. Here it is: $name = 'introduction'; $mysqli = new mysqli('localhost', 'user', 'pass', 'db') or die('There was a problem connecting to the database.'); $stmt = $mysqli->prepare("SELECT name, content FROM sections WHERE name = ?"); $stmt->bind_param('s', $name); $stmt->execute(); $stmt-

Login using MySqli Prepared Statement

放肆的年华 提交于 2019-12-13 10:43:07
问题 I checked my code by replacing all the statements inside IF with a echo statement and its working fine.. if($rows==1){ echo "Record exists in DB"; } I don't know why $result = mysqli_stmt_get_result($stmt); returning false and I am getting error as Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in E:\xampp\htdocs\jq\login_system_sql_injection_proof\loginprocess.php on line 57 I Wasted more than a day for searching Solution over Internet but did not find

I have a blank page after submitting a php mysqli update form,

拈花ヽ惹草 提交于 2019-12-13 09:00:40
问题 Hi I am trying to complete this update and It keeps sending me a blank page with no errors and not submitting the info into the DataBase. Everything works up to the point of the prepared statement as far as i can tell, it draws the id and the other variables no problem from the database and the previous search queries but wont let me go any further. Can anyone see where I have gone wrong, I just cant see it??? <html> <head> <title> <?php if ($id != '') { echo "Edit Record"; } else { echo "New

String with an apostrophe not being updated in mysqli

青春壹個敷衍的年華 提交于 2019-12-13 08:58:24
问题 I am using prepared statements to preform an update. But for some reason a string that contains an apostrophe does not get updated. Is there a way where I can update a string ans preserve the apostrophe?? Below is an example of my query $query = "UPDATE items SET item_name = ? , item_price = ? WHERE id = ? "; $stmt = $db->prepare($query); foreach($items_and_prices as $id => $item_and_price){ $item = $item_and_price[0]; $price = $item_and_price[1]; $stmt->bind_param("sdi",$item, $price,$id);

mysqli_connect not working on MAMP

守給你的承諾、 提交于 2019-12-13 08:39:26
问题 The code below worked on my old iMac with MAMP. However, it does not work on my new iMac. How do I fix this? Do I need to do something to the php.ini file? <?php $dbConnection = mysqli_connect("localhost", "xxxx", "xxxx", "gallery"); $query = "SELECT * FROM images"; $stmt = mysqli_prepare($dbConnection,$query); mysqli_stmt_execute($stmt); mysqli_stmt_bind_result($stmt, $id, $categories,$img_name); while (mysqli_stmt_fetch($stmt)) { echo $id."<br />"; } ?> 回答1: You should enable php_mysqli

Problem with python prepared stmt parameter passing

元气小坏坏 提交于 2019-12-13 08:30:12
问题 File C:\Users\User\AppData\Local\Programs\Python\Python37\lib\site-packages\mysql\connector\cursor.py, line 1149, in execute elif len(self._prepared[parameters]) != len(params): TypeError: object of type int has no len() 回答1: The problem is python make error when we pass single parameter we need to put comma(,) at the end of first parameter. like the follwoing input=(customerId,) cursor.execute(sql, input) 来源: https://stackoverflow.com/questions/55762444/problem-with-python-prepared-stmt

How can I setting parameters to query based on quarter date

大憨熊 提交于 2019-12-13 08:19:01
问题 I need to find the start of the quarter startQ1,startQ2 ect. run a query that takes 6 query parameters. I dont really know a way of doing this. So if I can use a calendar to find that today is March1st (startq1) I wan't to run the query with the q1 array ... Hope that's clearer. Calendar cal = Calendar.getInstance(); java.sql.Date startQ1 = java.sql.Date.valueOf("2014-03-01"); java.sql.Date startQ2 = java.sql.Date.valueOf("2014-06-01"); java.sql.Date startQ3 = java.sql.Date.valueOf("2014-09

When putting rows into array it duplicates

╄→гoц情女王★ 提交于 2019-12-13 07:26:42
问题 I am trying to create a class for easier safe MySQLi connections an queries, but I came across this problem where it duplicates $row like [0] => 47, [example_id] => 47 Basically lets say I got a table like this ╒═══════════════════════════════════════════════╕ │ Content | ╞════════════╤═══════════════╤══════════════════╡ │ example_id │ example_title │ example_content │ ╞════════════╪═══════════════╪══════════════════╡ ╞════════════╪═══════════════╪══════════════════╡ │ 1 │ Hello World 1 │

PHP Prepare statement - getting errors having a query inside a while loop

戏子无情 提交于 2019-12-13 07:06:24
问题 I'm attempting to execute a query withing a query. The first loop displays all customer data, the second loop displays the orders for that customer. The code I have so far: $stmt = $conn->prepare("SELECT * FROM Customers WHERE travel_Date >= ? AND travel_Date <= ? ".$searchOption." LIMIT ? OFFSET ?"); $todayDateFrom = $todayDate." 00:00:00"; $todayDateTo = $todayDate." 23:59:59"; $stmt->bind_param("ssii", $todayDateFrom, $todayDateTo, $limit, $offset); $stmt->execute(); /* bind variables to

how to save image path to sql database in java

匆匆过客 提交于 2019-12-13 06:42:45
问题 I have to save the image path chosen by jfilechooser to sql database and load that image every time from that sql path. Im using preparedStatment . But I got the path saved in sql database without "\" . Here is part my code.. Please help me on this. PreparedStatement ps = null; ResultSet rs = null; Connection conn = null; conn = DBConnection.ConnectDB(); try { JFileChooser choose = new JFileChooser(); choose.showOpenDialog(null); File f = choose.getSelectedFile(); if (f != null) { fileName =