prepared-statement

问题 I'm trying to add a record, and at the same time return the id of that record added. I read it's possible to do it with a RETURNING clause. $stmt->prepare("INSERT INTO tablename (field1, field2) VALUES (:value1, :value2) RETURNING id"); but the insertion fails when I add RETURNING. There is an auto-incremented field called id in the table being added to. Can someone see anything wrong with my syntax? or maybe PDO does not support RETURNING ? 回答1: I don't think it has anything to do with PDO

问题 I'm a beginner at python. We use this code to execute SQL commands. cur.execute("INSERT INTO test (num, data) VALUES (%s, %s)", (100, "abcdef")) I wonder is this prepared statement or just a client side quoting? 回答1: No, it does not, not for psycopg2 at least. The "Prepare" in the docs refers to a "PREPARE TRANSACTION" which is entirely different than a prepared statement. You can emulate a prepared statement, by overriding the methods or executing extra statements, however. See: An example

问题 Is it possible to use one parameter in a prepared mysqli -statement multiple times with only binding it one time ? something like this $stmt = $mysqli->prepare(SELECT * FROM user WHERE age BETWEEN ?1 - 2 AND ?1 + 2); $stmt->bind_param('i', $myAge); I think this is possible with PDO , but I don't konw how to do this with mysqli . 回答1: Just to close the question: The answer is no . If you want to bind a parameter only one time and using it multiple times in a query you have to use PDO and this

问题 Let's pretend that I have two tables in an InnoDB database: categories and jokes ; and that I'm using PHP/MySQLi to do the work. The tables look like so: CATEGORIES id (int, primary, auto_inc) | category_name (varchar[64]) ============================================================ 1 knock, knock JOKES id (int, primary, auto_inc) | category_id (int) | joke_text (varchar[255]) ============================================================================= empty Thanks to a previous answer on

问题 I have the following code forexample: $dbStatement=$this->dbObject->prepare("SELECT AVG(quality) as quality, AVG(adequacy) as adequacy, AVG(friendliness) as friendliness, SUM(overall) as overall, SUM(completed) as completed, type FROM (SELECT AVG(quality) as quality, AVG(adequacy) as adequacy, AVG(friendliness) as friendliness, COUNT(id) as overall, SUM(is_completed) as completed, category_id, type FROM valuation a WHERE status =1 AND type =:01 AND ((type='employer' AND owner_id=:02) OR (type

问题 I wanted to know of some way to create table on the fly based on user input(SQL Prepared Statement) CREATE TABLE ? ( First_Name char(50), Last_Name char(50) ) What should i put in place of question mark 回答1: PreparedStatement placeholders are not intended for table names nor column names, they are only intended for actual column values. So you would have to create the (prepared) statement string dynamically, which means your application will be vulnerable to SQL injection . Depending on how

问题 In my mind, the following script should work: $stmt = $db->prepare("UPDATE table SET status = ?, date_modified = ?"); $stmt->execute(array(1, 'NOW()')); but when passing NOW() into the prepared statement, nothing happens. Replacing NOW() with an actual date (i.e. 2010-11-23) works just fine. I am unable to find explanation online. Any ideas? EDIT Just to further clarify and rid of any confusion in the question, I want to actually pass a variable into the prepared statement HOWEVER, the

问题 I'm trying to make a log in system by using AES_ENCRYPT() to encode my password. But I have some warning from xdebug when trying to implement these codes: ... $key = 'd0gis=SUPER-cute'; $sql = "SELECT * FROM `users2` WHERE username = ? AND pwd = AES_ENCRYPT(?, ?)"; $stmt = $conn->stmt_init(); $stmt->prepare($sql); $stmt->bind_param('sss', $username, $password, $key); $stmt->execute(); $stmt->store_result(); ... When the debugger meets line 8 or $stmt->prepare($sql); , 6 same warning tables

问题 Let me preface that I just started learning prepared statements so much of this might just be to much to grasp, but I want to try. I am trying to make a dynamic create function within my DatabaseObject class. The function would take any number of values of potentially any number of the different allowed data types. Unfortunately nothing I have tried has worked. Here is the code. public function create() { $db = Database::getInstance(); $mysqli = $db->getConnection(); //array of escaped values

问题 I've been trying to create a class that handles queries from different Classes that create different objects, for example. Class Employees, Class Customers, Class Sales I'd like to pass a SQL query via the constructor derived from JTextField values (to the query class, "Database"). For example, from two different classes: new Database (SELECT PRODUCT FROM SALES WHERE DATE = YESTERDAY); new Database (SELECT FULLNAMES FROM CUSTOMER WHERE ADDRESS = NEWYORK); The problem I'm facing is when it