position

I am using JQPlot and I have many graphs on one HTML page. Each of the graphs has the same legend. My question is this: Is it possible to display a legend totally outside of the graph with its own position on the HTML page or in its own div? legend:{ show:true, renderer: $.jqplot.EnhancedLegendRenderer, location: 's' , placement : "outside", marginTop : "30px", rendererOptions: { numberRows: 1 } }, You can use placement : "outside" like in the above code. And you can move it using marginTop,marginBottom,marginRight,marginLeft properties. Maybe you could hide the legend of the 2nd to the last

I know that min-height: 100% will only work to take up a minimum of 100% of its parent element's height if the parent element has some numeric value for height, but what if I have a few nested divs and I want them all to have a min-height of 100%? I tried min-height:inherit but that didn't work either? I know I can probably solve this problem with JavaScript by simply checking the browser height value on document load and then assigning that to the min-height property of my nested divs, but I'd like to know if it would be possible to solve this with just css? Edit : I should also mention that

This question already has an answer here : how to get all the numbers greater than x with positions? (1 answer) In R: I have a vector and want to find the position of the first value that is greater than 100. # Randomly generate a suitable vector set.seed(0) v <- sample(50:150, size = 50, replace = TRUE) min(which(v > 100)) Ant Most answers based on which and max are slow (especially for long vectors) as they iterate through the entire vector: x>100 evaluates every value in the vector to see if it matches the condition which and max / min search all the indexes returned at step 1. and find the

1、position 给父元素设置position:relative，左边的子元素设置position:absulote，且左边元素的高度为100%。CSS代码如下： /*position*/ .left{ height: 100%; width: 100px; background: aqua; position: absolute; } .right{ width: 300px; margin-left: 110px; background: antiquewhite; } .parent{ position: relative; } 　　 2、margin负值 这种方法的原理其实是把子元素的实际高度撑开的很多，父元素overflow：hidden起到一个遮罩作用，来保持左右两侧元素高度相等的。css代码如下 /*margin负值*/ .parent{ overflow: hidden; } .left,.right{ margin-bottom: -5000px; padding-bottom: 5000px; } .left{ float: left; background: aqua; } .right{ float: right; background: antiquewhite; } 　　 3、flex布局 flex布局的中align

We have a scrollable div that has CSS hieght:40px; . Inside it are multiple LI height:20px <div id="#scroller"> <li title="I1">item1</li> <li title="I2">item2</li> <li title="I3">item3</li> <li title="I4">item4</li> <li title="I5">item5</li> <li title="I6">item6</li> <li title="I7">item7</li> <li title="I8">item8</li> <li title="I9">item9</li> </div> When the user scrolls I want to trigger a script that determines the first of the two elements which is visible. The div scroll is designed to snap to elements. So if you scroll down and item3 and item 4 are visible how do I fund out that item 3