pointers

Argument passing by reference to pointer problem

。_饼干妹妹 提交于 2020-12-28 21:09:29
问题 Every time I try to compile my code I get error: cannot convert parameter 1 from 'int *' to 'int *&' The test code looks like this: void set (int *&val){ *val = 10; } int main(){ int myVal; int *pMyVal = new int; set(&myVal); // <- this causes trouble set(pMyVal); // <- however, this doesn't } I'd like to call that function in a single shot without creating a pointer somewhere only to pass it. And as pointers don't have constructors, something like this can't be done: set(int*(&myVal)); Is

Argument passing by reference to pointer problem

假装没事ソ 提交于 2020-12-28 21:08:53
问题 Every time I try to compile my code I get error: cannot convert parameter 1 from 'int *' to 'int *&' The test code looks like this: void set (int *&val){ *val = 10; } int main(){ int myVal; int *pMyVal = new int; set(&myVal); // <- this causes trouble set(pMyVal); // <- however, this doesn't } I'd like to call that function in a single shot without creating a pointer somewhere only to pass it. And as pointers don't have constructors, something like this can't be done: set(int*(&myVal)); Is

Argument passing by reference to pointer problem

时光怂恿深爱的人放手 提交于 2020-12-28 21:08:31
问题 Every time I try to compile my code I get error: cannot convert parameter 1 from 'int *' to 'int *&' The test code looks like this: void set (int *&val){ *val = 10; } int main(){ int myVal; int *pMyVal = new int; set(&myVal); // <- this causes trouble set(pMyVal); // <- however, this doesn't } I'd like to call that function in a single shot without creating a pointer somewhere only to pass it. And as pointers don't have constructors, something like this can't be done: set(int*(&myVal)); Is

Argument passing by reference to pointer problem

两盒软妹~` 提交于 2020-12-28 21:08:03
问题 Every time I try to compile my code I get error: cannot convert parameter 1 from 'int *' to 'int *&' The test code looks like this: void set (int *&val){ *val = 10; } int main(){ int myVal; int *pMyVal = new int; set(&myVal); // <- this causes trouble set(pMyVal); // <- however, this doesn't } I'd like to call that function in a single shot without creating a pointer somewhere only to pass it. And as pointers don't have constructors, something like this can't be done: set(int*(&myVal)); Is

Pointer passed to function changes unexpectedly

萝らか妹 提交于 2020-12-27 06:35:02
问题 I'm designing a preloader-based lock tracing utility that attaches to Pthreads, and I've run into a weird issue. The program works by providing wrappers that replace relevant Pthreads functions at runtime; these do some logging, and then pass the args to the real Pthreads function to do the work. They do not modify the arguments passed to them, obviously. However, when testing, I discovered that the condition variable pointer passed to my pthread_cond_wait() wrapper does not match the one

Pointer passed to function changes unexpectedly

老子叫甜甜 提交于 2020-12-27 06:34:58
问题 I'm designing a preloader-based lock tracing utility that attaches to Pthreads, and I've run into a weird issue. The program works by providing wrappers that replace relevant Pthreads functions at runtime; these do some logging, and then pass the args to the real Pthreads function to do the work. They do not modify the arguments passed to them, obviously. However, when testing, I discovered that the condition variable pointer passed to my pthread_cond_wait() wrapper does not match the one

Pointer passed to function changes unexpectedly

只愿长相守 提交于 2020-12-27 06:34:46
问题 I'm designing a preloader-based lock tracing utility that attaches to Pthreads, and I've run into a weird issue. The program works by providing wrappers that replace relevant Pthreads functions at runtime; these do some logging, and then pass the args to the real Pthreads function to do the work. They do not modify the arguments passed to them, obviously. However, when testing, I discovered that the condition variable pointer passed to my pthread_cond_wait() wrapper does not match the one

Why does it seem that func is the same as &func in C? [duplicate]

杀马特。学长 韩版系。学妹 提交于 2020-12-26 03:50:55
问题 This question already has answers here : How does dereferencing of a function pointer happen? (5 answers) Closed last month . According to the GNU C manual, functions can be called using function pointers like so: func (j); /* (*func) (j); would be equivalent. */ So my reasoning here is: func itself is a pointer to the func(int) function. When you call func(j) , you are implicitly accessing the value of the pointer func (you are moving to the memory location where func is), in the same way as

C# function pointer?

两盒软妹~` 提交于 2020-12-24 05:07:22
问题 I'm having a problem with C#, I'd like to get a pointer of a method in my code, but it seems impossible. I need the pointer of the method because I want to no-op it using WriteProcessMemory. How would I get the pointer? Example code main() { function1(); function2(); } function1() { //get function2 pointer //use WPM to nop it (I know how, this is not the problem) } function2() { Writeline("bla"); //this will never happen because I added a no-op. } 回答1: I know this is very old, but an example

C/C++ Pointer to a POD struct also points to the 1st struct member

邮差的信 提交于 2020-12-21 03:59:35
问题 Can I assume that a C/C++ struct pointer will always point to the first member? Example 1: typedef struct { unsigned char array_a[2]; unsigned char array_b[5]; }test; //.. test var; //.. In the above example will &var always point to array_a? Also in the above example is it possible to cast the pointer to an unsigned char pointer and access each byte separately? Example 2: function((unsigned char *)&var,sizeof(test)); //... //... void function(unsigned char *array, int len){ int i; for( i=0;