php-8

问题 I just have migrated to php v8.0.0 with XAMPP v3.2.4. But Xdebug is not working. Execution is not stopping on breakpoints. My installation instructions- Download php_xdebug-3.0.2-8.0-vs16-x86_64.dll Move the downloaded file to \xampp\php\ext Update D:\xampp\php\php.ini and change the line zend_extension = \xampp\php\ext\php_xdebug-3.0.2-8.0-vs16-x86_64.dll Restart the webserver Here is the installation summary- Xdebug installed: 3.0.2 Server API: Apache 2.0 Handler Windows: yes Compiler: MS

问题 I use the guzzlehttp/guzzle package in Laravel 8 . After upgrading to PHP 8 , I get: Symfony\Component\ErrorHandler\Error\FatalError: Invalid opcode 117/2/0. in file ../vendor/defuse/php-encryption/src/Core.php on line 412 composer.json: "require": { "php": "^8.0", "doctrine/dbal": "^2.12.1", "fideloper/proxy": "^4.4", "fruitcake/laravel-cors": "^2.0", "guzzlehttp/guzzle": "^7.2", "laravel/framework": "^8.12", "laravel/passport": "^10.0", "laravel/tinker": "^2.5", "ext-json": "*" }, "require

问题 I use the guzzlehttp/guzzle package in Laravel 8 . After upgrading to PHP 8 , I get: Symfony\Component\ErrorHandler\Error\FatalError: Invalid opcode 117/2/0. in file ../vendor/defuse/php-encryption/src/Core.php on line 412 composer.json: "require": { "php": "^8.0", "doctrine/dbal": "^2.12.1", "fideloper/proxy": "^4.4", "fruitcake/laravel-cors": "^2.0", "guzzlehttp/guzzle": "^7.2", "laravel/framework": "^8.12", "laravel/passport": "^10.0", "laravel/tinker": "^2.5", "ext-json": "*" }, "require

问题 after updating my mac to php 8 laravel app stopped working, this is the error I'm getting: Deprecated: Method ReflectionParameter::getClass() is deprecated in /Users/.../Sites/.../vendor/laravel/framework/src/Illuminate/Container/Container.php on line 871 Deprecated: Method ReflectionParameter::getClass() is deprecated in /Users/.../Sites/.../vendor/laravel/framework/src/Illuminate/Container/Container.php on line 945 Deprecated: Method ReflectionParameter::getClass() is deprecated in /Users/.

问题 I use the guzzlehttp/guzzle package in Laravel 8 . After upgrading to PHP 8 , I get: Symfony\Component\ErrorHandler\Error\FatalError: Invalid opcode 117/2/0. in file ../vendor/defuse/php-encryption/src/Core.php on line 412 nginx config: server { listen 80; root /var/www/finex_production/public/; index index.php; server_name ff.loc; location / { try_files $uri $uri/ /index.php?$query_string; } location ~ \.php$ { include snippets/fastcgi-php.conf; fastcgi_pass unix:/var/run/php/php8.0-fpm.sock

问题 I use the guzzlehttp/guzzle package in Laravel 8 . After upgrading to PHP 8 , I get: Symfony\Component\ErrorHandler\Error\FatalError: Invalid opcode 117/2/0. in file ../vendor/defuse/php-encryption/src/Core.php on line 412 nginx config: server { listen 80; root /var/www/finex_production/public/; index index.php; server_name ff.loc; location / { try_files $uri $uri/ /index.php?$query_string; } location ~ \.php$ { include snippets/fastcgi-php.conf; fastcgi_pass unix:/var/run/php/php8.0-fpm.sock

问题 Good afternoon. When an attempt is made to debug the script on PHP 8, PhpStorm reports that there is no connection with version 3 xdebug. Works with all versions below 3. I tried to change the parameters of xdebug.remote_{host, port} to xdebug.client_{host, port} but also did not help. 回答1: Xdebug 3 will be fully supported in PhpStorm 2020.3 version only, which is currently in EAP stage (Early Access Program) and will be released in about 1 month time. It is already supported in the most

问题 Good afternoon. When an attempt is made to debug the script on PHP 8, PhpStorm reports that there is no connection with version 3 xdebug. Works with all versions below 3. I tried to change the parameters of xdebug.remote_{host, port} to xdebug.client_{host, port} but also did not help. 回答1: Xdebug 3 will be fully supported in PhpStorm 2020.3 version only, which is currently in EAP stage (Early Access Program) and will be released in about 1 month time. It is already supported in the most

问题 This question already has answers here : Reference — What does this symbol mean in PHP? (20 answers) Closed 24 days ago . Could you please explain what does the operator ?-> do in PHP, since I have this piece of code: $drive = $objDrive?->func?->getDriver()?->value; 回答1: For the moment, it's just a proposal, you can find it enter link description here. It's the NullSafe Operator , it returns null in case you try to invoke functions or get values from null ... Example $objDrive = null; $drive

问题 Can I allow two different types using type hinting? E.g. parameter $requester could be either of User or File : function log (User|File $requester) { } 回答1: Academically, this is called a type union. Union types in PHP You can cheat by creating interfaces, parent types, etc, as mentioned in other answers, but what's the point, apart for adding complexity and LoCs to your project? Plus, that can't work for scalar types as you can't extend/implement a scalar type. Instead of making the code