pattern-matching

Can I make Pattern Password Screen Locker android app

烈酒焚心 提交于 2019-12-03 16:35:10
Has anyone got experience with developing an application to replace the default lock screen? I've been told it is not possible, however this application manages it. Any tutorials or guidance you know of would be appreciated. KBusc 100% possible. Here are some links to get you started. Android App and Pattern Lock Screen Android Lock Screen Widget Developing a custom lock screen Try this one: lockscreenswitchwidget You can implement deviceAdminReciever to use device locks and all please have a look at this it explains everything about locks setting passwords..... Update: Use this library Link

Match a Query to a Regular Expression in SQL?

别等时光非礼了梦想. 提交于 2019-12-03 16:01:45
I'm trying to find a way to match a query to a regular expression in a database. As far as I can tell (although I'm no expert), while most DBMS like MySQL have a regex option for searching, you can only do something like: Find all rows in Column 1 that match the regex in my query. What I want to be able to do is the opposite, i.e.: Find all rows in Column 1 such that the regex in Column 1 matches my query. Simple example - say I had a database structured like so: +----------+-----------+ | Column 1 | Column 2 | +----------+-----------+ | [a-z]+ | whatever | +----------+-----------+ | [\w]+ |

How do I used matched arguments in elixir functions

我只是一个虾纸丫 提交于 2019-12-03 15:38:21
Say I have two use cases for a function. Do something with users that have a subscription and something with users that don't have a subscriptions. def add_subscription(subscription_id, %User{subscription: nil}) # Do something with user here. And def add_subscription(subscription_id, user) How do I do pattern matching like this and also still use the user in the first function? Thanks! You can bind the function argument to a variable: def add_subscription(subscription_id, %User{subscription: nil} = user) The convention is to assign after the pattern match: # Do This def foo(%User{subscription:

haskell parse error in pattern for n+k pattern

久未见 提交于 2019-12-03 15:33:28
问题 I have started working my way through Erik Meijer's 13-part lectures (and Graham Hutton's slides) to learn Haskell. On the slides for Chapter 4, on page 13, it introduces the pattern-matching syntax for n+k patterns. In particular, it says: As in mathematics, functions on integers can be defined using n+k patterns, where n is an integer variable and k>0 is an integer constant. pred :: Int -> Int pred (n+1) = n When I tried this on my own in the REPL I get an error message: *Main> let mypred

detect object in image,how they did it. I think it is unbelieveable

老子叫甜甜 提交于 2019-12-03 15:18:02
问题 alt text http://pascallin.ecs.soton.ac.uk/challenges/VOC/voc2007/examples/person_06.jpg alt text http://pascallin.ecs.soton.ac.uk/challenges/VOC/voc2007/examples/dog_08.jpg alt text http://pascallin.ecs.soton.ac.uk/challenges/VOC/voc2007/examples/sheep_07.jpg this picture is download from a website,the team show their research result like this. I want to know how they did it, some body know tell me I will be appreciate. thank you 回答1: Based on their publications, one can conclude they use SVM

Scala Map pattern matching

人走茶凉 提交于 2019-12-03 14:27:50
How to do pattern matching on a Map in Scala ? A (non working) attempt includes, Map("a"->1, "b"->2, "c"->3) match { case Map(a,b,_*) => a } which errs with value Map is not a case class, nor does it have an unapply/unapplySeq member case Map(a,b,_*) => a The error is indicative enough, yet how to enrich Map with an unapply method for pattern matching ? Many Thanks Update Following @Paul's comment, a neater use case may be like this, Map("a"->1, "b"->2, "c"->3) match { case Map("b"->2,_*) => "222" } namely, in this case, if map contains key b that maps onto value 2 . Most easy way is tramsform

Any software for pattern-matching and -rewriting source code? [closed]

大憨熊 提交于 2019-12-03 14:09:03
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 3 years ago . I have some old software (in a language that's not dead but is dead to me ;-)) that implements a basic pattern-matching and -rewriting system for source code. I am considering resurrecting this code, translating it into a modern language, and open-sourcing the project as a refactoring power-tool. Before I go

Pattern matching a regex pattern in Haskell

丶灬走出姿态 提交于 2019-12-03 13:59:28
In Scala, I have a regular expression pattern match like this: val Regex = """(\d{4})/(\d{2})/(\d{2})""".r val Regex(year, month, day) = "2013/01/06" The result is: year: String = 2013 month: String = 01 day: String = 06 How can I accomplish a similar result in Haskell? In other words, can I match a regular expression containing groups and assign the groups to identifiers? This works for me: Prelude Text.Regex.Posix> "2013/01/06" =~ "([0-9]+)/([0-9]*)/([0-9]*)" :: (String,String,String,[String]) ("","2013/01/06","",["2013","01","06"]) (ghci 7.4.2 on OS X) Ralph Expanding on Chris's answer ,

Performance difference between pattern matching and if-else

99封情书 提交于 2019-12-03 13:58:57
Why can OCaml generate efficient machine code for pattern matching and not for if-else tests? I was reading Real World OCaml and I came across this section where they compared the performance of pattern matching to the performance of if-else tests. It turned out that pattern matching in their example was significantly faster than if-else tests. Even though the code doesn't utilize any special pattern match cases that would not be possible with if-else tests, it just compares integers. They ascribe compiler optimization for pattern matching as the reason for the performance difference. The

Can multiple dispatch be achieved in Haskell with pattern matching on type classes?

只愿长相守 提交于 2019-12-03 13:29:05
问题 This is a question about multiple dispatch in Haskell. Below I use the term "compliant to [type class]" to mean "has type which is instance of [type class]", because type classes are often like interfaces, so it's intuitive to think of a concrete thing like an actual Int value as being "compliant" to an interface/type class by virtue of its type implementing whatever is needed to belong to that interface/type class. Consider the example of wanting to make a single exponentiation function that