partial-views

How to pass string into Rails partial?

情到浓时终转凉″ 提交于 2019-12-05 05:58:24
I have a view that is like this: render :partial => 'shared/_address', :locals => {:address => order.bill_address} With a partial that looks like this: <b><%= address.name %></b><br/> <%= raw address.address_lines('<br/>') %><br/> <%= address.city_state_zip %><br/> There are multiple instances of the partial rendered on a page. Instead of having it display address.name, how can I modify my render :partial line so that I am passing on a custom string e.g. "Future Shipping Address" instead of having to use address.name? So the code would look like below: <b>STRING GOES HERE</b><br/> <%= raw

Does Razor ViewEngine cache the rendered HTMLs?

a 夏天 提交于 2019-12-05 04:58:48
I have a 2-level menu item: I have a list of department and each department has a list of stores. I have a Menu, PartialView which iterates through the Model (departments) and builds the menu: @model IEnumerable<Department> <ul> @foreach (var department in Model) { <li> <a href="#">@Model.DepartmentName</a> <ul> @foreach (var store in department.Stores) { <li><a href="some-url">@store.StoreName</a></li> } </ul> </li> } </ul> And this is how I call the Menu PartialView in my _layout.cshtml : @Html.Partial("Shared/_Menu", MyApplicationCache.departments) As you can see I am passing the same model

Display mvc partial view with errors on parent page

大兔子大兔子 提交于 2019-12-05 01:40:46
问题 I have a page with multiple forms, each as a partial. I want to post each partial on submit. If there are errors, I want the validation errors to show in the partial as part of the main page i.e. I don't want to just see the partial on it's own page if there are errors. Am I correct in saying this behavior is only possible with an ajax post? How would I return the model state errors WITHOUT an ajax post, just a normal form post? Edit: Still seeing the partial on it's own page Partial - @using

Rails 3: How do I call a javascript function from a js.erb file

我怕爱的太早我们不能终老 提交于 2019-12-05 00:57:01
问题 Now that I've upgraded to Rails 3, I'm trying to figure out the proper way to separate and reuse pieces of javascript. Here's the scenario I'm dealing with: I have a page with two areas: one with elements that should be draggable, the other with droppables. When the page loads I use jQuery to setup the draggables and droppables. Currently I have the script in the head portion of application.html.erb, which I'm sure is not the right solution but at least works. When I press a button on the

jquery load with asp.net MVC partial view

生来就可爱ヽ(ⅴ<●) 提交于 2019-12-04 22:26:44
问题 I have a partial view and I want to render it in main view using jquery. Here is how I am coding the jQuery: $(document).ready(function() { $("#dvGames").load("/LiveGame/Partial3"); }); where as controller method looks like this: public ActionResult Partial3(DateTime gameDate) { return View("Partial3"); } I dont see anything. I tried <% Html.RenderPartial("Partial3"); %> and it works but I want to filter data in partial view so I am using jquery load method. 回答1: Your controller action

Zend Framework 2 - How to include partial from library

元气小坏坏 提交于 2019-12-04 21:35:47
问题 I wrote a partial which I want to use in several modules. I thought the best way would be to put it into my custom library. But unfortunately I couldn't figure out a way to include this partial without using a very ugly path like: echo $this->partial('/../../../../vendor/myvendor/library/MyVendor/View/Views/FormPartial.phtml' , array(...)); Any ideas how to link to my vendor directory from my view? 回答1: The problem is the resolver can't resolve the path of the view template you had provided.

Using Kendo Grid in PartialView

最后都变了- 提交于 2019-12-04 21:05:47
I have two <section> in the Index view of my MVC application and I want to render two partial views in these sections. There is no problem rendering a Kendo grid to one Index. However, in order to render data on Kendo Grid, could I use the two methods returning Json in the controller as shown below. Could you give me an example how to achieve this? Controller: public ActionResult Index() { return View(); } public ActionResult Issues_Read([DataSourceRequest]DataSourceRequest request) { IQueryable<Issue> issues = db.Issues; DataSourceResult result = issues.ToDataSourceResult(request, c => new

asp.net MVC3 partial view result not updating EditorFor value

蓝咒 提交于 2019-12-04 18:05:42
I have a simple email capture form as part of my home page, however when I return the partial view the model value for the Editor for form is not getting updated: The Model public class Contact { [Key] public int Id { get; set; } [Required] public string Email { get; set; } [NotMapped] public string Message { get; set; } } The Views @model TestApp.Models.Contact @{ ViewBag.Title = "Home Page"; } <script src="@Url.Content("~/Scripts/jquery.validate.min.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.validate.unobtrusive.min.js")" type="text/javascript"><

using partial view on asp.net core razor pages

牧云@^-^@ 提交于 2019-12-04 17:42:32
I am developing a project that runs on asp.net core 2 razor pages. I need a solution to load a partial view or component to in a RAZOR pages and also I could send come object (some class model or basic string). this is detail pages which I want load partial view into. Using this code : @{ await Html.RenderPartialAsync("Shared/Partial/DeleteModal", Model.DeleteModalModel); } this is my partial view inside <div class="modal fade" id="deleteModal" tabindex="-1" role="dialog"> <div class="modal-dialog" role="document"> <div class="modal-content"> <div class="modal-header bg-red"> <h4 class="modal

ASP.NET MVC Strongly Typed Partial View, gives could not load type error

你离开我真会死。 提交于 2019-12-04 16:09:45
问题 I am attempting to create a strongly typed view with a "MVC View User Control" that is being rendered using Html.RenderPartial(). The top of my ascx file looks like this: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<System.Collections.IEnumerable<string>>" %> There is nothing else on this page, currently. When I execute the app and load the page that renders this control, I get the following error: Could not load type 'System.Web.Mvc.ViewUserControl<System.Collections