parsing

问题 I need to strip out all non standard text characers from a string. I need remove all non ascii and control characters (except line feeds/carriage returns). 回答1: Something like this should do: // For those who need a disclaimer: // This code is meant as a sample to show you how the basic check for non-ASCII characters goes // It will give low performance with long strings that are called often. // Use a TStringBuilder, or SetLength & Integer loop index to optimize. // If you need really

问题 I need to strip out all non standard text characers from a string. I need remove all non ascii and control characters (except line feeds/carriage returns). 回答1: Something like this should do: // For those who need a disclaimer: // This code is meant as a sample to show you how the basic check for non-ASCII characters goes // It will give low performance with long strings that are called often. // Use a TStringBuilder, or SetLength & Integer loop index to optimize. // If you need really

问题 I am trying to access the article content from a website, using beautifulsoup with the below code: site= 'www.example.com' page = urllib2.urlopen(req) soup = BeautifulSoup(page) content = soup.find_all('p') content=str(content) the content object contains all of the main text from the page that is within the 'p' tag, however there are still other tags present within the output as can be seen in the image below. I would like to remove all characters that are enclosed in matching pairs of < >

问题 This question already has answers here : Evaluating a string as a mathematical expression in JavaScript (16 answers) Closed 6 years ago . Is there a simple way, with javascript, to convert the following expression e*((a*(b+c))+d) into something like multiply(e, add(multiply(a, add(b,c)), d)) The expression would be stored in a string. I'm open to any solution that will avoid me to write my own parser (library, buitl-in capabilities, ...) EDIT : I should have precised that I don't actually

问题 I am using boost::split to parse a data file. The data file contains lines such as the following. data.txt 1:1~15 ASTKGPSVFPLAPSS SVFPLAPSS -12.6 98.3 The white space between the items are tabs. The code I have to split the above line is as follows. std::string buf; /*Assign the line from the file to buf*/ std::vector<std::string> dataLine; boost::split( dataLine, buf , boost::is_any_of("\t "), boost::token_compress_on); //Split data line cout << dataLine.size() << endl; For the above line of

问题 I am using boost::split to parse a data file. The data file contains lines such as the following. data.txt 1:1~15 ASTKGPSVFPLAPSS SVFPLAPSS -12.6 98.3 The white space between the items are tabs. The code I have to split the above line is as follows. std::string buf; /*Assign the line from the file to buf*/ std::vector<std::string> dataLine; boost::split( dataLine, buf , boost::is_any_of("\t "), boost::token_compress_on); //Split data line cout << dataLine.size() << endl; For the above line of

问题 The web server works (python flask) but when I go to the website, where the value of animal should be (dog) it shows the variable name animal. (There is more to the code but this is the most simplistic version which is the same concept. Let's say I have these lines of code in my python script running python flask. animal = dog return render_template('index.html', value=animal) and in my HTML <h3>I like the animal: {{ value }}<h3> but rather than displaying 'dog' it displays the variable name

问题 How can I parse a JDBC URL (oracle or sqlserver) to get the hostname, port, and database name. The formats of the URL are different. 回答1: Start with something like this: String url = "jdbc:derby://localhost:1527/netld;collation=TERRITORY_BASED:PRIMARY"; String cleanURI = url.substring(5); URI uri = URI.create(cleanURI); System.out.println(uri.getScheme()); System.out.println(uri.getHost()); System.out.println(uri.getPort()); System.out.println(uri.getPath()); Output from the above: derby

问题 How can I parse a JDBC URL (oracle or sqlserver) to get the hostname, port, and database name. The formats of the URL are different. 回答1: Start with something like this: String url = "jdbc:derby://localhost:1527/netld;collation=TERRITORY_BASED:PRIMARY"; String cleanURI = url.substring(5); URI uri = URI.create(cleanURI); System.out.println(uri.getScheme()); System.out.println(uri.getHost()); System.out.println(uri.getPort()); System.out.println(uri.getPath()); Output from the above: derby

问题 This question already has answers here : How do you split a list into evenly sized chunks? (63 answers) Closed 4 years ago . I'm very new to python and was wondering what the most pythonic/easy way is to split a string into a list with parts of N characters. I've come across this: >>>s = "foobar" >>>list(s) ['f', 'o', 'o', 'b', 'a', 'r'] which is how I can turn a string into a list of characters, but what I would want is to have a method that would look like this: >>>def splitInNSizedParts(s,