parseint


Why does parseInt('dsff66',16) return 13?

亡梦爱人 提交于 2020-01-12 06:33:08
问题 today I stumbled on a strange (in my opinion) case in JavaScript. I passed a non-hexadecimal string to the parseInt function with the base of 16 and...I got the result. I would expect the function to throw some kind of exception or at least return NaN, but it succeeded parsing it and returned an int. My call was: var parsed = parseInt('dsff66', 16); // note the 's' in the first argument document.write(parsed); and the result was: 13 . I noticed that it "stops" parsing with the first character

Converting String Mac Address to Hex

泄露秘密 提交于 2020-01-06 07:56:14
问题 I am trying to convert a string macaddress to hex value. I got a C# code which does the same thing but when I use the java code it gives me negative values. as in the C# code returns signed integer but how do i do the same in Java following is part of my code Integer hex = Integer.parseInt(MacAddress.subString(0,2), 16 ); MacAddress[0] = hex.byteValue(); i get something like 148 on the c# code and java returns -148 how can I sort this out thanks UPDATE and I just realised that my c# code

Checking if a variable is an integer in javascript

有些话、适合烂在心里 提交于 2019-12-29 08:47:05
问题 I made a form where the user inputs values for width and height that they want for the pop up window to be. I am using window.open for that. So I think I need to check if the values for width and height are integer. I have a function that checks that a variable is an integer that is... function isInteger(possibleInteger) { return !isNaN(parseInt(possibleInteger)); } but I don't know how to call this function to the width and height function to check if the user inputted an integer. Can any

JavaScript parseInt is giving me wrong number, what I'm doing wrong?

折月煮酒 提交于 2019-12-29 01:51:05
问题 So, for parseInt('10152547376283911', 10) I'm expecting 10152547376283911, but I'm getting 10152547376283912. What I'm doing wrong? 回答1: Javascript native numbers do not have enough precision (significant digits) to hold the number you are expecting. See the question What JavaScript library can I use to manipulate big integers? for suggestions on how to deal with this problem. Depending on your application, you may actually be able to use strings instead of numbers (for example, if your

I want to be able to convert numbers into text according to the ASCII decimal table

一曲冷凌霜 提交于 2019-12-25 08:23:54
问题 I am trying to make it so that I can take individual three-character substrings and convert them to integers under the conditions tht the length of the String is a multiple of three. The integers into which the partioned substrings are converted are supposed to function as relative positions in an array that contains all the printing characters of the ASCII table. String IntMessage = result.toString(); if { (IntMessage.substring(0,1)=="1" && IntMessage.length()%3==0) for(j=0;j < IntMessage

Is using parseInt extraenous if unnecessary?

懵懂的女人 提交于 2019-12-25 07:40:09
问题 I am a beginner to coding and JavaScript but I am doing a practice exercise and I came across something I am unsure about. var nameLength = parseInt(fullName.length); var nameLength = fullName.length; I used the first line not even thinking it would already be an integer, so should I still have included the parseInt or not? 回答1: Yes, remove var nameLength = parseInt(fullName.length); Below is your explanation: The parseInt() method in JavaScript is used to turn the integer value of a string

NumberFormatException for valid number String

╄→尐↘猪︶ㄣ 提交于 2019-12-25 06:31:05
问题 I'm making a program that needs to receive data over the internet. It's doing so using DatagramSockets and receiving DatagramPackets. This all works fine, and the byte array it receives is the exact one I would expect. However, when I try to convert the byte array to a string, and subsequently to an integer, very strange things happen. Running the code below gives a NumberFormatException on the parseInt line: String length = new String(data, 1, data.length-1); System.out.println("length = "

NumberFormatException for valid number String

眉间皱痕 提交于 2019-12-25 06:30:06
问题 I'm making a program that needs to receive data over the internet. It's doing so using DatagramSockets and receiving DatagramPackets. This all works fine, and the byte array it receives is the exact one I would expect. However, when I try to convert the byte array to a string, and subsequently to an integer, very strange things happen. Running the code below gives a NumberFormatException on the parseInt line: String length = new String(data, 1, data.length-1); System.out.println("length = "

你不知道的parseInt

不打扰是莪最后的温柔 提交于 2019-12-24 06:29:25
首先,请允许我抄袭一段你知道的parseInt 以下节选自 parseInt - JavaScript | MDN 实际上你连这些基础都没掌握 概述 parseInt() 函数将给定的字符串以指定基数(radix/base)解析成为整数。 语法 1 parseInt(string, radix); 参数 string 要被解析的值。如果参数不是一个字符串,则将其转换为字符串。字符串开头的空白符将会被忽略。 radix 一个2到36之间的整数值,用于指定转换中采用的基数。比如参数"10"表示使用我们通常使用的十进制数值系统。 总是指定该参数 可以消除阅读该代码时的困惑并且保证转换结果可预测。当忽略该参数时,不同的实现环境可能产生不同的结果。 描述 parseInt 顶级函数,没有与任何对象关联。 parseInt 函数将第一个参数(字符串)解析并试图返回一个整数或者 NaN (Not a Number)。如果结果不是 NaN ,那么返回值是把第一个参数看作是radix参数指定的进制下的数,然后把它转换成十进制的整数。例如: radix 参数为10 将会把第一个参数看作是一个数的十进制表示,8 对应八进制,16 对应十六进制,等等。基数大于 10 时,用字母表中的字母来表示大于 9 的数字。例如十六进制中,使用 A 到 F。 如果 parseInt 遇到了不属于 radix

java.lang.NumberFormatException: Invalid int: “3546504756”, what does this error mean?

核能气质少年 提交于 2019-12-24 00:16:57
问题 I'm creating an Android app, and I'm reading some coordinates from a text file. I'm using Integer.parseInt(xCoordinateStringFromFile) to convert the X coordinates to integers, and in the same way with the Y coordinates. When I run the app, I get an error on that line, which looks like this: BridgeData data = new BridgeData( elements[0], elements[1], Integer.parseInt(elements[2]), Integer.parseInt(elements[3]), Integer.parseInt(elements[4]), new GeoPos(Integer.parseInt(elements[5].split(",")[0

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