parseint

Converting string into array of ints ex String st = “1 2 3 4 5” into ar=[1,2,3,4,5]

只愿长相守 提交于 2021-02-04 21:39:54
问题 I am reading in a string, as an entire line of numbers, separated by spaces, ie ie 1 2 3 4 5 . I want to convert them into an array of integers, so that I can manipulate them. But this code doesn't work. It says incompatible types. String str = br.readLine(); int[] array = new int[4]; StringTokenizer tok = new StringTokenizer(str," ", true); boolean expectDelim = false; int i = 0; while (tok.hasMoreTokens()) { String token = tok.nextToken(); ar[i] = Integer.parseInt(token); i++; } 回答1: If you

Converting string into array of ints ex String st = “1 2 3 4 5” into ar=[1,2,3,4,5]

萝らか妹 提交于 2021-02-04 21:36:41
问题 I am reading in a string, as an entire line of numbers, separated by spaces, ie ie 1 2 3 4 5 . I want to convert them into an array of integers, so that I can manipulate them. But this code doesn't work. It says incompatible types. String str = br.readLine(); int[] array = new int[4]; StringTokenizer tok = new StringTokenizer(str," ", true); boolean expectDelim = false; int i = 0; while (tok.hasMoreTokens()) { String token = tok.nextToken(); ar[i] = Integer.parseInt(token); i++; } 回答1: If you

Integer.parseInt() and Integer.toString() runtime

你。 提交于 2021-01-05 07:45:10
问题 Would the runtime of Integer.parseInt(String i) and Integer.toString(int i) both be O(n)? 回答1: Yes both of them Integer.parseInt("1000") and Integer.toString(1000) have time complexity O(N) The internal code of Integer.parseInt("1000") reads the the strings char by char and covert to decimal in while loop The internal code of Integer.toString(1000) reads the integers and convert every digit to char and stores in byte[] buf then creates new string from the byte array Here is the code of

Why am I getting weird result using parseInt in node.js? (different result from chrome js console)

谁都会走 提交于 2020-08-26 21:32:41
问题 I just noticed that: //IN CHROME JS CONSOLE parseInt("03010123"); //prints: 3010123 //IN NODE.JS parseInt("03010123"); //prints: 790611 Since both are based on V8, why same operation yielding different results??? 回答1: Undefined behavior occurs when the string being passed to parseInt has a leading 0, and you leave off the radix parameter. An integer that represents the radix of the above mentioned string. Always specify this parameter to eliminate reader confusion and to guarantee predictable

Check whether the entered value is actually a number. If not, you will see an error message under the division

天涯浪子 提交于 2020-08-11 18:47:24
问题 I want to create in jquery a web page with two text boxes, a button and a div with dummy text. After clicking the button, the height and width of the div is set with the values entered in text boxes. Make a submitted values a number using the parseInt function. Then check whether the entered value is actually a number. If not, you will see an error message under the division. My question is, how can i use function parseInt and also function isNaN in this case and get error message ? Thanks

Check whether the entered value is actually a number. If not, you will see an error message under the division

情到浓时终转凉″ 提交于 2020-08-11 18:46:49
问题 I want to create in jquery a web page with two text boxes, a button and a div with dummy text. After clicking the button, the height and width of the div is set with the values entered in text boxes. Make a submitted values a number using the parseInt function. Then check whether the entered value is actually a number. If not, you will see an error message under the division. My question is, how can i use function parseInt and also function isNaN in this case and get error message ? Thanks

How can I overcome ArrayIndexOutOfBoundException for Integer.parseInt(args[0])?

▼魔方 西西 提交于 2020-07-04 02:47:57
问题 I've seen below code in one of the video tutorial.There its executes fine but while I'm trying to execute in my system, it is compiling fine but I'm getting runtime error saying, Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0 class Test13 { public static void main(String[] args) { int i = Integer.parseInt(args[0]); System.out.println(i); } } Can someone please guide me what's wrong with this code and how to rectify? Thanks in advance! 回答1:

How can I overcome ArrayIndexOutOfBoundException for Integer.parseInt(args[0])?

杀马特。学长 韩版系。学妹 提交于 2020-07-04 02:47:01
问题 I've seen below code in one of the video tutorial.There its executes fine but while I'm trying to execute in my system, it is compiling fine but I'm getting runtime error saying, Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0 class Test13 { public static void main(String[] args) { int i = Integer.parseInt(args[0]); System.out.println(i); } } Can someone please guide me what's wrong with this code and how to rectify? Thanks in advance! 回答1:

Convert string to either integer or float in javascript

浪子不回头ぞ 提交于 2020-05-15 05:45:08
问题 Is there a straightforward way to parse a string to either integer or float if I don't know if the variable is integer-number-like or decimal-number-like? a = '2'; // => parse to integer b = '2.1'; // => parse to float c = '2.0'; // => parse to float d = 'text'; // => don't parse EDIT: It seems my question lacked the necessary context: I want to do some calculations without losing the original format (Original format thereby means integer vs. float. I don't care about the original number of

js/数值

…衆ロ難τιáo~ 提交于 2020-04-04 20:05:47
1、toString(数字转字符串)   toString方法可以接受一个参数,表示输出的进制。如果省略这个参数,默认将数值转成十进制的字符串;否则就根据参数指定的进制,将一个数字转化成某个进制的字符串   toString 方法只能将十进制的数,转为其他进制的字符串。如果要将其他进制的数,转回十进制,需要使用 parseInt 方法 。   ( 10 ).toString( )  // "10"   ( 10 ).toString( 2 )  // "1010"   ( 10 ).toString( 8 )  // "12"   ( 10 ).toString( 16 )  // "a"   10["toString"]( 2 )  // "1010"   注意: 上面代码中,数字一定要放在括号里,这样表明后面的点表示调用对象属性。如果不加括号,这个点会被 JavaScript 引擎解释成小数点,从而报错。 2、toFixed(保留数字小数点后几位)   toFixed( )方法将数字转成指定位数的小数的字符串   由于浮点数的原因,小数 5 的四舍五入是不确定的,使用的时候必须小心。   ( 10 ).toFixed( 2 )  // "10.00"   ( 10.005 ).toFixed( 2 )  // "10.01"   注意: 上面代码中,数字一定要放在括号里