pagination

Laravel: Paginating a query on a view MySQL Error 1140 Mixing of GROUP columns

南楼画角 提交于 2021-01-05 08:45:08
问题 I am trying to do a simple pagination of a query that uses a view: DB::table('vw_myview')->paginate(50) And get this error: SQLSTATE[42000]: Syntax error or access violation: 1140 Mixing of GROUP columns (MIN(),MAX(),COUNT(),...) with no GROUP columns is illegal if there is no GROUP BY clause (SQL: select count(*) as aggregate from vw_myview) Yet when I manually run the query, it works just fine: mysql> select count(*) as aggregate from vw_myview; +-----------+ | aggregate | +-----------+ |

Django pagination with dictionary where key is a list

元气小坏坏 提交于 2021-01-05 05:34:26
问题 I have a dictionary in my views.py file where the values are lists. In my template I have the following html: {% for key, values in my_dict %} <tr> <td colspan="6" class="key">{{ key }}</td> </tr> {% for value in values %} <tr> <td colspan="6" class="value">{{ value }}</td> </tr> {% endfor %} {% endfor %} which prints out the name of the key followed by the list items inside the value. However, I want to be able to paginate the keys such that only 10 keys with their values appear per page. I

Django pagination with dictionary where key is a list

99封情书 提交于 2021-01-05 05:32:56
问题 I have a dictionary in my views.py file where the values are lists. In my template I have the following html: {% for key, values in my_dict %} <tr> <td colspan="6" class="key">{{ key }}</td> </tr> {% for value in values %} <tr> <td colspan="6" class="value">{{ value }}</td> </tr> {% endfor %} {% endfor %} which prints out the name of the key followed by the list items inside the value. However, I want to be able to paginate the keys such that only 10 keys with their values appear per page. I

FastApi pagination error using fastapi-contrib

柔情痞子 提交于 2021-01-04 06:45:48
问题 I'm trying to add pagination to my fastapi project. So I decide to use this: fastapi-contrib I follow the same example there, but for some reason I'm getting this error: type object 'MOrdenesTrabajo' has no attribute 'count' Here is my code, thanks for your help!! route @router.get("/ordenes-trabajo") async def read_ot(pagination: Pagination = Depends(), db: Session =Depends(get_db)): filter_kwargs = {} return await pagination.paginate(serializer_class=OtSerializer.MOrdenesTrabajo, **filter

AWS s3 listobjects with pagination

让人想犯罪 __ 提交于 2020-12-31 14:59:46
问题 I want to implement pagination using aws s3. There are 500 files in object ms.files but i want to retrieve only 20 files at a time and next 20 next time and so on. var params = { Bucket: 'mystore.in', Delimiter: '/', Prefix: '/s/ms.files/', Marker:'images', }; s3.listObjects(params, function(err, data) { if (err) console.log(err, err.stack); else console.log(data); }); 回答1: Came across this while looking to list all of the objects at once, if your response is truncated it gives you a flag

AWS s3 listobjects with pagination

主宰稳场 提交于 2020-12-31 14:57:49
问题 I want to implement pagination using aws s3. There are 500 files in object ms.files but i want to retrieve only 20 files at a time and next 20 next time and so on. var params = { Bucket: 'mystore.in', Delimiter: '/', Prefix: '/s/ms.files/', Marker:'images', }; s3.listObjects(params, function(err, data) { if (err) console.log(err, err.stack); else console.log(data); }); 回答1: Came across this while looking to list all of the objects at once, if your response is truncated it gives you a flag

AWS s3 listobjects with pagination

拟墨画扇 提交于 2020-12-31 14:56:39
问题 I want to implement pagination using aws s3. There are 500 files in object ms.files but i want to retrieve only 20 files at a time and next 20 next time and so on. var params = { Bucket: 'mystore.in', Delimiter: '/', Prefix: '/s/ms.files/', Marker:'images', }; s3.listObjects(params, function(err, data) { if (err) console.log(err, err.stack); else console.log(data); }); 回答1: Came across this while looking to list all of the objects at once, if your response is truncated it gives you a flag

AWS s3 listobjects with pagination

好久不见. 提交于 2020-12-31 14:55:48
问题 I want to implement pagination using aws s3. There are 500 files in object ms.files but i want to retrieve only 20 files at a time and next 20 next time and so on. var params = { Bucket: 'mystore.in', Delimiter: '/', Prefix: '/s/ms.files/', Marker:'images', }; s3.listObjects(params, function(err, data) { if (err) console.log(err, err.stack); else console.log(data); }); 回答1: Came across this while looking to list all of the objects at once, if your response is truncated it gives you a flag

Spring Data JPA Pagination (Pageable) with Dynamic Queries

笑着哭i 提交于 2020-12-29 05:16:04
问题 I have a simple query as follows "select * from USERS". I also use Pageable to enable pagination. This query may have optional predicates based on the given parameters being null or not. For example if "code" parameter is given and not null, then the query becomes "select * from USERS where code = :code"; As far as I know I cannot implement this using @Query annotation. I can implement a custom repository and use EntityManager to create a dynamic query. However, I am not sure how I can

Mongoid pagination

北城余情 提交于 2020-12-28 18:22:35
问题 I tried @posts = Post.page(params[:page]).per_page(10) and @posts = Post.paginate(:page => 1, :per_page => 10) but neither method works undefined method `page' for Post:Class undefined method `paginate' for Post:Class How do you do pagination with mongoid? 回答1: You should use Kaminari https://github.com/amatsuda/kaminari 回答2: This works fine for me: @posts = Post.paginate(:page => 1, :limit => 10).desc(:_id) desc(:_id) is added so that latest posts could be listed first. 回答3: Still using will