pagination

Pagination in Wagtail

♀尐吖头ヾ 提交于 2020-05-25 06:08:22
问题 I'm fairly new to Wagtail, and I am in the process of creating a site that will have a Resources (blog) section and I'm not sure how to implement pagination so that there are only 5 posts on each page and the user has to click a number (1, 2, 3, etc.) to go to the next page to see the next 5 posts. I have this in my template for the pagination section of the resource/blog index page: <ul class="pagination"> <li><a href="#"><i class="fa fa-angle-left"></i></a></li> <li class="active"><a href="

How to Update State of class component from functional component

北城以北 提交于 2020-05-17 08:46:22
问题 Am Using pagination in my project here pagination component is a functional one am trying to update the currentPage which is state of view statement component.when i debug the code in the initial render i get props as undefined & if i click next the state is not updated immediately it calls the props.tableRow() and then again comes back to pagination updates the state before this details get mapped. need some solution thanks in advance import React ,{useState} from 'react' import { Card,

Facing issues in Chat Pagination

巧了我就是萌 提交于 2020-05-17 06:42:22
问题 I am running the code to load the chats in swift iOS chat application. The problem in chat application is at "query in else{}" in function paginateData() while running the app, the first "query in if{}" runs smoothly as expected, but in other one does not run. I am using firestore database for implementing chat. My goal is to paginate the chats in the chat room. If any more information is required, please let me know. CODE func paginateData() { fetchingMore = true var query: Query! if

Is there a way in laravel 5 to manually decide on pagination numbers?

送分小仙女□ 提交于 2020-05-17 06:03:18
问题 Currently working on a Laravel CRM for someone. I was wondering if there is a way to let the user decide how much results are displayed on a page? Something like this: Where the user decides how many records they wish to see on the page, so that they aren't limited to what is specified in the code. They wish to be able to print the records, so it would be great to have them be able to set the results to show all the records on 1 page when needed. If you have an answer or a link to an article

Is there a way in laravel 5 to manually decide on pagination numbers?

耗尽温柔 提交于 2020-05-17 06:01:31
问题 Currently working on a Laravel CRM for someone. I was wondering if there is a way to let the user decide how much results are displayed on a page? Something like this: Where the user decides how many records they wish to see on the page, so that they aren't limited to what is specified in the code. They wish to be able to print the records, so it would be great to have them be able to set the results to show all the records on 1 page when needed. If you have an answer or a link to an article

how can i implement a pagination in spring jdbcTemplate

末鹿安然 提交于 2020-05-13 11:51:26
问题 here is my following dao implementaion @Override public List<UserAddress> getAddresses(int pageid,int total) { String sql = "select * FROM user_addresses order by id desc limit "+(pageid-1)+","+total; List<UserAddress> userAddresses = jdbcTemplate.query(sql, new RowMapper<UserAddress>() { @Override public UserSessionLog mapRow(ResultSet rs, int rowNum) throws SQLException { UserAddress userAdd = new UserAddress(); userAdd.setId(rs.getInt("id")); userAdd.setId(rs.getString("city")); return

PHP pagination - next/previous button

瘦欲@ 提交于 2020-05-12 02:03:57
问题 I'm trying to learn PHP pagination. So far I can paginate through numbers, but previous/next buttons are appearing on the left and right of each page number, like this. Here is the code I am using to generate pagination: <!DOCTYPE html> <html lang="en"> <head> <title>PHP</title> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, initial-scale=1"> <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css"> <script src="https:/

深入解析当下大热的前后端分离组件django-rest_framework系列四

匆匆过客 提交于 2020-05-08 03:45:21
查漏补缺系列 解析器 request类 django的request类和rest-framework的request类的源码解析 局部视图 from rest_framework.parsers import JSONParser,FormParser class PublishViewSet(generics.ListCreateAPIView): parser_classes = [FormParser,JSONParser] queryset = Publish.objects.all() serializer_class = PublshSerializers def post(self, request, *args, ** kwargs): print( " request.data " ,request.data) return self.create(request, *args, **kwargs) 全局视图 REST_FRAMEWORK= { " DEFAULT_AUTHENTICATION_CLASSES ":[ " app01.service.auth.Authentication " ,], " DEFAULT_PERMISSION_CLASSES ":[ " app01.service.permissions.SVIPPermission " ,], "

Javascript using Fetch and pagination, recursive?

大城市里の小女人 提交于 2020-05-06 17:16:20
问题 Hello I'm new to Javascript and APIs. But I have an excersise where I should get Data from. https://swapi.co/api/planets/ The problem is that it doesn't list all the planets at once so that URL only shows the first 10 entries while https://swapi.co/api/planets/?page=2 shows the next and so on. This is my current code, it works but I don't think I'm going as I'm supposed to so I wonder how you would solve this problem. https://codepen.io/indiehjaerta/pen/QQXVJX var starWarsAPI = new

Javascript using Fetch and pagination, recursive?

北慕城南 提交于 2020-05-06 17:16:06
问题 Hello I'm new to Javascript and APIs. But I have an excersise where I should get Data from. https://swapi.co/api/planets/ The problem is that it doesn't list all the planets at once so that URL only shows the first 10 entries while https://swapi.co/api/planets/?page=2 shows the next and so on. This is my current code, it works but I don't think I'm going as I'm supposed to so I wonder how you would solve this problem. https://codepen.io/indiehjaerta/pen/QQXVJX var starWarsAPI = new