overrun

I am unable to understand the following: In java, long l = 130L; byte b = (byte)l; If I print the value of b, why do I get -126? What is the bit representation of long l? Bytes are signed in Java - so the range of values is -128 to 127 inclusive. The bit pattern for 130 as a long, when simply truncated to 8 bits, is the bit pattern for -126 as a byte. As another example: int x = 255; byte b = (byte) x; // b is now -1 A byte is a sequence of 8 bits, which makes 2^8 cases = 256. Half of them represent negative numbers, which is -128 to -1. Then there is the 0, and about the half, 1 to 127

I have a Label in a GridPane in a TitledPane. I want it to downsize stepwise by 0.05em if it is overrun so the three dots ("Long Labe...") dont show up -> "Long Label" in small. An isOverrun()-method for the Label would be great but JavaFX doesnt supply that and life isn't a wishconcert. So my workarround so far: Bounds tpBounds = tPane.getBoundsInLocal(); Bounds lblBounds = label.getBoundsInLocal(); Double fontSize = 1.0; while (tpBounds.getWidth() < lblBounds.getWidth() && fontSize > 0.5) { fontSize = fontSize-0.05; label.setStyle("-fx-font-size: "+fontSize+"em;"); System.out.println