overriding

For example: (function() { var proxied = window.eval; window.eval = function() { return proxied.apply(this, arguments); }; })(); But this code is not working. T.J. Crowder You can't. (There is a limited way of doing it, but it's quite limited and doesn't maintain the magic that bobince talks about .) eval isn't a real JavaScript function in at least one major implementation (IE's JScript, at least not through IE7; haven't tested the new IE8 version), so right off the bat you're going to run into trouble, because you won't be able to call the original via apply (not that that really matters for

SETUP Win7 64b, R2015b, 16 GB of RAM, CPU i7-2700 The table() is a fundamental Matlab class which is also sealed , hence I cannot subclass it. I want to fix some methods of this class and add new ones. For instance, table.disp() is fundamentally broken, e.g. try NOT disp(table(rand(1e7,1))) , or forget the ; in the command window. The variable takes only 76 MB in RAM but the display is unbuffered and it will stall your system! Can I override methods like table.disp() without writing into matlabroot\toolbox\matlab\datatypes\@table ? Can I extend the table class with a new method under C:\MATLAB

Having #include <iostream> using namespace std; class A { public: virtual void foo() { cout << "A" << endl; } }; class B : public A { public: void foo() { cout << "B" << endl; } }; class C : public B { public: void foo() { cout << "C" << endl; } }; int main() { C c; B* b = &c; b->foo(); return 0; } The output is C , but I expected B . I didn't declare B::foo() with the virtual modifier, so I expect the function call to be determined by the static type (no polymorphism). Why is C::foo() being called? Is it possible to provide a non-virtual function in a derived class, that hides the virtual

I have a base class with an abstract property: public abstract int ID {get;set;} now, I have a subclass, which is XmlSerialized. So, it has: [XmlElement("something")] public override int ID { get { //... } set { //... } } I cannot move the XmlElement attribute to baseclass, since every subclass will have a different xml elementname. Now, when I deserialize this class I get the following error: Member 'Subclass.ID' hides inherited member 'BaseClass.ID', but has different custom attributes. What can I do? Vijay Sirigiri Serialization and deserialization of derived types works when the overridden

I want to understand polymorphism in c# so by trying out several constructs I came up with the following case: class Shape { public virtual void Draw() { Console.WriteLine("Shape.Draw()"); } } class Circle : Shape { public override void Draw() { Console.WriteLine("Circle.Draw()"); } } I understand that in order to send the Draw() message to several related objects, so they can act according to its own implementation I must change the instance to which (in this case) shape is 'pointing' to: Shape shape = new Circle(); shape.Draw(); //OK; This prints: Circle.Draw() But why, when I do this:

I am using a DataContractJsonSerializer and have an issue with the DataMember Name. I made a base class and several derived classes. I need the derived classes because I have different json strings. I want to deserialize the json strings and therefore need different names for the datamembers. I try to change the DataMember name as in the following example: Baseclass: [DataContract] public abstract class BaseClass { [DataMember] public virtual string FirstMethod { get; protected set; } } Derived class: [DataContract] [KnownType(typeof(BaseAccess))] public class DerivedClass { [DataMember(Name=

I have a class structure where I would like some methods in a base class to be accessible from classes derived directly from the base class, but not classes derived from derived classes. According to the Java Language specification it is possible to override access specifications on inherited methods to make them more public, but not more private. For example, this is the gist of what I need to do, but is illegal: // Defines myMethod public class Base { protected void myMethod() {} } // Uses myMethod and then hides it. public class DerivedOne extends Base { @Override private void myMethod(); }

Assume I have a project K K depends lib.jar In lib.jar , there is a class named x.y.z.Foo If i create the same class x.y.z.Foo in K , then in this project when I create a instance of Foo , now will JVM use Foo in K rather than in lib.jar ? And if it's unstable or depends on something , how to make sure that Foo should use K 's version rather than lib.jar ? Java class loading behaviour in a standalone application (at least with no custom classloaders) is stable. Make sure that your k.jar (or path) comes before lib.jar in -cp java arg java -cp k.jar lib.jar ... or add dependencies to /META-INF