overriding

jQuery override $.post function

混江龙づ霸主 提交于 2019-12-01 19:35:43
First of all I apologize for my poor english... Hope someone will understand my question and help me... I'm working on a project using lots of $.post call and I want to improve them by adding the same verification for all of them. I do not want to change all scripts one by one so is there any way to override the $.post function to add the same thing to all of them at the same time ? Or maybe a way to trigger another function on each $.post ? Something like : $.post.each(function(){[...]}); or $('body').on('post', function(){[...]}); Thanks ! EDIT : Finally did it as I wanted ! Here is my code

Where to call base.WndProc() or base.DefWndProc()?

旧时模样 提交于 2019-12-01 19:25:50
问题 I have some questions regarding overriding the WndProc method of a Windows Form / NativeWindow. What exactly is the difference between WndProc and DefWndProc (edit: I thought it is called "DefaultWndProc" before)? I can only override WndProc, but what is DefWndProc for, which I can call anytime? And where to call base.WndProc in my overridden method? Or should I call DefWndProc instead? The following positions came into my mind: protected override void WndProc(ref Message m) { // 1st: I call

How to call a keyboard key press programmatically?

蓝咒 提交于 2019-12-01 19:11:12
Problem : Calling a keyboard key to be pressed, from a piece of C# code but here's the catch: the key-press should not be limited to the process/application but received by the entire operating system, so also when the program is in the background and a different form/program has focus Goal : make a program that locks the state of CapsLock and NumLock Background : I have a laptop, and these 2 keys frustrate me to much, I want to make a application that runs in the background, and that disables CapsLock as soon as it gets accidentally enabled, and for NumLock to never be disabled, also, I want

Why static method of parent class is called when subclass has already overridden it?

邮差的信 提交于 2019-12-01 18:41:39
I am confused by the behaviour of the static method when it is overridden in the subclass. Below is the code: public class SuperClass { public static void staticMethod() { System.out.println("SuperClass: inside staticMethod"); } } public class SubClass extends SuperClass { //overriding the static method public static void staticMethod() { System.out.println("SubClass: inside staticMethod"); } } public class CheckClass { public static void main(String[] args) { SuperClass superClassWithSuperCons = new SuperClass(); SuperClass superClassWithSubCons = new SubClass(); SubClass subClassWithSubCons

What are the rules for virtual function lookup?

北城以北 提交于 2019-12-01 18:16:02
问题 #include <iostream> class base { public: virtual void print (int a) { std::cout << "a: " << a << " base\n"; } virtual void print (int a, int b) { std::cout << "base\n"; } }; class derived : public base { public: virtual void print (double d) { std::cout << "derived\n"; } }; int main () { int i = 10; double d = 10000.0; base *b = new derived (); b->print (i, i); b->print (d); return 0; } The output of this function is: base a: 10000 base Why b->print (d) don't invoke the derived class

How to override Show instance of some basic types in Haskell?

假装没事ソ 提交于 2019-12-01 18:15:11
I'm writting some programs in Haskell, dealing with a lot of basic types like Word32/Word64 etc.. I use ghci to test the functions frequently, see the results in terminal. To be convenient and fast, I always show data in hexadecimal e.g. data Human = M Int | F Int instance Show Human where show M x = printf "man, age %d" x show F x = printf "woman, age %d" x but I want basic types to be showed in hexadecimal (espacially in ghci). I found instance declaration cannot be overridden. and I don't want to warp all of them up like: newtype MyInt = MyInt Int instance Show MyInt where ... It looks a

Overriding ApplicationRecord initialize, bad idea?

余生颓废 提交于 2019-12-01 18:08:24
I am creating a foo obeject like this: @foo = Foo.new(foo_params) @foo.bar = Bar.where(name: "baz").first_or_create But there are other objects that I will need to do this as well. So, I thought of overriding the Foo initialize method to do something like this: class Foo < ApplicationRecord def initialize(*args, BarName) @foo = super @foo.bar = Bar.where(name: BarName).first_or_create end end and call it like this: @foo = Foo.new(foo_params, "baz") But Foo is an ApplicationRecord and it seems that it's not recommended to override the ApplicationRecord initialize method. So how could I do this?

Where to call base.WndProc() or base.DefWndProc()?

孤者浪人 提交于 2019-12-01 17:58:57
I have some questions regarding overriding the WndProc method of a Windows Form / NativeWindow. What exactly is the difference between WndProc and DefWndProc (edit: I thought it is called "DefaultWndProc" before)? I can only override WndProc, but what is DefWndProc for, which I can call anytime? And where to call base.WndProc in my overridden method? Or should I call DefWndProc instead? The following positions came into my mind: protected override void WndProc(ref Message m) { // 1st: I call the base handler at the start, in front of my handling. // Are there disadvantages here? base.WndProc

Class inheritance: recreate base class items (or instance) from a property of the inherited class

陌路散爱 提交于 2019-12-01 17:56:48
I have a class A that is inherited from B. A as some readonly properties that I want to modify from B Hiding those properties with new is not a suitable option, cause the base class has some functions that use its own properties... Can't use the override keyword, cause the properties are not marked as abstract, virtual nor override So I'd like to know whether from the inherited class (B) I can totally recreate the actual instance of my object to access those readonly properties. For example and for a better explaination, for a class inheriting Tuple, if it was possible , I would do something

Why is overriding ActiveRecord::Base.initialize wrong?

混江龙づ霸主 提交于 2019-12-01 17:51:27
In several places, I've seen claims that overriding ActiveRecord::Base.initialize is wrong because it might not always be called: How can I set default values in ActiveRecord? http://blog.dalethatcher.com/2008/03/rails-dont-override-initialize-on.html With never versions of ActiveRecord (3.0+), is this still true? If so, what specifically are the circumstances under which it is not called when one might expect that it would be? It's not that it won't be called, it's that there already is an initialize , in ActiveRecord::Base . Could you call super ? Probably, maybe, in general. Across Rails