overload-resolution

I have a vexing error. type Animal = abstract member Name : string type Dog (name : string) = interface Animal with member this.Name : string = name let pluto = new Dog("Pluto") let name = pluto.Name The last line, specifically "Name" generates a compiler error saying that "the field, constructor or member 'Name' is not defined". The workaround I've used is to write let name = (pluto :> Animal).Name However this is very annoying and creates a lot of visual noise. Is there something one can do in F# to just be able to resolve Name without telling the compiler explicitly that Name is a derived

Consider this code: struct A { void foo() const { std::cout << "const" << std::endl; } private: void foo() { std::cout << "non - const" << std::endl; } }; int main() { A a; a.foo(); } The compiler error is: error: 'void A::foo()' is private`. But when I delete the private one it just works. Why is the public const method not called when the non-const one is private? In other words, why does overload resolution come before access control? This is strange. Do you think it is consistent? My code works and then I add a method, and my working code does not compile at all. NathanOliver When you call

I have the following sample code: class Serializable {}; class MyData : public Serializable {}; void GetData( Serializable& ) {} template<typename T> void GetData( T& data ) { std::istringstream s{"test"}; s >> data; } int main() { MyData d; GetData(d); } ( Live Sample ) Based on overload resolution rules, the non-template version should be preferred because the base class is of type Serializable . However, I expect SFINAE to kick in when there are errors in the template version when it is instantiated for overload resolution (because if the >> operator is not defined for a type, it should not

I want to check for the existence of a function in a specific namespace using SFINAE. I have found SFINAE to test a free function from another namespace which does the job, but there are some things I don't understand. Currently I have this working code, straight from the linked question: // switch to 0 to test the other case #define ENABLE_FOO_BAR 1 namespace foo { #if ENABLE_FOO_BAR int bar(); #endif } namespace detail_overload { template<typename... Args> void bar(Args&&...); } namespace detail { using namespace detail_overload; using namespace foo; template<typename T> decltype(bar()) test

#include <iostream> #include <cmath> #include <vector> using namespace std; int square(int a){ return a*a; } struct Point{ int x,y; }; int distance (const Point& a,const Point& b){ int k=(int) sqrt((float)((a.x-b.x)*(a.x-b.x))+((a.y-b.y)*(a.y-b.y))); return k; } int main(){ vector<Point>a(10); for (int i=0;i<10;i++){ cin>>a[i].x>>a[i].y; } int s=0; int s1; int k=0; for (int i=1;i<10;i++){ s+=square(distance(a[0],a[i])); } for (int i=1;i<10;i++){ s1=0; for (int j=0;j<10;j++){ s1+=square(distance(a[i],a[j])); if (s1<s) { s=s1; k=i;} } } cout<<k<<"Points are:"; cout<<a[k].x; cout<<a[k].y; return

How do I get all the address locations for functions/procedures/methods that is overloaded? For example, Dialogs.MessageDlgPosHelp is overloaded having two different versions of it - one without a default button and one with. How would I obtain the address locations for the two functions? TLama Based on this thread and what Thomas Mueller pointed there, you might define types with the same signatures as methods whose addresses you want to obtain (for each overload). If you then declare the variables of those types and assign method pointers to them you will make sure that compiler chooses the