outer-join

Top 1 with a left join

由 我的梦境 提交于 2019-11-28 15:27:08
问题 Given the query below there might be multiple rows in dps_markers with the same marker key but we only want to join against the first. If I take this query and remove the top 1 and ORDER BY I get a value for mbg.marker_value but run as it is it always returns null SELECT u.id, mbg.marker_value FROM dps_user u LEFT JOIN (SELECT TOP 1 m.marker_value, um.profile_id FROM dps_usr_markers um (NOLOCK) INNER JOIN dps_markers m (NOLOCK) ON m.marker_id= um.marker_id AND m.marker_key =

how to search Sql Server 2008 R2 stored procedures for a string?

由 别说谁变了你拦得住时间么 提交于 2019-11-28 09:10:39
I'm migrating a legacy SQLS2k to 2008R2, and it seems all data access was done through stored procs, and any custom queries use the legacy *= =* outer join syntax. There are upwards of a hundred procs so I don't want to open each one individually to see if it uses that syntax (most wouldn't), is there a way I can query the metadata for a list of procs/functions/views/triggers, then loop through searching for the *= or =* strings, printing out the name of the offending object? My background is oracle, I know how to find the metadata views there, but I'm a bit new to Sql Server. Downgrading the

Left outer join in linq

由 此生再无相见时 提交于 2019-11-28 05:22:10
问题 I have the following query but i have no idea on how to do a left outer join on table 1. var query = (from r in table1 join f in table2 on r.ID equals f.ID select new { r.ID, r.FirstName, r.LastName, FirstNameOnRecord = (f != null ? f.FirstName : string.Empty), LastNameOnRecord = (f != null ? f.LastName : string.Empty), NameChanged = (f != null ? (f.FirstName.CompareTo(r.FirstName) == 0 && f.LastName.CompareTo(r.LastName) == 0) : false) }).ToList(); 回答1: Refer this or this examples to learn

An Error in R: When I try to apply outer function:

由 本小妞迷上赌 提交于 2019-11-28 02:23:16
问题 Here is my code: Step1: Define a inverse function which I will use later inverse = function (f, lower = -100, upper = 100) { function (y) uniroot((function (x) f(x) - y), lower = lower, upper = upper)[1] } Step2: Here is my functions and their inverse: F1<-function(x,m1,l,s1,s2){l*pnorm((x-m1)/s1)+(1-l)*pnorm((x+m1)/s2)} F1_inverse = inverse(function(x) F1(x,1,0.1,2,1) , -100, 100) F2<-function(x,m2,l,s1,s2){l*pnorm((x-m2)/s1)+(1-l)*pnorm((x+m2)/s2)} F2_inverse = inverse(function(x) F1(x,1,0

Jquery: animate .outerWidth()?

由 北战南征 提交于 2019-11-28 02:21:21
问题 When animating a width toggle, it's not animating the padding, so i looked into .outerWidth() but i'm not exactly sure how to implement this... $('#shareheart').click(function(){ $('.share-text').animate({outerWidth: 'toggle'}, 2000) }) 回答1: Animate only works on css properties. Im not sure what the toggle key word does but i assume its shortand for alternating hide / show keyword. you could try: $('#shareheart').click(function(){ $('.share-text').animate({ width: 'toggle', 'padding-left':

How to FULL OUTER JOIN multiple tables in MySQL

由 纵饮孤独 提交于 2019-11-28 01:21:00
问题 I need to FULL OUTER JOIN multiple tables. I know how to FULL OUTER JOIN two tables from here. But I have several tables, and I can't apply it over them. How can I achieve it? My SQL code, below: INSERT INTO table ( customer_id ,g01 ,g02 ,g03 ,has_card ,activity ) SELECT sgd.customer_id, sgd.g01,sgd.g02,sgd.g03,sc.value, a.activity FROM s_geo_data sgd LEFT JOIN s_category sc ON sc.customer_id = sgd.customer_id UNION SELECT sgd.customer_id, sgd.g01,sgd.g02,sgd.g03,sc.value, a.activity FROM s

Efficient way to simulate full outer join in MySQL?

由 落爺英雄遲暮 提交于 2019-11-28 00:58:29
问题 According to Google search: since MySQL does not support full outer join, it could be simulated via union and/or union all. But both of these either remove genuine duplicates or show spurious duplicates. What would be correct and efficient way? This question seems relevant but couldn't get the answer of it. 回答1: You can use a LEFT JOIN and a RIGHT JOIN: SELECT * FROM tableA LEFT JOIN tableB ON tableA.b_id = tableB.id UNION ALL SELECT * FROM tableA RIGHT JOIN tableB ON tableA.b_id = tableB.id

Join Matrices in MATLAB

由 天涯浪子 提交于 2019-11-27 23:22:20
I have two matrices like the following ones: '01/01/2010' 1 '02/01/2010' 2 '03/01/2010' 3 '05/01/2010' 11 '06/01/2010' 17 '01/01/2010' 4 '02/01/2010' 5 '04/01/2010' 6 '05/01/2010' 7 , and after doing a few tricky things in MATLAB, I want to create the following three matrices: '01/01/2010' 1 4 '02/01/2010' 2 5 '03/01/2010' 3 NaN '04/01/2010' NaN 6 '05/01/2010' 11 7 '06/01/2010' 17 NaN '01/01/2010' 1 4 '02/01/2010' 2 5 '05/01/2010' 11 7 Any idea on how to join these tables? Cheers. EDIT: Really sorry for my typos, guys. I updated both the question and the input/output data. Please, feel free to

How can we differ LEFT OUTER JOIN vs Left Join [duplicate]

由 旧城冷巷雨未停 提交于 2019-11-27 22:38:45
This question already has an answer here: LEFT JOIN vs. LEFT OUTER JOIN in SQL Server 12 answers What is the difference between Left Join and Left Outer Join ? They are the same thing in MySQL. A LEFT JOIN is a synonym or shorthand for LEFT OUTER JOIN . There is none. The keyword OUTER is optional. They mean the same. 来源： https://stackoverflow.com/questions/2809594/how-can-we-differ-left-outer-join-vs-left-join

How to generalize outer to n dimensions?

由 断了今生、忘了曾经 提交于 2019-11-27 14:10:39
The standard R expression outer(X, Y, f) evaluates to a matrix whose (i, j)-th entry has the value f(X[i], Y[j]) . I would like to implement the function multi.outer , an n-dimensional generalization of outer : multi.outer(f, X_1, ..., X_n) , where f is some n-ary function, would produce a (length(X_1) * ... * length(X_n)) array whose (i_1,...,i_n)-th entry has the value f(X_1[i_1], ..., X_n[i_n]) for all valid index sets (i_1,...,i_n). Clearly, for each i in {1, ..., n}, all the elements of X_i in multi.outer(f, X_1,...,X_i,..., X_n) must be allowable i-th arguments for the function f . For
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