ordereddictionary

问题 The csv file that I have contain several repeated supplier_name but with different amt for year 2015-2017. Here goes my codes. df = pd.read_csv('government-procurement-via-gebiz.csv', parse_dates=['award_date'], infer_datetime_format=True, usecols=['supplier_name', 'award_date', 'awarded_amt'],) df = df[(df['supplier_name'] != 'na') & (df['award_date'].dt.year == 2015)].reset_index(drop=True) d1 = df.set_index('supplier_name').to_dict()['awarded_amt'] top5D1 = dict(sorted(d1.iteritems(), key

问题 Environment is: Ansible 1.9.2, CentOS 6.5 I have created a role to download JAVA (.tar.gz) artifact files for 3 different JAVA versions from Artifactory. I'm trying to use Ansible's with_dict feature (instead of using with_items). Created the following files: $ cat roles/java/defaults/main.yml --- java_versions: java7_60: version: 1.7.60 group_path: com/oracle/jdk classifier: linux-x64 ext: tar.gz dist_file: "jdk-{{ version }}-{{ classifier }}-{{ ext }}" # dist_file: "jdk-{{item.value.version

问题 My first attempt to combine the features of two dictionaries in the collections module was to create a class that inherits them: from collections import OrderedDict, defaultdict class DefaultOrderedDict(defaultdict, OrderedDict): def __init__(self, default_factory=None, *a, **kw): super().__init__(default_factory, *a, **kw) However, I cannot assign an item to this dictionary: d = DefaultOrderedDict(lambda: 0) d['a'] = 1 Traceback (most recent call last): File "<stdin>", line 1, in <module>

问题 I have an ordered dictionary that, as one would expect, contains a number of key-value pairs. I need to parse the contents of the ordered dictionary into CSV format, with the keys in the top row and their respective values in the second row. I've got the first row down, but I'm at a loss as to how to write the second row. The values in the OrderedDict are what you'd expect (what it looks like printed out in the terminal): ([(a, 1), (b, 2), (c, 3)]) . Here's what I have: import csv with open(

问题 I am trying to create a pandas dataframe from an ordereddict to preserve the order of the values. But for some reason after creating the dataframe the fields are messed up again. Here's the list of ordereddicts: [OrderedDict([ ('key_a', 'value_a'), ('key_b', 'value_b'), ]), OrderedDict([ ('key_a', 'value_c'), ('key_b', 'value_d'), ]) ] Now how should I create a pandas DataFrame from these? What I am looking for is something like that (the important thing is the key_a and key_b etc column name

问题 How do I convert an OrderedDict to a normal dictionary while preserving the same order? The reason I am asking this is because is when I fetch my data from an API, I get a JSON string, in which I use json.loads(str) to return a dictionary. This dictionary that is returned from json.loads(...) is just out of order and is randomly ordered. Also, I've read that OrderedDict is slow to work with so I want to use regular dict in same order as original JSON string. Slightly off-topic: Is there

问题 I've a dictionary such as this: my_dict=collections.OrderedDict([((123, 1), 'qwe'), ((232, 1), 'asd'), ((234, 2), 'zxc'), ((6745, 2), 'aaa'), ((456, 3), 'bbb')]) The combination of the tuple is always unique and I would like to maintain the order of insertion, and hence OrderedDict. I've a well over ~10K items in the dict. How can I efficiently maintain a counter that gives the count of the second element in the tuple? Basically, I need to know the count whenever I would like to add/delete an

问题 I'm trying to POST a request to an Amazon S3 endpoint using Python's Requests library. The request is of the multipart/form-data variety, because it includes the POSTing of an actual file. One requirement specified by the API I'm working against is that the file parameter must be posted last . Since Requests uses dictionaries to POST multipart/form-data, and since dictionaries don't follow a dictated order, I've converted it into an OrderedDict called payload . It looks something like this

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 4 years ago . I am trying to sort the following OrderedDict by doing the following--> >>> from collections import OrderedDict >>> d = OrderedDict([(4995L, [{'isbn_13': u'9788131805923', 'book_quantity': 49L, 'seller_book_id': 4995L, 'book_id': 4995L, 'title': u'Industrial Automation and Robotics', 'selling_price': 292.0, 'id'

问题 Ruby 1.9.2 introduced order into hashes. How can I test two hashes for equality considering the order? Given: h1 = {"a"=>1, "b"=>2, "c"=>3} h2 = {"a"=>1, "c"=>3, "b"=>2} I want a comparison operator that returns false for h1 and h2 . Neither of the followings work: h1 == h2 # => true h1.eql? h2 # => true 回答1: Probably the easiest is to compare the corresponding arrays. h1.to_a == h2.to_a 回答2: You could compare the output of their keys methods: h1 = {one: 1, two: 2, three: 3} # => {:one=>1,