openmp

openmp slower more than one threads, can't figure out

夙愿已清 提交于 2019-12-11 04:47:08
问题 I got a problem that my following code runs slower with openmp: chunk = nx/nthreads; int i, j; for(int t = 0; t < n; t++){ #pragma omp parallel for default(shared) private(i, j) schedule(static,chunk) for(i = 1; i < nx/2+1; i++){ for(j = 1; j < nx-1; j++){ T_c[i][j] =0.25*(T_p[i-1][j] +T_p[i+1][j]+T_p[i][j-1]+T_p[i][j+1]); T_c[nx-i+1][j] = T_c[i][j]; } } copyT(T_p, T_c, nx); } print2file(T_c, nx, file); The problem is when I run more than one threads, the computational time will be much

Why is this code giving SIGABRT with openMP?

孤街醉人 提交于 2019-12-11 04:43:59
问题 for (int i = 0; i < x_res; i++){ #pragma omp parallel for for (int j = 0; j < y_res; j++) { Ray hit = s.kd_tree->intersect(rays[i][j]); } } Why is this code not working in parallel? I cannot find the reason. The backtrace outputs this: #0 0x00007fff8ce03bf2 in __psynch_mutexwait () #1 0x00007fff8cd331a1 in pthread_mutex_lock () #2 0x00000001000027e4 in gomp_barrier_destroy () #3 0x000000010000247b in gomp_team_end () 回答1: Download the last gcc (4.8 for now) from http://hpc.sourceforge.net/ .

private variable outside parallel for-loop

断了今生、忘了曾经 提交于 2019-12-11 04:43:15
问题 I want to know how much time each thread is using in the for loop. I want time_taken to be private for each thread so they can append their own time there. Best cast i would like the total time for each thread, instead of the time for each iteration in the while-loop. double time_taken = 0.0; while(delta >= epsilon) { delta = 0.0; double wtime = omp_get_wtime(); #pragma omp parallel for reduction(+:delta) for (i = 0; i < workSize; i++) { #do some work and change delta } time_taken += omp_get

How to recompile Numpy with enabled OpenMP directives

柔情痞子 提交于 2019-12-11 04:38:49
问题 In this answer to Multiprocessing.Pool makes Numpy matrix multiplication slower the author of the answer recommends in the second paragraph to recompile Numpy with enabled OpenMP directives. So my questions are: How do you do that? What could be negative side effects? Would you recommend that? Searching SO I found following post OpenMP and Python, where the answers explain why there is no use for OpenMP in general Python due to the GIL. But I assume Numpy is a different issue. 回答1: While

why do people declare iterated values before loop for openmp?

旧时模样 提交于 2019-12-11 04:37:13
问题 So from what I understand, either of these are correct in ALL versions of openmp: //int i declared in loop, explicitly private #pragma omp parallel for for (int i = 0; i < NUMEL; i++) { foo(i); } //int i declared outsize loop, but is the iterated value, implicitly private int i; #pragma omp parallel for for (i = 0; i < NUMEL; i++) { foo(i); } However, I more commonly see the second than the first. Why is that? 回答1: Because not everybody writes in C++ or targets a C99-compliant C compiler.

Using an openmp pragma inside #define [duplicate]

隐身守侯 提交于 2019-12-11 04:31:59
问题 This question already has answers here : Closed 8 years ago . Possible Duplicates: C/C++ pragma in define macro Conditional “pragma omp” How can I use an OpenMP pragmas inside a macro definition? E.g. #define A() { \ ...a lot of code... \ #pragma omp for \ for(..) \ ..do_for.. \ ...another a lot of code \ } 回答1: As it was answered here Conditional "pragma omp" C99 has the _Pragma keyword that allows you to place what otherwise would be #pragma inside macros. Something like #define OMP_PARA

Why does OpenMP fail to sum these numbers?

自闭症网瘾萝莉.ら 提交于 2019-12-11 04:16:43
问题 Consider the following minimal C code example. When compiling and executing with export OMP_NUM_THREADS=4 && gcc -fopenmp minimal2.c && ./a.out (homebrew GCC 5.2.0 on OS X 10.11), this usually produces the correct behavior, i.e. seven lines with the same number. But sometimes, this happens: [ ] bsum=1.893293142303100e+03 [1] asum=1.893293142303100e+03 [2] asum=1.893293142303100e+03 [0] asum=1.893293142303100e+03 [3] asum=3.786586284606200e+03 [ ] bsum=1.893293142303100e+03 [ ] asum=3

c++ openmp and threadprivate

≯℡__Kan透↙ 提交于 2019-12-11 04:02:48
问题 I'm in a situation where on one computer (cluster with high perf nodes) a code compiles but on my personal computer it doesn't. The error is 'var' declared 'threadprivate' after first use. #pragma omp threadprivate(var) The related line in the code is in a header file and looks like this extern const int var; #pragma omp threadprivate(var); I haven't written the code so it is difficult to give a minimal example of the problem. Here are some specification of the computer I use : cluster

the desired number of processors are not used

无人久伴 提交于 2019-12-11 03:44:58
问题 I am running the following fortran code in parallel using openmp, but only one processor is working. I added some of the execution routines like OMP_SET_NUM_THREADS and OMP_GET_NUM_THREADS to the code to follow the parallel-processing. Here is the relevant part of the code: integer a,b,omp_get_num_procs,omp_get_max_threads, & omp_get_num_threads open( unit=10 , file='threads' , status='new' ) a=4 call omp_set_num_threads(a) write(10,*) 'num_proc=',omp_get_num_procs() write(10,*) 'max_threads=

OpenMP: having a complete 'for' loop into each thread

好久不见. 提交于 2019-12-11 03:18:35
问题 I have this code: #pragma omp parallel { #pragma omp single { for (int i=0; i<given_number; ++i) myBuffer_1[i] = myObject_1->myFunction(); } #pragma omp single { for (int i=0; i<given_number; ++i) myBuffer_2[i] = myObject_2->myFunction(); } } // and so on... up to 5 or 6 of myObject_x // Then I sum up the buffers and do something with them float result; for (int i=0; i<given_number; ++i) result = myBuffer_1[i] + myBuffer_2[i]; // do something with result If I run this code, I get what I