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Fuseki SPARQL INSERT produces the “Error 400: SPARQL Query: No 'query=' parameter”

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问题 I try to insert an individual into my ontology, but get the error: Error 400: SPARQL Query: No 'query=' parameter Fuseki - version 2.4.1 (Build date: 2016-11-04T18:59:20+0000) This is my SPARQL INSERT query #1: PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#> PREFIX owl: <http://www.w3.org/2002/07/owl#> PREFIX xsd: <http://www.w3.org/2001/XMLSchema#> PREFIX oo: <http://www.test.com/test-ontology.owl#> INSERT { oo:cap_123 rdf:type oo:MyTours . oo:cap_123 oo:active true . oo:cap_123 oo

path between two resources

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问题 Is it possible to count the number of the edges that connect two instance with a SPARQL query? I want to find a path. 回答1: You count the number of edges in a unique path using SPARQL's property paths and aggregate functions. For instance, with data like this, which contains two paths that we care about ( a to c with two edges, and d to g with three edges): @prefix : <https://stackoverflow.com/questions/19587520/sparql-path-between-two-instance/> . :a :p :b . # a to c is a path of length 2 :b

Representing if-then sentence using OWL?

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问题 I am working with basic OWL, and it's quite easy to represent some simple sentence like "Songoku is a lecturer, he teaches Maths". E.g.: <owl:Class rdf:ID="Lecturer"></owl:Class> <owl:Class rdf:ID="Subject"></owl:Class> <owl:Property rdf:ID="teach"> <rdfs:domain rdf:resource="#Lecturer"/> <rdfs:range rdf:resource="#Subject"/> </owl:Property> <Subject rdf:ID="Maths"></Subject> <Lecturer rdf:ID="Songoku"> <teach> <Subject rdf:about="#Maths"></Subject> </teach> </Lecturer> But I faced a problem

Adding statements of knowledge to an OWL Ontology in Protege)

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问题 In my Ontology I have three classes, Player , Team , and Competition . I also have the two object properties, employs , and competesIn . The domain of employs is Team , and the range Player , the domain of competesIn is Team or Player and the range Competition . I want the Ontology to infer that if a Player is employed by a Team and that Team competes in a Competition then the Player also competes in that Competition . Is there any way to add this information to an Ontology without putting in

Ontology property definition in Protégé-OWL / SWRL

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I need to implement an OWL-ontology in Protégé, which contains a two classes: s1 and s2 , both are the instances of System class. These two classes are connected by the connection class s1_s2 , which contains property omega . This property has to take a value according to the following law: omega = 1 * s1.complete How can I implement it in Protégé, such way I could use it in SWRL-rule in the future? In general, you'd start by defining the classes and the properties that you need: At this point you could add some axioms that govern how the systems have to interact, how the properties work, etc.

How to infer isBrotherOf property between two individuals

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问题 I need to infer that one individual is the brother of other one if they have the same father. So, if I have this: Bart hasFather Homer. Lisa hasFather Homer. Because Bart and Lisa have the same father, I would like to infer: Lisa hasBrother Bart. Is there any method to do that using any property characteristics? 回答1: Use Property Chains and Rolification Antoine Zimmermann's answer is a very good start to this problem, and touches on the major point that you need to solve this sort of task:

Ontology property definition in Protégé-OWL / SWRL

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问题 I need to implement an OWL-ontology in Protégé, which contains a two classes: s1 and s2 , both are the instances of System class. These two classes are connected by the connection class s1_s2 , which contains property omega . This property has to take a value according to the following law: omega = 1 * s1.complete How can I implement it in Protégé, such way I could use it in SWRL-rule in the future? 回答1: In general, you'd start by defining the classes and the properties that you need: At this