object

how to declare class with 1000000 elements c++

由 元气小坏坏 提交于 2020-01-03 05:48:10
问题 I am writing a c++ code and my need is to declare a class having two elments as class arr{ public: long num; string str; }; now i need to store almost 1000000 elments of this class(depending on user input number of class object can warry in a range of 1 <= n <= 1000000 The object are created dynamically as #include <iostream> #include<string> using namespace std; class arr{ public: long i; string str; }; int main(){ long n,j,i; cin>>n; arr a[n]; .... rest of programme but if value of n is

Converting two-dimensional array to an object c#

由 本小妞迷上赌 提交于 2020-01-03 05:35:06
问题 This all originates from querying Google Analytics data. For a basic query the main factors that change are the dimensions and the metrics . The object that is returned is of a type called GaData, and the actual results that you need reside in GaData.Rows. The format of GaData.Rows looks like this: There will first be a row for each dimension, in this example there is a row for "New Visitor" and a 2nd row for "Returning Visitor". Within those rows will be another set of rows that contain the

Convert JSON File to C# Object

由 眉间皱痕 提交于 2020-01-03 04:58:12
问题 I need some help with converting JSON file to C# object. I've been using Json.NET library. JSON file format are as below: {"174.845620 -36.913447 WGS84":[{"uuid":"a7e72b5c1fb96f1452d3c64fe89c7e6a","name":"35 Carbine Road","suburb":"Mount Wellington","town":"Auckland","district":"Auckland City","region":"Auckland","island":"North Island","x":2674839,"y":6474828,"longitude":174.845707,"latitude":-36.913385,"locality":"Mount Wellington, Auckland, Auckland City"}],"174.698503 -36.788258 WGS84":[{

PHP sorting object array by certain criteria?

由 北城余情 提交于 2020-01-03 02:29:09
问题 I have something like this: $i = 0; foreach($tracks['results'] as $track){ $trackName[$i] = $track['name']; $trackPlaycount[$track['name']] = $track['playcount']; $trackPercent[$track['name']] = $track['percent']; $i++; } $this->trackName = $trackName; $this->trackPlaycount = $trackPlaycount; $this->trackPercent = $trackPercent; how could I sort these objects by playcount? From what I have read so far I understand I should probably create a compare function and then make it work with usort(),

In java can i have more than one class/object in a file?

由 馋奶兔 提交于 2020-01-03 02:24:06
问题 So the way i've been told to do things is you have your file and the file name is Classname.java and then the code is something like this: class ClassName { SOME METHODS main {} } and then thats all. I'd like to have two objects defined and used within the same .java file. (i don't want to have to put the other class in a difernt file just because i'd like to send this to someone and i want to avoid hasstle of atatching multiple files to an email [the lazy do make good programers though if

string的相关知识点

由 点点圈 提交于 2020-01-03 02:15:38
string 只是 String 的一个别名，以下三种写法都可以 string myName="YZX"; String myName="YZX"; System.String myName="YZX"; http://www.cnblogs.com/skywind/archive/2007/04/30/733414.html 中有写到"在C#的编译时,会自动的把string转化为Sysem.string 即 using string = System.String;" 由于string是C#中的关键字，我们可以统一使用第一种写法 String虽然是类，但却不能用如下方法赋值： String s1=new String("test"); 编译器提示错误 与“string.String(char*)”最匹配的重载方法具有一些无效参数 有些示例还用以上方法写，我不知道它们是怎么编译通过的。 但是却有这样赋值方法： String s1=new String('*', 5); 生成"*****"这个字符串给s1 如果只是取字符串的其中一位，除了用Substring函数外，还可以直接这种表达： Console.WriteLine("hello"[1]); 字符串中==是比较值，而如果要比较对象，要使用(object)来强制转换，或者用Object.ReferenceEquals来检测。

How to specify generic type when the type is only known at runtime?

由 大憨熊 提交于 2020-01-03 01:21:13
问题 I have some code that I need to generate a generic object on the fly with the generic type of 1 of a set of subclasses: e.g. keyEvent , mouseEvent or appEvent , these all extend event . So, my generic class EventFunction requires a template, however I dont know what the class type is until I recieve the event, so is there a way to do the following: Event event = new KeyEvent(); // FOR EXAMPLE RECIEVING A KEY EVENT // Require an EventFunction with that event class as the generic type

Sencha Touch - How to get list itemtpl to display JSON child objects?

由 ￣綄美尐妖づ 提交于 2020-01-03 00:58:52
问题 I am having some problems trying to display child objects using itemtpl property for a list. here is an example of the issue JSON String: {"messages" : [{"body":{"special":"some special format", "plain":"plain format"}}] Model: Ext.regModel('MyFeed', { fields: [ {name: 'body'} ] }); Store: var FeedStore = new Ext.data.Store({ model: 'MyFeed', proxy: { type: 'ajax', url: 'data.json', reader: { type: 'json', root: 'messages' } } }); List: var FeedList = new Ext.List({ itemTpl : '<div>{body}<

Java复习之路（第十天 API）（tostring‘ equals方法的重写）

由 谁说我不能喝 提交于 2020-01-02 21:53:12
Java基础 API定义 应用程序编程接口，是一种预先定义的函数，目的是提供应用程序与开发人员基于某软件或者是硬件的以访问一组例程的能力，而且无需要访问的源码，或者是理解工作内部的细节 object： 所有对象的顶级的父类，每个类都直接或者间接的继承object 存在于java.lang包中，这个过程不需要进行手动的导入包 Tostring： 默认返回，类名@地址 的格式,来展示对象的地址值,重写后返回值是将返回值属性值进行拼接成为字符串 就是返回我们的想要的值，将返回值的值转化为结果的字符串 equals(object obj) 当前对象和参数的对象比较大小， 默认的是进行比较内存的地址 ，如果要比较的对象的属性，可以进行重写该方法，s1==s2 s1.equals(s2) 该代码里面实现了tostring和equals方法重写 package com.tedu.api; import java.util.jar.Attributes.Name; //测试object类的tostring()equals() public class Test1_Object { public static void main(String[] args) { Student student=new Student(); student.setAge(15); //进行设置数值 student

How best to store a Python object for later evaluation?

由 青春壹個敷衍的年華 提交于 2020-01-02 20:58:13
问题 I have written the following python code using a scipy function. The particular form of function f is irrelevant. import numpy as np from scipy.interpolate.interpnd import LinearNDInterpolator def f(x, y): s = np.hypot(x, y) phi = np.arctan2(y, x) tau = s + s*(1-s)/5 * np.sin(6*phi) return 5*(1-tau) + tau npts = 200 px, py = np.random.choice(x, npts), np.random.choice(y, npts) ip = LinearNDInterpolator((px, py), f(px,py)) What kind of object is ip ? I would like to store it in a file and
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