object

using .each to execute array of functions on .resize

浪尽此生 提交于 2020-01-06 04:30:09
问题 In the an object called Response this works to trigger a function on .ready and .resize simultaneously... Response.action = function ( func ) { if ( typeof func !== 'function' ) { return false; } // If func is not a function, return false. $(function () { func(); $(window).resize( func ); }); // return func; }; // Response.action ...using this to call it: Response.action( myfunc ); function myfunc() { //do stuff } (We worked that out in this thread.) I'd like to make another version that can

js--深拷贝与浅拷贝

柔情痞子 提交于 2020-01-06 03:55:26
对象: 只针对于Object和Array这样的引用数据类型 说明: 浅拷贝只复制指向某个对象的指针,而不是复制对象的本身,新旧对象还是共享一块内存。但深拷贝会另外创造一个一模一样的对象,新的对象跟原对象不共享内存,修改新对象不会改到原对象。 赋值与深浅拷贝的区别:    实现:   浅拷贝:     1. Object.assign()        Object.assign() 方法可以把任意多个的源对象自身的可枚举属性拷贝给目标对象,然后返回目标对象。但是 Object.assign() 进行的是浅拷贝,拷贝的是对象的属性的引用,而不是对象本身。       注意: 当object只有一层的时候,是深拷贝     2.Array.prototype.concat()     3.Array.prototype.slice()         关于Array的slice和concat方法的补充说明 :Array的slice和concat方法不修改原数组,只会返回一个浅复制了原数组中的元素的一个新数组。     原数组的元素会按照下述规则拷贝:       如果该元素是个对象引用(不是实际的对象),slice 会拷贝这个对象引用到新的数组里。两个对象引用都引用了同一个对象。如果被引用的对象发生改变,则新的和原来的数组中的这个元素也会发生改变。       对于字符串

Xcode refuses to compile when trying to get property from custom object out of array

柔情痞子 提交于 2020-01-06 03:13:08
问题 I've been running into this problem a lot lately. I have an NSMutableArray called tests which is populated with instances of my custom class Test . I'm trying to access a property with the following method: return [tests objectAtIndex:row].name; However LLVM always throws an error and refuses to compile: error: Semantic Issue: No member named 'name' in 'struct objc_object' How do I tell the compiler that I'll be accessing a Test object and to let me compile the damned thing? 回答1: Since

Xcode refuses to compile when trying to get property from custom object out of array

僤鯓⒐⒋嵵緔 提交于 2020-01-06 03:13:07
问题 I've been running into this problem a lot lately. I have an NSMutableArray called tests which is populated with instances of my custom class Test . I'm trying to access a property with the following method: return [tests objectAtIndex:row].name; However LLVM always throws an error and refuses to compile: error: Semantic Issue: No member named 'name' in 'struct objc_object' How do I tell the compiler that I'll be accessing a Test object and to let me compile the damned thing? 回答1: Since

Creating interface objects in java

爱⌒轻易说出口 提交于 2020-01-06 02:33:11
问题 I encountered some Java code: public class LocationProvider { public interface LocationCallback { public void handleNewLocation(Location location); } // class constructor public LocationProvider(Context context, LocationCallback callback){ ... } } For the first time in Java, I am encountering a constructor or method with an argument of a "type" that is an interface. Is it possible to create objects of interfaces ? Can you use them like regular objects ? In C++ I know it's not possible to

python的一些内置函数

坚强是说给别人听的谎言 提交于 2020-01-06 01:03:38
最近看到一些人写的文章里有提到python的描述符__get__,__set__,__del__. 这里我也小小研究了一下,除了这3个之外还加上过程中学习的几个,比如__call__等。 __get__ object.__get__(self, instance, owner) 如果一个class定义了__get__,那么它就是一个descriptor。其中的参数instance是访问 descriptor 的实例,owner是所有者的类。如果不是通过实例而是通过类来访问 那么instance就为None。 比如下面的例子: class simpleDescriptor(object): def __get__(self,instance,owner): print "call __get__" return instance,owner class A(object): foo=simpleDescriptor() print A.foo # None a=A() print a.foo # <__main__.A object at 0x02A299F0> 输出: call __get__ (None, <class '__main__.A'>) call __get__ (<__main__.A object at 0x02A698F0>, <class '__main__

create javascript object

风格不统一 提交于 2020-01-05 20:01:46
问题 I have this function // add history paths and save data function AddPath( strTag, strUserName, arrayLatLngPoints, pathColour) { for (var i = 0; i < arrayLatLngPoints.length; i++) { var point = arrayLatLngPoints[i]; var date = new Date( parseInt( point.timestamp)); addMarkers(point.timestamp, point.lat, point.lng, point.timestamp, strUserName, pathColour, date.toString()); date = null; } } as well as adding the markers with addMarkers() i want to store the lat, long and timestamp in an object.

How to pass object between several views in storyboard, iOS Dev

二次信任 提交于 2020-01-05 15:22:13
问题 I have searched for this but the answer is too simple to satisfy me :( I want to pass a NSManagedObjectContext from TabBarController to almost every view controllers in my app. In detail, my storyboard structure is kind of like this: TabBarController >>> several tab items views ( this is easy to pass, just pass one time in according view controllers). But I have another relation: TabBarController (the one mentioned above) >>> NavigationController >>> TableViewControllerOne >>>

oss上传实例

倖福魔咒の 提交于 2020-01-05 14:39:35
pom.xml <dependency> <groupId>com.aliyun.oss</groupId> <artifactId>aliyun-sdk-oss</artifactId> <version>2.8.3</version> </dependency> java public class HelloOSS { //static Logger logger = Logger.getLogger(HelloOSS.class); // endpoint是访问OSS的域名。如果您已经在OSS的控制台上 创建了Bucket,请在控制台上查看域名。 // 如果您还没有创建Bucket,endpoint选择请参看文档中心的“开发人员指南 > 基本概念 > 访问域名”, // 链接地址是:https://help.aliyun.com/document_detail/oss/user_guide/oss_concept/endpoint.html?spm=5176.docoss/user_guide/endpoint_region // endpoint的格式形如“http://oss-cn-hangzhou.aliyuncs.com/”,注意http://后不带bucket名称, // 比如“http://bucket-name.oss-cn-hangzhou.aliyuncs

Parse.com Query: Cache is always empty (iOS)

柔情痞子 提交于 2020-01-05 14:25:42
问题 I'm writing an iOS-App using Parse.com as a backend. In the - (PFQuery)queryForTable method of my PFQueryTableViewController I'm retrieving a set of data from Parse, but I'm unable to cache this query in order to support functionality when the device is currently offline. The method looks as followed: - (PFQuery *)queryForTable { PFQuery *query = [PFQuery queryWithClassName:self.parseClassName]; [query whereKey:@"city" equalTo:[[NSUserDefaults standardUserDefaults] objectForKey:@"city"]]; //