numbers

Get a random number focused on center

时光总嘲笑我的痴心妄想 提交于 2019-11-27 19:45:27
问题 Is it possible to get a random number between 1-100 and keep the results mainly within the 40-60 range? I mean, it will go out of that range rarely, but I want it to be mainly within that range... Is it possible with JavaScript/jQuery? Right now I'm just using the basic Math.random() * 100 + 1 . 回答1: The simplest way would be to generate two random numbers from 0-50 and add them together. This gives a distribution biased towards 50, in the same way rolling two dice biases towards 7. In fact,

Why is not 'decimal.Decimal(1)' an instance of 'numbers.Real'?

不问归期 提交于 2019-11-27 19:29:00
问题 I try to check if a variable is an instance of a number of any type ( int , float , Fraction , Decimal , etc.). I cam accross this question and its answer: How to properly use python's isinstance() to check if a variable is a number? However, I would like to exclude complex numbers such as 1j . The class numbers.Real looked perfect but it returns False for Decimal numbers... from numbers Real from decimal import Decimal print(isinstance(Decimal(1), Real)) # False In contradiction, it works

JavaScript adding a string to a number

折月煮酒 提交于 2019-11-27 19:20:57
I was reading the re-introduction to JavaScript on MDN and in the section Numbers it said that you can convert a string to a number simply by adding a plus operator in front of it. For example: +"42" which would yield the number output of 42. But further along in the section about Operators it says that by adding a string "something" to any number you can convert that number to a string. They also provide the following example which confused me: "3" + 4 + 5 would presumably yield a string of 345 in the output, because numbers 4 and 5 would also be converted to strings. However, wouldn't 3 + 4

Best way to convert English numbers to Arabic [duplicate]

柔情痞子 提交于 2019-11-27 18:35:16
Possible Duplicate: Convert String to another locale in java I want to convert a java String that contains english numbers to arabic one's so i make this int arabic_zero_unicode= 1632; String str = "13240453"; StringBuilder builder = new StringBuilder(); for(int i =0; i < str.length(); ++i ) { builder.append((char)((int)str.charAt(i) - 48+arabic_zero_unicode)); } System.out.println("Number in English : "+str); System.out.println("Number In Arabic : "+builder.toString() ); the out put Number in English : 13240453 Number In Arabic : ١٣٢٤٠٤٥٣ is there another more efficient way to do this ? This

Explanation on Integer.MAX_VALUE and Integer.MIN_VALUE to find min and max value in an array

喜你入骨 提交于 2019-11-27 18:33:31
I don't seem to understand how Integer.MAX_VALUE and Integer.MIN_VALUE help in finding the min and max value in an array. I understand how this method (pseudocode below) works when finding the min and max values: max = A[0], min = A[0] for each i in A if A[i] > max then max = A[i] if A[i] < min then min = A[i] But as for this method, I don't understand the purpose of Integer.MAX_VALUE and Integer.MIN_VALUE : import java.util.Scanner; class MyClass { public static void main(String[] args) { int[] numbers; // declaring the data type of numbers numbers = new int[3]; //assigning the number of

Why don't numbers support .dup?

荒凉一梦 提交于 2019-11-27 18:20:01
问题 >> a = 5 => 5 >> b = "hello, world!" => "hello, world!" >> b.dup => "hello, world!" >> a.dup TypeError: can't dup Fixnum from (irb):4:in `dup' from (irb):4 I understand that Ruby will make a copy every time you assign an integer to a new variable, but why does Numeric#dup raise an error? Wouldn't this break abstraction, since all objects should be expected to respond to .dup properly? Rewriting the dup method will fix the problem, as far as I can tell: >> class Numeric >> def dup() >> self >>

Number of all longest increasing subsequences

时光怂恿深爱的人放手 提交于 2019-11-27 18:12:53
I'm practicing algorithms and one of my tasks is to count the number of all longest increasing sub-sequences for given 0 < n <= 10^6 numbers. Solution O(n^2) is not an option. I have already implemented finding a LIS and its length ( LIS Algorithm ), but this algorithm switches numbers to the lowest possible. Therefore, it's impossible to determine if sub-sequences with a previous number (the bigger one) would be able to achieve the longest length, otherwise I could just count those switches, I guess. Any ideas how to get this in about O(nlogn) ? I know that it should be solved using dynamic

How to dismiss number pad keyboard by tapping anywhere

ぐ巨炮叔叔 提交于 2019-11-27 18:06:17
I'd like to know the simplest code to dismiss the number pad keyboard when tapping anywhere outside the number pad. It's a simple application to input a number inside a text field and then a user can dismiss the keyboard after the user finishes typing the numbers on the text field. Thanks! :) Declaring the text field as instance variable or property if it isn't already and implementing a simple method like this: - (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event { [textField resignFirstResponder]; } will do just fine. Try this method, -(void)touchesBegan:(NSSet *)touches

SQL BETWEEN for text vs numeric values

流过昼夜 提交于 2019-11-27 17:58:41
问题 BETWEEN is used in a WHERE clause to select a range of data between two values. If I am correct whether the range's endpoint are excluded or not is DBMS specific. What I can not understand in the following: If I have a table of values and I do the following query: SELECT food_name FROM health_foods WHERE calories BETWEEN 33 AND 135;` The query returns as results rows including calories =33 and calories =135 (i.e. range endpoints are included ). But if I do: SELECT food_name FROM health_foods

How do you check in python whether a string contains only numbers?

淺唱寂寞╮ 提交于 2019-11-27 17:55:23
How do you check whether a string contains only numbers? I've given it a go here. I'd like to see the simplest way to accomplish this. import string def main(): isbn = input("Enter your 10 digit ISBN number: ") if len(isbn) == 10 and string.digits == True: print ("Works") else: print("Error, 10 digit number was not inputted and/or letters were inputted.") main() if __name__ == "__main__": main() input("Press enter to exit: ") You'll want to use the isdigit method on your str object: if len(isbn) == 10 and isbn.isdigit(): From the isdigit documentation: str.isdigit() Return true if all