numbers

This question already has an answer here: How to prevent ifelse() from turning Date objects into numeric objects 6 answers I am trying to make ifesle for two dates. I have two columns- DateIn and DateOut. I need to add 3rd variable, which would show "DateOut" if there is date value, or DateIn if there is : DateIn DateOut Travel date 2010-11-24 <NA> 2010-11-24 2011-12-21 2012-01-21 2012-01-21 2010-10-25 2010-11-25 2010-11-25 2014-01-14 <NA> 2014-01-14 I tried to do that with TravelDate <- ifelse(is.na(DateIn), DateOut, DateIn) But the result I am gettin is: DateIn DateOut Travel date 2010-11-24

Could anyone please me why the output of the following programme is not " different different"? public static void main(String[] args) { float f1=3.2f; float f2=6.5f; if(f1==3.2) System.out.println("same"); else System.out.println("different"); if(f2==6.5) System.out.println("same"); else System.out.println("different"); } o/p :different same 6.5 has a finite binary representation: 110.1 Any floating type with at least 4 significant bits can represent this number perfectly. 110.100000000000000000000 (float) = 6.5 110.10000000000000000000000000000000000000000000000000 (double) = 6.5 3.2 on the

I just learnt from Format numbers as currency in Python that the Python module babel provides babel.numbers.format_currency to format numbers as currency. For instance, from babel.numbers import format_currency s = format_currency(123456.789, 'USD', locale='en_US') # u'$123,456.79' s = format_currency(123456.789, 'EUR', locale='fr_FR') # u'123\xa0456,79\xa0\u20ac' How about the reverse, from currency to numbers, such as $123,456,789.00 --> 123456789 ? babel provides babel.numbers.parse_number to parse local numbers, but I didn't found something like parse_currency . So, what is the ideal way

I have an array with keys and values. Each value is an integer. I have an other array with the same keys. How can I subtract all of the values for the matching keys? Also there might be keys that do not occur in the second array but both arrays have the same length. If there is a key in array 2 that is not present in array 1 its value should be unchanged. If there is a key in the first array that is not in the second it should be thrown away. How do I do it? Is there any built-in function for this? If I would write a script it would be some kind of for loop like this: $arr1 = array('a' => 1,

Possible Duplicate: How can I create a Zerofilled value using JavaScript? I have to output a day number that must always have 3 digits. Instead of 3 it must write 003 , instead of 12 it must write 012 . If it is greater than 100 output it without formatting. I wonder if there's a regex that I could use or some quick in-line script, or I must create a function that should do that and return the result. Thanks! How about: zeroFilled = ('000' + x).substr(-3) For arbitrary width: zeroFilled = (new Array(width).join('0') + x).substr(-width) As per comments, this seems more accurate: lpad = function