numberformatexception

Android studio show me error in event log NumberFormatException: Invalid revision: 24.0.0-alpha1: Invalid revision: 24.0.0-alpha1 build.gradle: apply plugin: 'com.android.application' android { compileSdkVersion 23 buildToolsVersion "23.0.2" lintOptions { checkReleaseBuilds false abortOnError false } defaultConfig { applicationId "com.xxxx" minSdkVersion 10 multiDexEnabled true } buildTypes { release { minifyEnabled false proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.txt' } } } dependencies { compile project(':library') compile 'com.android.support:multidex:1.0

Why do Double.parseDouble(null) and Integer.parseInt(null) throw different exceptions? Is this a historical accident or intentional? The documentation clearly states two types of exceptions for Double.parseDouble(...) and one for Integer.parseInt() , but it seems inconsistent: Integer.parseInt(null); // throws java.lang.NumberFormatException: null However Double.parseDouble(null); // throws java.lang.NullPointerException It is reasonable to expect the same exceptions to be thrown for null; however, these api's are very old and may not be able to be changed at this point. And: Since the

I have a double value = 1.068879335 i want to round it up with only two decimal values like 1.07. I tried like this DecimalFormat df=new DecimalFormat("0.00"); String formate = df.format(value); double finalValue = Double.parseDouble(formate) ; this is giving me this following exception java.lang.NumberFormatException: For input string: "1,07" at sun.misc.FloatingDecimal.readJavaFormatString(FloatingDecimal.java:1224) at java.lang.Double.parseDouble(Double.java:510) can some one tell me what is wrong with my code. finaly i need the finalValue = 1.07; Note the comma in your string: "1,07".

Why does this part of code fail: Integer.parseInt("11000000000000000000000000000000",2); Exception in thread "main" java.lang.NumberFormatException: For input string: "11000000000000000000000000000000" As far as I understand Integer is a 32 bit value. The number of zeros and ones in the upper code is 32. If there are 31 the code works. Why is that so? millimoose Your code fails because it tries to parse a number that would require 33 bits to store as a signed integer. A signed int is a 32 bit value in two's complement representation, where the first bit will indicate the sign of the number,

I'm running into this situation where I need to parse a String into an int and I don't know what to do with the NumberFormatException . The compiler doesn't complain when I don't catch it, but I just want to make sure that I'm handling this situation properly. private int getCurrentPieceAsInt() { int i = 0; try { i = Integer.parseInt(this.getCurrentPiece()); } catch (NumberFormatException e) { i = 0; } return i; } I want to just simplify my code like this. The compiler doesn't have a problem with it, but the thread dies on the NumberFormatException . private int getCurrentPieceAsInt() { int i

This question already has an answer here: What is a NumberFormatException and how can I fix it? [duplicate] 9 answers In my day to day web application development there are many instances where we need to take some number inputs from the user. Then pass on this number input to may be service or DAO layer of the application. At some stage since its a number (integer or float), we need to convert it into Integer as shown in the following code snippet. String cost = request.getParameter("cost"); if (cost !=null && !"".equals(cost) ){ Integer intCost = Integer.parseInt(cost); List<Book> books =