nsset

How to search an NSSet or NSArray for an object which has an specific value for an specific property? Example: I have an NSSet with 20 objects, and every object has an type property. I want to get the first object which has [theObject.type isEqualToString:@"standard"] . I remember that it was possible to use predicates somehow for this kind of stuff, right? Ole Begemann NSPredicate *predicate = [NSPredicate predicateWithFormat:@"type == %@", @"standard"]; NSArray *filteredArray = [myArray filteredArrayUsingPredicate:predicate]; id firstFoundObject = nil; firstFoundObject = filteredArray.count

Setup: I have a Core Data object A that has a to-many relation to B. Call the relation "items". So, a.items returns all B-s associated with A. Now, I have a manually composed NSSet "itemSet" of B objects. I want to do the following: return all A objects whose "items" relation exactly matches itemSet How do I construct a predicate for that? I’ve tried this: NSPredicate *predicate = [NSPredicate predicateWithFormat: @"(ALL items in %@)", itemSet]; But that just gives me Unsupported predicate (null) . This: NSPredicate *predicate = [NSPredicate predicateWithFormat: @"(items in %@)", itemSet];

How can we create unique object list in Swift language like NSSet & NSMutableSet in Objective-C. As of Swift 1.2 (Xcode 6.3 beta), Swift has a native set type. From the release notes: A new Set data structure is included which provides a generic collection of unique elements, with full value semantics. It bridges with NSSet , providing functionality analogous to Array and Dictionary . Here are some simple usage examples: // Create set from array literal: var set = Set([1, 2, 3, 2, 1]) // Add single elements: set.insert(4) set.insert(3) // Add multiple elements: set.unionInPlace([ 4, 5, 6 ]) //