nsnumber

An NSNumber containing a Bool is easily confused with other types that can be wrapped in the NSNumber class: NSNumber(bool:true).boolValue // true NSNumber(integer: 1).boolValue // true NSNumber(integer: 1) as? Bool // true NSNumber(bool:true) as? Int // 1 NSNumber(bool:true).isEqualToNumber(1) // true NSNumber(integer: 1).isEqualToNumber(true) // true However, information about its original type is retained, as we can see here: NSNumber(bool:true).objCType.memory == 99 // true NSNumber(bool:true).dynamicType.className() == "__NSCFBoolean" // true NSNumber(bool:true).isEqualToValue(true) ||

How can I convert all numbers that are more than 3 digits down to a 4 digit or less number? This is exactly what I mean: 10345 = 10.3k 10012 = 10k 123546 = 123.5k 4384324 = 4.3m Rounding is not entirely important, but an added plus. I have looked into NSNumberFormatter but have not found the proper solution, and I have yet to find a proper solution here on SO. Any help is greatly appreciated, thanks! Luca Iaco -(NSString*) suffixNumber:(NSNumber*)number { if (!number) return @""; long long num = [number longLongValue]; int s = ( (num < 0) ? -1 : (num > 0) ? 1 : 0 ); NSString* sign = (s == -1 ?

Consider this code: NSNumber* interchangeId = dict[@"interchangeMarkerLogId"]; long long llValue = [interchangeId longLongValue]; double dValue = [interchangeId doubleValue]; NSNumber* doubleId = [NSNumber numberWithDouble:dValue]; long long llDouble = [doubleId longLongValue]; if (llValue > 1000000) { NSLog(@"Have Marker iD = %@, interchangeId = %@, long long value = %lld, doubleNumber = %@, doubleAsLL = %lld, CType = %s, longlong = %s", self.iD, interchangeId, llValue, doubleId, llDouble, [interchangeId objCType], @encode(long long)); } The results: Have Marker iD = (null), interchangeId =

How can I determine if a Cocoa NSNumber represents NaN (not a number)? This emerges, for example, when I parse a string that has an invalid (non-numeric) contents. So, I found out that the class property [NSDecimalNumber notANumber] is just for this purpose. In some languages NaN != NaN, but this isn't the case in Cocoa. As Mike Abdullah says, the natural way to represent a NaN in Cocoa is with nil , but [NSNumber numberWithDouble:NAN] does return a valid object. There is no NSNumber -specific way of detecting this, but the general way, isnan([foo doubleValue]) , works. If you don’t like

I have an unsigned long long value which I want to store into an NSString and retrieve from the string. Initially I have the value in an NSNumber and I am using this to get the string NSString *numStr = [NSString stringWithFormat:@"%llu", [myNum unsignedLongLongValue]]; where myNum is an NSNumber. To get back the NSNumber from the NSString I have to first get the unsigned long long value. But there is no method in the NSString class to do that (we just have one for getting the long long value, not the unsigned long long value). Can someone please tell me how I can get back the value into an

I am a beginner at Obj-C and I am a bit confused at this scenario I have the following code: if (number1 < number2) { NSLog(@"THE FOLLOWING NUMBER "); NSLog(@"%@", number1); NSLog(@"IS LESS THAN"); NSLog(@"%@", number2); } When I run this code I see really strange results like this: 2011-07-06 20:38:18.044 helloworld[1014:207] THE FOLLOWING NUMBER 2011-07-06 20:38:18.047 helloworld[1014:207] 190.8776 2011-07-06 20:38:18.050 helloworld[1014:207] IS LESS THAN 2011-07-06 20:38:18.053 helloworld[1014:207] 96.75866 Both numbers are NSNumber objects, how could something like this happen? I am