nsdate

I have an API that returns data including a timestamp for that record. In swift I have the timestamp element loaded and converted into a double and can then convert that into time. I want to be able to return the time if the date of the record is today and return the date if the record is not today. See below: let unixTimeString:Double = Double(rowData["Timestamp"] as! String)! let date = NSDate(timeIntervalSince1970: unixTimeString) // This is on EST time and has not yet been localised. var dateFormatter = NSDateFormatter() dateFormatter.timeStyle = .ShortStyle dateFormatter

I know how to sort Core Data objects in a tableview by NsDate, but this by default seems to create a new section for each object. I want to sort them by a medium formatted date with NSDateFormatter. How would I do this? For example, if I have 3 objects created on the same day, I want them to be in the same section with the section title being that Day, no time needed. Each object has an NSDate property. Thanks for your help. This is the code I have in fetchedResultsController with rgeorge's suggestions. What am I missing here? - (NSFetchedResultsController *)fetchedResultsController { if

How to get name of days between two dates in ios? Example: Input: Start Date: 3-11-2012 End date: 5-11-2012 Output: 3-11-2012 Wednesday 4-11-2012 Thursday 5-11-2012 Friday Thanks.. try this, NSDateFormatter *df = [[NSDateFormatter alloc] init]; [df setDateFormat:@"yyyy-MM-dd"]; NSDate *startDate = [df dateFromString:@"2012-07-20"]; // your start date NSDate *endDate = [NSDate date]; // your end date NSDateComponents *dayDifference = [[NSDateComponents alloc] init]; NSMutableArray *dates = [[[NSMutableArray alloc] init] autorelease]; NSUInteger dayOffset = 1; NSDate *nextDate = startDate; do {

Is there a quick way in Objective-C of identifying NSDate's in an NSArray that have a time of day after a given time (e.g. 8pm)? I can't quite see anyway other than manually walking through each NSDate in the array and then using NSDateComponents to break out the hour/minute/second...Not even sure if there is a simple way to get the time from an NSDate in a fashion that represents a fraction of 24hours, as this might help a little. (e.g. 6pm would be 18/24 = 0.75 in this case) There is no need to break in NSDateComponents . NSTimeInterval interval = [date1 timeIntervalSinceDate:date2]; if

I have a NSMutableArray with dictionaries, all of the dict's contain a NSDate is form of NSString with key 'Date'. I want to sort the NSDictionaries by the Dates. So for example i have the following state of the array: Dict Date 20.06.1996 23:30 Dict Date 04.10.2011 19:00 Dict Date 20.06.1956 23:39 And I want to sort it, so that it looks like this: Dict Date 20.06.1956 23:39 Dict Date 20.06.1996 23:30 Dict Date 04.10.2011 19:00 I have already experimented with NSSortDescriptor, but without success... Update: I have managed to sort the dates, but I came to this problem: In the dicts there is

I have this string... 2010-08-24T16:00:00-05:00 and I'd like to extract the time portion from it (i.e. 16:00) and convert it to its 12-hour equivalent (i.e. 04:00 pm). I'm trying to use NSDateFormatter to accomplish this, but it's not working... NSDateFormatter* dateformatter = [[NSDateFormatter alloc] init]; [dateformatter setDateFormat:@"hh:mm a"]; NSDate *date1 = [dateformatter dateFromString:[listOfTimes objectAtIndex:0]]; [dateformatter release]; Can I use NSDateFormatter with this date format? If not, how can I extract the time and convert it to its 12-hour time equivalent? Thanks!