nosetests

When I type $ nosetests -v mytest.py all my print outputs are captured when all tests pass. I want to see print outputs even everything passes. So what I'm doing is to force an assertion error to see the output, like this. class MyTest(TestCase): def setUp(self): self.debug = False def test_0(self): a = .... # construct an instance of something # ... some tests statements print a.dump() if self.debug: eq_(0,1) It feels so hackish, there must be a better way. Enlighten me please. Either: $ nosetests --nocapture mytest.py Or: $ NOSE_NOCAPTURE=1 nosetests mytests.py (it can also be specified in

When using nosetests for Python it is possible to disable a unit test by setting the test function's __test__ attribute to false. I have implemented this using the following decorator: def unit_test_disabled(): def wrapper(func): func.__test__ = False return func return wrapper @unit_test_disabled def test_my_sample_test() #code here ... However, this has the side effect of calling wrapper as the unit test. Wrapper will always pass but it is included in nosetests output. Is there another way of structuring the decorator so that the test will not run and does not appear in nosetests output. I

I'm writing tests for a function like next one: def foo(): print 'hello world!' So when I want to test this function the code will be like this: import sys from foomodule import foo def test_foo(): foo() output = sys.stdout.getline().strip() # because stdout is an StringIO instance assert output == 'hello world!' But if I run nosetests with -s parameter the test crashes. How can I catch the output with unittest or nose module? Rob Kennedy I use this context manager to capture output. It ultimately uses the same technique as some of the other answers by temporarily replacing sys.stdout . I